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The Goldberg Volcano

The Goldberg Volcano. By Matt, Erik, Scott, and Tom. Track and Marble. 1 st step GIVEN Length of Top Track (1)=32.25”=2.688’ Length of Bottom Track (2)=33”=2.75’ Change in Height of 1 (A)=9.5”=.79’ Change in Height of 2 (B)=11.5”=.958’ Angle of Track 1 to ground (Theta 1) =17.13°

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The Goldberg Volcano

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  1. The Goldberg Volcano By Matt, Erik, Scott, and Tom

  2. Track and Marble • 1st step GIVEN • Length of Top Track (1)=32.25”=2.688’ • Length of Bottom Track (2)=33”=2.75’ • Change in Height of 1 (A)=9.5”=.79’ • Change in Height of 2 (B)=11.5”=.958’ • Angle of Track 1 to ground (Theta 1) =17.13° • Angle of Track 2 to ground (Theta 2)=20.39°

  3. Rube Goldberg

  4. Rube Goldberg

  5. Rube Goldberg • By using Conservation of Energy, We were able to determine the velocity before hitting the ending wall and dropping onto the next track. • V1= A*32.2 ft/s²=1/2 v² =7.14ft/s • After bouncing back up the track, this is the final velocity at the bottom of the second incline track • V2= .958*32.2=1/2 v² =7.85ft/s

  6. Coefficient of Restitution • Finding the speed of the marble bouncing back • 1=32.25”=2.688’ • 2=5.5”=.4583’ • V1=7.14ft/s • V2=?

  7. Rube Goldberg

  8. e=-(v1’/v1) -(-4.321/7.14)=e =.605 V2=-2.94 ft/s (As found by timing and measuring the distance the marble traveled.) Coefficient of Restitution

  9. Dropping Weight • h=8” • w=1.6 oz

  10. Weight Dropping

  11. Weight Dropping • mgh=(1/2)mv² • The masses cancel out • gh=(1/2)v² • 32.2(8”*1/12)=(1/2)v² v=6.55ft/s • KE=(1/2)(6.55ft/s)²*(1.6oz)(1lb/16oz)/32.2 =0.66ft-lb

  12. The Domino Effect

  13. Domino Effect

  14. Domino Effect • For the first “domino”- • an=(6.55 (velocity from PE)/(3.75in*ft/12in) an=137.3ft/s² • For second “domino”- • Rotates 9.5 times on impact • f=9.5 in 5 sec • f=w*(1/2π) • w=19π radians/5sec =3.8π • v=(3.75/12)(3.8π) v=3.73ft/sec (2)

  15. Domino Effect • e=vf/vi= 3.73/6.55 e=.57 3.73^2/(3.75/12) Theoretically, since all dominoes are the same, the e remains similar throughout the recation. • v=6.55ft/sec an=137.3ft/s² • v=3.13ft/sec an=44.52ft/s² • v=2.12 an=14.38 • v=1.21 an=9.69

  16. Swing

  17. Swing

  18. Swing • Height the weight is dropped from =10”=.833’ • w=1.32oz=.08125lbs • m=.0025 slugs • Change in height=5”=.417’ • PE=(.002523)(32.2)(.417) =.0338 J

  19. Hot Wheels Car

  20. Hot Wheels Car

  21. Hot Wheels Car • Mass of car=1.1oz=.069lb= .00214slugs • Height=10”=.833’ • Velocity at Bottom • (32.2)(.833)=(1/2)v² v=7.33ft/s • PE=(.00214)(.833)(32.2)=.05729J • KE=(1/2)(.00214)(7.33)²= .05749J • Impulse at bottom= .015686 slug-ft/sec²

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