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Join us on a field trip to St. Edwards University to enhance your knowledge on heat exchangers through practical examples and key parameters such as NTU and effectiveness. Discover the importance of extended surfaces and how to calculate efficiency. Reading assignment includes in-depth studies on coil analysis and energy balances.
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Filed Trip is Tomorrow at 9 am https://www.google.com/maps/place/Saint+Edwards+University/@30.2273026,-97.7529731,1095m/data=!3m1!1e3!4m2!3m1!1s0x8644b492ae61201b:0x1142c282cbe51336
Objectives • Continue with heat exchangers (ch.11)
Coil Extended Surfaces Compact Heat Exchangers • Fins added to refrigerant tubes • Important parameters for heat exchange?
Overall Heat Transfer Q = U0A0Δtm Overall Heat Transfer Coefficient Mean temperature difference
Heat Exchangers • Parallel flow • Counterflow • Crossflow Ref: Incropera & Dewitt (2002)
Heat Exchanger Analysis - Δtm Counterflow For parallel flow is the same or
Counterflow Heat Exchangers Important parameters: Q = U0A0Δtm
What about crossflow heat exchangers? Δtm= F·Δtm,cf Correction factor Δt for counterflow Derivation of F is in the text book: ………
Overall Heat Transfer Q = U0A0Δtm Need to find this AP,o AF
Heat Transfer • From hot fluid to pipe • Through the wall • From the pipe and fins
Resistance model Q = U0A0Δtm From eq. 1, 2, and 3: • We can often neglect conduction through pipe walls • Sometime more important to add fouling coefficients R Internal R cond-Pipe R External
Example The air to air heat exchanger in the heat recovery system from previous example has flow rate of fresh air of 200 cfm. With given: Calculate the needed area of heat exchanger A0=? Solution: Q = mcp,coldΔtcold = mcp,hotΔthot = U0A0Δtm From heat exchanger side: Q = U0A0Δtm→ A0 = Q/ U0Δtm U0 = 1/(RInternal+RCond+RFin+RExternal) = (1/10+0.002+0+1/10) = 4.95 Btu/hsfF Δtm = 16.5 F From air side: Q = mcp,coldΔtcold = = 200cfm·60min/h·0.075lb/cf·0.24Btu/lbF·16 = 3456 Btu/h Then: A0 = 3456 / (4.95·16.5) = 42 sf
For Air-Liquid Heat Exchanger we need Fin Efficiency • Assume entire fin is at fin base temperature • Maximum possible heat transfer • Perfect fin • Efficiency is ratio of actual heat transfer to perfect case • Non-dimensional parameter tF,m
Fin Theory k – conductivity of material hc,o – convection coefficient pL=L(hc,o /ky)0.5
Fin Efficiency • Assume entire fin is at fin base temperature • Maximum possible heat transfer • Perfect fin • Efficiency is ratio of actual heat transfer to perfect case • Non-dimensional parameter
Heat exchanger performance (Book Section 11.3) • NTU – absolute sizing (# of transfer units) • ε – relative sizing (effectiveness)
Summary • Calculate efficiency of extended surface • Add thermal resistances in series • If you know temperatures • Calculate R and P to get F, ε, NTU • Might be iterative • If you know ε, NTU • Calculate R,P and get F, temps
Reading Assignment • Chapter 11 - From 11.1-11.7
Analysis of Moist Coils • Redo fin theory • Energy balance on fin surface, water film, air Introduce Lewis Number • Digression – approximate enthalpy • Redo fin analysis for cooling/ dehumidification (t → h)
Energy and mass balances • Steady-state energy equation on air • Energy balance on water • Mass balance on water