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CH 14 #79-a

CH 14 #79-a. SAME FOR BOTH THEREFORE DROPS OUT. k=-Ea/RT + lnA. K c IS CATALIZED RATE CONSTANT , Ea c IS CATALZED ACTIVATION ENERGY. lnk c -lnk= -[Ea c /RT + lnA] - [-Ea/RT + lnA] ln( k c /k)= Ea - Ea c / R T ln(k c /k)= 95.5 kJmol - 55 kJ/mol /[( 8.314J/K*mol )(298K)(1 kJ/1000J)]

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CH 14 #79-a

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  1. CH 14 #79-a SAME FOR BOTH THEREFORE DROPS OUT. k=-Ea/RT + lnA Kc IS CATALIZED RATE CONSTANT, Eac ISCATALZED ACTIVATION ENERGY. lnkc-lnk= -[Eac/RT + lnA] - [-Ea/RT + lnA] ln(kc/k)= Ea-Eac/RT ln(kc/k)= 95.5 kJmol-55 kJ/mol/[(8.314J/K*mol)(298K)(1 kJ/1000J)] (kc/k)=1 x 107

  2. CH 14 #79-a A IS SAME FOR BOTH THEREFORE DROPS OUT. k=-Ea/RT + lnA Kc IS CATALIZED RATE CONSTANT, Eac ISCATALZED ACTIVATION ENERGY. lnkc-lnk= -[Eac/RT + lnA] - [-Eac/RT + lnA] ln(kc/k)= Ea-Eac/RT ln(kc/k)= 95.5 kJmol-55 kJ/mol/[(8.314J/K*mol)(398K)(1 kJ/1000J)] (kc/k)=2 x 105

  3. CH 14 #71- 2[NO2(g) + SO2 (g) NO(g) + SO3 (g)] 2 NO(g) + O2 (g) 2 NO2 (g) 2SO2 (g) + O2 (g) 2 SO3 (g) WHERE NO2 IS A CATALYST, IT IS IN THE GAS STATE AS ALL OTHER SPECIES, THEREFORE IT IS A HOMOGENOUS CATALYST.

  4. CH 14 #65 Rate = k[H2][ICl] SLOW H2(g) + ICl (g) HI (g) + HCl (g) HI(g) + ICl(g) I2 (g) + HCl (g) H2(g) + 2 ICl(g)  I2 (g) + 2HCl (g) RATE = k[H2][HCl] Rate = k[HI][HCl]

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