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18. 15. 12. Weight (lbs.). 9. 6. 3. 2. 4. 6. 8. 10. Age (months). This is a LINE GRAPH . It’s easy to see the baby’s weight changing as the months go by. Since Jill charges $25 per lawn each time, the “ 25 ” will not have a variable next to it.
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18 15 12 Weight (lbs.) 9 6 3 2 4 6 8 10 Age (months) This is a LINE GRAPH. It’s easy to see the baby’s weight changing as the months go by.
Since Jill charges $25 per lawn each time,the “25” will not have a variable next to it. $18 for each hour means that the “18” should be multiplied by the “h”. Then, we simply add the 18h and the 25 together to get the total charge.
Since all right angles must be 90o,the yellow angle is also 45o.
Even though Leroy has rolled a “5” four times in a row, that won’t affect the probability of his next toss. The cube has 6 sides. Each side is equally likely to land facing up. The probability of any number being rolled is 1/6.
4” 2” 10” 5” cola juice Each can is a cylinder. Volume = p *r2* h Volume = p *(1)2* 5 Volume = 5p in3 The volume of the juice can is 8 times greater than the volume of the cola can. Volume = p *(2)2* 10 Volume = 40p in3
When writing a number in scientific notation, you slip the decimal point in so that you’ve got a number between 1 and 10. Next, you see how far the decimal point needs to be moved in order to get it back to where it’s supposed to be. (Since we’re moving it to the LEFT, the exponent will be NEGATIVE.)
When the shape is folded, these two segments will be joined together. Therefore, the circles and squares will need to be next to each other.
35boxes 35boxes 35boxes 500 boxes total Each day, he loses 35 boxes.
The area of this triangle = ½(3)(2) = 3 cm2 Since there are four identical triangles, their combined area is 12 cm2. The red rectangle is 6 cm x 3 cm, so its area is 18 cm2. The total area of the hexagon is 12 cm2 + 18 cm2 = 30 cm2.
Since Pedro actually made more money, the group’s mean will increase. The nice thing about this problem is that you don’t have to add all the numbers together to solve it. Once the mistake was fixed, Pedro had earned an extra $16. Since there are 8 people in the group, that means we could simply take 16 8 to find how much the group’s mean increases by.
ShadedSquares Figure 1 1 2 3 3 5 4 7 5 9 If we multiply each number in the firstcolumn by 2, we’re always slightly too large. Subtracting 1 fixes this problem each time.Therefore, our formula for figure “n” is2n-1 shaded squares. 6 11 Notice how the numbers on the left sideof the table go up by one, while the numberson the right side go up by two each time. This tells us that the formula for findingthe number of shaded squares must involvemultiplication by 2. 7 13 n 2n-1
ShadedSquares Figure 1 1 2 3 3 5 4 7 5 9 6 11 7 13 n 2n-1 = 2(50) - 1 50 99 =99 shaded squares
Let’s convert them all to decimals… 7.75 7.625 7.071 7.82 Now, arrange them from least to greatest… 7.071 7.625 7.75 7.82
First, convert 18oC to Fahrenheit. F = (9/5)(18) + 32 F = 32.4 + 32 F = 64.4o The difference between high and low temperatures can be found by subtracting. Next, convert 7oC to Fahrenheit. F = (9/5)(7) + 32 64.4o - 44.6o F = 12.6 + 32 19.8o F F = 44.6o
If we continue this pattern, here’s what the table would look like… Add 2 Add 3 Add 4 Add 5 6 21 7 28 8 36 9 45 10 55
The number of cans can be found by using the formula (L)(L+1) 2 (4)(5) (10)(11) (7)(8) (4)(4+1) (7)(7+1) (10)(10+1) = = = 2 2 2 2 2 2 Other students may prefer to work with formulas. For example… 6 21 7 28 8 36 = 10 9 45 10 55 = 28 = 55
The residents’ concern is about the traffic volume during the 4-6 PM rush hour period only. It’s very possible that this intersection may not be used much at all during the rest of the day, so including non-rush hour data will make the intersection seem less busy. The department could get more accurate data if they would only monitor the intersection between 4-6 PM instead of taking an overall daily average.
The slope of RW is ¼. Parallel lines have the same slope. Going up 1 block and over 4 blocks from point Q puts us at (-1,-3). (As you can see, we’ve formed a parallelogram.)
h 0.4 meters 1.5 meters height = 1.25 meters 0.6 0.6 Volume = (length)(width)(height) 0.75 = (1.5)(0.4)(height) 0.75 = (0.6)(height)
The best way is to try each formula to see whether or not it works. As luck would have it, choice A works all four times, so it’s the right answer. 1.15(3) = 3.45 1.15(5) = 5.75 1.15(8) = 9.20 1.15(12) = 13.80 If choice A would have failed, we would have gone to choice B, then choice C, etc. The correct answer must work all 4 times.
meters meters kg kg = First, make a proportion.Include units before you start. x 50 502.5 7.5 Next, cross-multiply and solve using Algebra. (7.5)(x)= (50)(502.5) 7.5x = 25125 x = 3350
-5.80x -5.80x 7.80x > 120 7.80 7.80 x 15.3846 > Revenue Cost 5.80x + 120 13.60x > Frank must sell at least 16 frames in order for his revenue to be greater than his costs.
6 2 9 6 = n 8 Dropping down an altitudeforms a 30o/60o/90o triangle. n = 12 6n = 72
2 + 2(3) 2(2) + 3 (2)2 + (3)2 (2+3)2 8 7 13 25 Often times, the best way to solve a problem like this is to pick an even number and an odd number and simply try them out. Let’s make x = 2 and y = 3.
3500 customers 7 days We’ll round the values offas we go… Sun = 800 Mon = 350 Tue = 400 Wed = 350 Thur = 300 Fri = 400 Sat = 900 TOTAL = 3500 = 500 each day
This is a volume problem. V = (length)(width)(height) V = (22)(9)(8) V = 1584 in3 BE CAREFUL!This is not our final answer… …and it happens to be a choice.DON’T BE FOOLED! We need to take ¾ of 1584. 1188 in3
When an object travels at a constant rate, the graph will always be a straight line.
New Salaries $500 raise 2% raise The 34 employees with the lower salaries would be better off with the $500 raise. The 30 employees with the higher salaries would be better off with the 2% raise. Let’s compare both situations and see what the new salaries would be: If these employees voted, the $500 raise would be the likely winner. $19,000 $18,870 $20,706 $20,800 $24,600 $24,582 $31,500 $31,620 $42,500 $42,840 $58,500 $59,160 $71,500 $72,420 To figure the 2% raise, multiply the current salary by 1.02 $18,500 * 1.02 = $18,870 $20,706 $20,300 * 1.02 = and so on…
15 We’ll draw a “line of best fit” through the data points. Since the line has a positive slope, it’s obvious that the population is not going to decline or stay the same. It’s unlikely that it will get above 120,000 in the next 10 years when it’s not even above 50,000 during the first 10 years. If we extend the line out, you can see from the graph that this is the obvious choice.
Since it’s a trig problem, we’ll be using SOH CAH TOA opposite 4 tangent = = adjacent x Starting from the shaded angle, label the 3 sides of the triangle: HYP OPP ADJ The sides we’re dealing with are the OPPOSITE and the ADJACENT, so we’ll be using the TANGENT.
687.5 n = 3 n = 229.16666
Total = 94,000 Here are my estimates: Superior = 31,000 Michigan = 22,000 Huron = 23,000 Erie = 10,000 Ontario = 8,000
These 2 triangles are similar.The orange triangle has sides which are twice as long as the yellow triangle. Using this scale factor, the bottom side of the yellow one is 14. 14 12 28 24 28 If R and T are both midpoints, then SR = 14 and ST = 12. 14 12 14 14 + 14 + 12= 40
The final coordinates of the kite will beP”(1,3), Q”(2,4), R”(1,7), and S”(0,4).
Some students may choose not to use a graph. Here’s what they’d need to do: P(-2,-1) Q(-1,-2) R(-2,-5) S(-3,-2). Reflecting the graph over the x-axis simply changes the signs on the y-coordinates. P’(-2,1) Q’(-1,2) R’(-2,5) S’(-3,2). Translating the graph 3 units right and 2 units up requires us to add 3 to each x-coordinate and 2 to each y-coordinate. P”(1,3) Q”(2,4) R”(1,7) S”(0,4). The final coordinates of the kite will beP”(1,3), Q”(2,4), R”(1,7), and S”(0,4).
w2 n2 - q (-6)2 (1/3)2 - 2/3 36 1/9 - 2/3 8 = -53 9 Do the exponents first. Dividing by 2/3is the same as multiplying by 3/2. 1/9 - 54
Hispanic males Probability = Total males 76,660 Probability = 5,215,573 Probability = 0.0146982891
day #1 60 MPH 9 hours x 540 milestraveled 704 miles day #2 11 hours 1244 miles total - 540 miles on day #1 704 miles to go = 64 MPH average
This presentation brought to you by Mr. Jeff LuceBBHHS Mathematics Dept.