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Leave space between each step to add more information.

Directions for solving titration problems. Leave space between each step to add more information. Write a balance chemical equation between the acid and the base. Remember it’s a double replacement reaction with water and a salt forming.

jeremy-fitzgerald
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  1. Directions for solving titration problems • Leave space between each step to add more information. • Write a balance chemical equation between the acid and the base. Remember it’s a double replacement reaction with water and a salt forming. • 2. Convert the molarity (M) to moles using the volume. You will need to change the volume to Liters (divide by 1000)

  2. Directions for solving titration problems 3. Convert the moles of acid to moles of base (base to acid) using molar ratios from the balanced chemical equation. 4. To get concentration (molarity), divide the moles by the volume.

  3. Chapter 15 - Section 3 Neutralization and Titrations Objectives • Predict the product of an acid-base reaction. • Calculate the molarity of an unknown acid or base.

  4. Chapter 15 - Section 3 Neutralization and Titrations Standards • IE 1e Solve scientific problems by using quadratic equations and simple trigonometric, exponential and logarithmic function

  5. Chapter 15 - Section 3 Neutralization and Titrations Neutralization - All Neutralizations Are the Same Reaction • Aneutralization reactionis the reaction between an acid and base to form water molecules and a salt. • When solutions of a strong acid and a strong base, having exactly equal amounts of H3O+(aq) and OH−(aq) ions, are mixed, the hydronium and hydroxide ions react to form water. • H3O+(aq) + OH−(aq)  2H2O(l)

  6. Chapter 15 - Section 3 Neutralization and Titrations Neutralization - All Neutralizations Are the Same Reaction • Supposethat hydrochloric acid, HCl, and the base was sodium hydroxide, NaOH are mixed. • The result will be a solution of water and a salt • HCl + NaOHHOH + NaCl

  7. 2 2 If 20.0 mL of 0.015 M aqueous hydrochloric acid is required to neutralize 30.0 mL of an aqueous solution of calcium hydroxide, what is the concentration of the calcium hydroxide solution? 1. Write a balance chemical equation between the acid and the base. Remember it’s a double replacement reaction with water and a salt forming. HCl + Ca(OH)2 CaCl2 + HOH

  8. If 20.0 mL of 0.015 M aqueous hydrochloric acid is required to neutralize 30.0 mL of an aqueous solution of calcium hydroxide, what is the concentration of the calcium hydroxide solution? 2. Convert the molarity (M) to moles using the volume. You will need to change the volume to Liters (divide by 1000)

  9. HCl + Ca(OH)2 CaCl2 + HOH 2 2 If 20.0 mL of 0.015 M aqueous hydrochloric acid is required to neutralize 30.0 mL of an aqueous solution of calcium hydroxide, what is the concentration of the calcium hydroxide solution? 3. Convert the moles of acid to moles of base (base to acid) using molar ratios from the balanced chemical equation.

  10. If 20.0 mL of 0.015 M aqueous hydrochloric acid is required to neutralize 30.0 mL of an aqueous solution of calcium hydroxide, what is the concentration of the calcium hydroxide solution? 4. To get concentration (molarity), divide the moles by the volume. 2 Sig figs

  11. Now you try! A 25.0 mL solution of H2SO4 is completely neutralized by 18.0 mL of 1.5 M NaOH using phenolphthalein as an indicator. What is the concentration of the H2SO4 solution?

  12. 2 2 A 25.0 mL solution of H2SO4 is completely neutralized by 18.0 mL of 1.5 M NaOH using phenolphthalein as an indicator. What is the concentration of the H2SO4 solution? H2SO4 + NaOH  Na2 SO4 + HOH

  13. 2 H2SO4 + NaOH  Na2 SO4 + HOH 2 A 25.0 mL solution of H2SO4 is completely neutralized by 18.0 mL of 1.5 M NaOH using phenolphthalein as an indicator. What is the concentration of the H2SO4 solution?

  14. 2 H2SO4 + NaOH  Na2 SO4 + HOH 2 A 25.0 mL solution of H2SO4 is completely neutralized by 18.0 mL of 1.5 M NaOH using phenolphthalein as an indicator. What is the concentration of the H2SO4 solution? 2 Sig figs

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