1 / 35

ALGEBRA 1 EOC REVIEW 4 EXPONENTS, FOIL, FACTORING, SYSTEMS

ALGEBRA 1 EOC REVIEW 4 EXPONENTS, FOIL, FACTORING, SYSTEMS. SIMPLIFY:. 7 x 2 – 5 x – 3 + 2 x. 1). A) 7 x 2 + 3 x – 3. B) x 4. C) – 3. D) 7 x 2 – 3 x – 3. SIMPLIFY:. (- 3 c 3 d 4 )(5 c 5 d 2 ). 2). A) - 15 c 15 d 8. B) - 15 c 8 d. C) - 15 c 8 d 6. D) - 8 c 8 d 8.

ivory-wilkinson
Download Presentation

ALGEBRA 1 EOC REVIEW 4 EXPONENTS, FOIL, FACTORING, SYSTEMS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. ALGEBRA 1 EOC REVIEW 4 EXPONENTS, FOIL, FACTORING, SYSTEMS

  2. SIMPLIFY: 7 x2 – 5 x – 3 + 2 x 1) A) 7 x2 + 3 x – 3 B) x4 C) – 3 D) 7 x2 – 3 x – 3

  3. SIMPLIFY: (- 3 c3 d4)(5 c5 d2) 2) A) - 15 c15 d8 B) - 15 c8 d C) - 15 c8 d6 D) - 8 c8 d8

  4. SIMPLIFY: 3) B) A) - 15 x2 y3 z3 D) C)

  5. SIMPLIFY: (6 b2 c3)2 4) A) 12 b4 c6 B) 36 b4 c6 C) 12 b4 c5 D) 36 b4 c5

  6. SIMPLIFY: 5) B) A) D) C)

  7. SIMPLIFY: 6) B) A) D) C)

  8. SIMPLIFY: 7) B) A) D) C)

  9. 8) Find the perimeter of a triangle whose sides are (3 x2 + 5); (5 x – 2); and (6 x2 + 5 x). A) 9 x2 + 10 x + 3 B) 19 x2 + 3 C) 9 x4 + 10 x2 – 3 D) 7 x4 + 10 x – 3

  10. 9) Simplify: (2 x + 5) (2 x – 3) A) 4 x2 – 15 B) 4 x2 – 4 x – 15 C) 4 x2 + 4 x – 15 D) 8 x – 15

  11. 10) Simplify: (3 x2 + 5 x + 1) – (7 x2 – 2) A) - 4 x2 + 5 x + 3 B) - 4 x2 + 5 x – 1 C) x2 – 1 D) x2 + 3

  12. 11) Simplify: (x – 2) (3 x2 – x + 4) A) 3 x3 – 7 x2 + 6 x – 8 B) 3 x3 – 6 x2 + 6 x + 4 C) 3 x3 + 7 x2 – 6 x – 8 D) 2 x3 – 8

  13. 12) Find the perimeter of a rectangle if the width is (2 x – 4) and the length is (5 x + 1). A) 7 x – 3 B) 7 x + 3 C) 14 x – 6 D) 14 x + 6

  14. 13) Find the area of a triangle if the base is (2 x – 4) and the height is (x + 6). A) x2 + 4 x – 12 B) 2 x2 + 8 x – 24 C) 2 x2 – 8 x – 24 D) 3 x + 2

  15. SIMPLIFY: 14) A) 2 x y – 3 + 4 x B) 2 y – 3 + 4 x C) 2 y – 3 + 4 y D) 2 x y – 3 + 4 x2

  16. SIMPLIFY: 15) A) B) C) D)

  17. SIMPLIFY: 16) A) B) C) D)

  18. 17) The area of a rectangle is given by the expression: x2 – 5 x – 6. The length and width have only integral coefficients. Which of the following could represent the length of the rectangle? A) x – 6 B) x – 2 D) x – 1 C) x – 3

  19. Given: 2 x – 3 y = 12 6 x + 2 y = 42 18) What is x + y? 2(2 x – 3 y = 12) 4 x – 6 y = 24 3(6 x + 2 y = 42) 18 x + 6 y = 126 22 x = 150 x = 150/22 = 75/11 2(75/11) – 3 y = 12 x + y = 75/11 + 6/11 y = 6/11 150/11 – 3 y = 12 – 3 y = - 18/11 x + y = 81/11 = 7.4

  20. 19) A restaurant received 270 hamburger patties and 350 hotdogs on Monday for $ 450. On Friday the restaurant received 550 hamburger patties and 425 hotdogs for $ 630. a) How much did each hamburger cost? x = cost of a hamburger cost of a hamburger = $ .38 y = cost of a hotdog cost of a hotdog = $ .995 270 x + 350 y = 450 550 x + 425 y = 630 b) How much will 25 hamburgers and 50 hotdogs be? 25($.38) + 50($.995) = $ 59.25

  21. 20) A local pet store has triple the amount of fish as birds and has a total of 250 fish and birds. Write a system of equations represents the number of fish and birds using the variables F and B. F = number of fish B = number of birds F = 3(62.5) = 187.5 F = 3 B F + B = 250 No solution since you cannot have a fraction of a bird or of a fish. 3 B + B = 250 4 B = 250 B = 62.5

  22. Given: 4 x + 3 y = 60 x – y = 10 21) x = y + 10 What is the value of x ? 4(y + 10) + 3 y = 60 4 y + 40 + 3 y = 60 7 y + 40 = 60 7 y = 20 y = 20/7 = 2 6/7 = 2.86 x = 2 6/7 + 10 = 12 6/7 = 12.86

  23. Given: 2 x + y = 15 5 x – 6 y = - 22 22) y = - 2 x + 15 What is the value of x – y ? 5 x – 6(- 2 x + 15) = - 22 5 x + 12 x – 90 = - 22 17 x – 90 = - 22 y = - 2(4) + 15 y = 7 17 x = 68 y = - 8 + 15 x = 4 x – y = 4 – 7 = - 3 A) 11 B) 2 D) - 3 C) 3

  24. Given: w = 1 – v 2 v + w = 4 23) What is the value of w ? 2 v + 1 – v = 4 w = 1 – v = 1 – 3 = - 2 v + 1 = 4 v = 3 A) 3 B) 2 D) - 2 C) 1

  25. A limosine company charges a flat-fee of $ 80 plus $.05 per mile. A shuttle van company charges a flat-fee of $ 60 plus $.50 per mile. Approximately what mileage will yield the same fare for both? 24) limo: y = .05 x + 80 shuttle: y = .5 x + 60 .05 x + 80 = .5 x + 60 2000 = 45 x 5 x + 8000 = 50 x + 6000 44.4 = x A) 24 miles B) 34 miles D) 54 miles C) 44 miles

  26. The price of six sodas and four candy bars is $ 18.50. The price of two candy bars and eight sodas is $ 20.50. What is the price of a candy bar? 25) x = number of sodas y = number of candy bars 6 x + 4 y = 18.50 x = $ 2.25 y = $ 1.25 8 x + 2 y = 20.50 A) $ 1.25 B) $ 2.25 D) $ 2.15 C) $ 1.65

  27. The area of a rectangle is given by the expression: x2 – 5 x – 6. The length and width only have integral coefficients. Which of the following could represent the length of the rectangle? 26) (x – 6)(x + 1) A) x – 6 B) x – 3 D) x – 1 C) x – 2

  28. 27) Factor: x2 + 9 x + 18 (x + 6) (x + 3) 28) Factor: x2 – 13 x y – 30 y2 (x – 3 y)(x – 10 y)

  29. 29) Factor: w2 + 2 w – 15 (w + 5) (w – 3) 30) Factor: x3 + 5 x2 + 6 x x(x2 + 5 x + 6) x(x + 2)(x + 3)

  30. A restaurant makes at least 50 pizzas a night, but no more than 250 pizzas. The restaurant makes at least 20 salads but no more than 90 salads. A total of no less than 325 pizzas and salads are made each night. Each pizza makes a profit of $ 3.00. Each salad makes a profit of $ 2.25. What is the maximum profit the restaurant can make in a night? 31) Constraints: P(x, y) = 3 p + 2.25 s 50 ≤ p ≤ 250 20 ≤ s ≤ 90 p + s ≥ 325 A) $ 998.25 B) $ 881.25 D) $ 952.50 C) $ 907.50

  31. 31) x + y ≥ 325 P3(250, 90) Corner points: P1(235, 90) y ≤ 90 P2(250, 75) x > 50 y ≥ 50 x ≤ 250 P(235, 90) = 3(235) + 2.25(90) = $ 672.50 P(250, 75) = 3(250) + 2.25(75) = $ 918.75 HIGHEST PROFIT P(250, 90) = 3(250) + 2.25(90) = $ 952.50

  32. SIMPLIFY: 32) A) B) C) D)

  33. SIMPLIFY: 33)

  34. 34) Solve the following system of inequalities: 2 x + y < 3 x – 2 y ≤ 8 y < - 2 x + 3 y ≥ ½ x – 4 y = - 2 x + 3 y = ½ x – 4

  35. 34) Solve the following system of inequalities: 3 y ≥ 6 x – 9 3 x + 4 y < 12 y ≥ 2 x – 3 y < - ¾ x + 3 y = - ¾ x + 3 y = 2 x – 3

More Related