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Lab #2 Report due TODAY. Individual Data Processing and Individual Write Up Lab #2 Report is due TODAY by midnight Answer Multiple Choice Questions ONLINE TODAY by midnight Answer Student Survey ONLINE TODAY by midnight
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Lab #2 Report due TODAY • Individual Data Processing and Individual Write Up • Lab #2 Report is due TODAY by midnight • Answer Multiple Choice Questions ONLINE TODAY by midnight • Answer Student Survey ONLINE TODAY by midnight • Submit the Lab Report #2 in the drawer labeled “MECE204-Strength Lab” under M. E. Mail Folders
Torsion Testing • Circular Cross-section Only • Determine Material Properties in Torsion • Draw Shear Stress-Strain Curve • Ductile or Brittle Failure ? • ASTM E-143 Test Method • Compare results from Tensile, Poisson’s & Torsion Test • Become familiar with Tinius Olsen Torsion Tester (10,000 in-lb capacity)
Assumptions Perfectly linear-elastic behavior Circular x-section (solid or hollow) Small rotations Constant length Constant diameter
No deformation A highly deformable member A circular x-section A grid of parallel circles and longitudinal lines on the outer surface
After Deformation Two torques are applied Circles remain circles Longitudinal lines become twisted All angles are equal End x-section remains flat
Angle of Twist A prismatic circular member Fixed at x = 0 Other end is FREE Loaded by a torque at the free end Angle (x) - angle of twist It depends on x: /x=constant
Shear Strain After Before
Shear Strain Distribution max = c max - occurs on the outer surface = (/c) max Result valid also for circular tubes within the material Valid for plastic deformation also 9
Shear Strain & Angle of Twist = * / L max = * D / 2 / L
Shear Stress Distribution - Elastic Deformation only • X-section: linear distribution • Complimentary stresses in action • Shear stress occur on axial planes (normal to the x-section 12
Shear Stress & Torque- Linear Elastic Deformation Only = T * / J max = T * D / 2 / J
Modulus of Rupture tmax,psi gmax, rad Shear Stress-Strain Curve Slope = Dt/Dg = Shear Modulus, G Figure 3.2 Typical shear stress-strain diagram from a Torsion Test
n t N V P Stresses on an Inclined Plane in an Axially Loaded Member • Seek for equilibrium after cutting along the oblique plane x
Measuring Angle of Twist T=(R-R0)-(L-L0)
Manually Recorded Data slip= H-(LH/LT)T T=(R-R0)-(L-L0) cor = H - slip R0 L0
Shear Strain and Stress =Radians(cor)*D/2/LH =16T//D3
Integrating Computer Data slip= constant cor=H - slip
Selecting Computer Data Head Angle = 30.00 deg When Protractors taken OFF Max Torque = 1931 in-lb
Proportional Limit =G*
Proportional Limit Plot columns H, I, & J
Key Ideas - Torsion • Shear strain formula is valid in both elastic & plastic region • Torque formula is valid in linear elastic region ONLY • Thus, shear stress formula is valid until proportional limit • After proportional limit, shear stress formula overestimates stress.
Lab #2 Report due TODAY • Individual Data Processing and Individual Write Up • Lab #2 Report is due TODAY by midnight • Answer Multiple Choice Questions ONLINE TODAY by midnight • Answer Student Survey ONLINE TODAY by midnight • Submit the Lab Report #2 in the drawer labeled “MECE204-Strength Lab” under M. E. Mail Folders