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Area and Perimeter. Review. Area Formula Review. Area – Parallelogram (rectangle, rhombus, and square). Area - Triangle. Area - Square. Formulas. Area of a circle. Circumference of a circle. Area - Trapezoid. Area of a Triangle. Area equals the base times the height divided by 2.
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Area and Perimeter Review
Area Formula Review Area – Parallelogram (rectangle, rhombus, and square) Area - Triangle Area - Square
Formulas Area of a circle Circumference of a circle Area - Trapezoid
Area of a Triangle • Area equals the base times the height divided by 2. • Find the area of triangle ABC B 8 in A C 6 in
Practice • Vicki wants to plant a flower garden with an area of 480 ft² with a height of 24ft. What will the base of that triangle be?
Vicki wants to plant a flower garden with an area of 480 ft² with a height of 24ft. What will the base of that triangle be? • Make an illustration • Write down the formula A = ½bh • Substitute what we know into the formula • 480ft² = ½ (b)(24ft) • Solve the equation algebraically B 24 ft A=480 ft² A C base
Vicki wants to plant a flower garden with an area of 480 ft² with a height of 24ft. What will the base of that triangle be? • 480ft² = ½ (b)(24ft) • Multiply what you can • 480ft² = (b)(12ft) • To isolate the variable perform the inverse operation Vicki’s triangular flower garden has a base 40 feet in length. B 24 ft A=480 ft² A C base
What is the area of parallelogram ABCD • A = bh • A = (12m)(9m) • A = 108m² B A 9m D 12m C
What is the height of parallelogram with a base of 18ft and an area of 216ft²
What is the height of parallelogram with a base of 18ft and an area of 216ft² • Draw the picture • A = bh • substitute what you know • 216ft² = (18ft)x • Solve for x B A A = 216ft² x D 18ft C
B A A = 216ft² x D 18ft C What is the height of parallelogram with a base of 18ft and an area of 216ft² • The height of the parallelogram is 12ft.
area of a trapezoid • use the formula 3 ft. B C 2.5 ft. A 4.5 ft. D
3 ft. B C 2.5 ft. • The area of this trapezoid is 9.375ft² A 4.5 ft. D
Using area of a trapezoid • What is the height? 8 in. B C A = 36 in² h A 10 in. D
8 in. B C A = 36 in² h A 10 in. D What is the height? • The height of this trapezoid is 4 in.
h = 18 in. 14 in. Isosceles Triangle • A triangle where two sides are equal • What is the area • What is the perimeter
h = 18 in. 14 in. Isosceles Triangle • What is the area
Isosceles Triangle • What is the perimeter • The height will cut the base exactly in half • Two identical right triangles • The height is a leg • Half the base is the second leg h = 18 in. 14 in.
h = 18 in. c c 18 in. 7 in. 7 in. Isosceles Triangle • What is the perimeter • Find the hypotenuse
Isosceles Triangle • What is the perimeter • Find the hypotenuse • a² + b² = c² h = 18 in. c c 18 in. 7 in. 7 in.
Isosceles Triangle • What is the perimeter • P = 19.31in. + 19.31in. + 14in. • P = 52.62in. 19.31in. 19.31in. h = 18 in. 18 in. 14 in.
4cm What is the area of a circle with a radius of 4cm?
6cm What is the circumference of a circle with a radius of 6cm?
13 ft. 8 ft. 38 ft. • Sam wants to paint his living room wall and does not know how much paint to purchase • Sam drew a diagram of the wall • Sam knows the paint he wants will cover 250 ft² • How much paint should Sam purchase?
area of an irregular polygon • Separate it into its parts • Find the area of each part • Take the sum of the parts 13 ft. 13 ft. 8 ft. 38 ft.
area of an irregular polygon • First lets look at the rectangle • A=(38ft.)(8ft.) • A=304ft² 13 ft. 8 ft. 38 ft.
area of an irregular polygon • Now lets look at the triangle • The base is 38ft • The height is 13ft – 8ft = 5ft 13 ft. 8 ft. 38 ft.
area of an irregular polygon 13 ft. 8 ft. 38 ft.
area of an irregular polygon • Find the sum of the two areas 13 ft. 8 ft. Total Area = 304ft² + 95ft² Total Area = 399ft² 38 ft.
area of an irregular polygon • The area Sam is painting is 399ft² • Divide the area by the number of square feet one gallon will cover. • Sam will need to purchase 2 gallons of paint Total Area = 399ft² 8 ft. 38 ft.
area of an irregular polygon • Separate it into its parts • Find the area of each part • Take the sum of the parts