130 likes | 143 Views
Explore the rights and privileges of first-class citizens in Scheme through higher-order procedures and learn patterns like transforming, filtering, and accumulating results in lists. Dive into unique element selection using functional programming techniques.
E N D
6.001 SICP – October 1 6001-HOPs, Lists, Trees Trevor Darrell trevor@csail.mit.edu 32-D512 Office Hour: W 11 6.001 web page: http://sicp.csail.mit.edu/ section web page: http://www.csail.mit.edu/~trevor/6001/ • More Higher-order procedures • HOPs and Lists 6.001 SICP
Summary of higher order procedures Rights and privileges of first class citizens • May be named by variables • May be passed as arguments to procedures • May be returned as results of procedures • May be included as parts of data structures Procedures in Scheme are + first class citizens! 6.001 SICP
Repeated power rather than: (define fourth-power (composef square square)) (define eight-power (composef square (composef square square))) let’s use… (define fourth-power (repeated square 2)) (define eight-power (repeated square 3)) (define composef (lambda (f g) (lambda (x) (f (g x)))) ) 6.001 SICP
Recusive repeated (define fourth-power (repeated square 2)) (define (repeated proc n) (if (= n 0) (lambda (x) x) (composef proc (repeated proc (- n 1))))) (define fourth-power (repeated square 2)) (repeated square 2) (composef square (repeated square 1)) (composef square (composef square (repeated square 0))) (composef square (composef square (lambda (x) x))) ... 6.001 SICP
Iterative repeated (define (repeated proc n) (define (iter n ans) (if (= n 0) ans (iter (- n 1) (composef f ans)))) (iter n (lambda (x) x))) 6.001 SICP
List HOP Common Pattern #1: Transforming a List (define (square-list lst) (if (null? lst) nil (adjoin (square (first lst)) (square-list (rest lst))))) (define (double-list lst) (if (null? lst) nil (adjoin (* 2 (first lst)) (double-list (rest lst))))) (define (square-list lst) (map square lst)) (define (double-list lst) (map (lambda (x) (* 2 x)) lst)) (define (MAP proc lst) (if (null? lst) nil (adjoin (proc (first lst)) (map proc (rest lst))))) 6.001 SICP
List HOP Common Pattern #2: Filtering a List (filter even? (list 1 2 3 4 5 6)) ;Value: (2 4 6) (define (filter pred lst) (cond ((null? lst) nil) ((pred (first lst)) (adjoin (first lst) (filter pred (rest lst)))) (else (filter pred (rest lst))))) 6.001 SICP
List HOP Common Pattern #3: Accumulating Results (define (add-up lst) (if (null? lst) 0 (+ (first lst) (add-up (rest lst))))) (define (mult-all lst) (if (null? lst) 1 (* (first lst) (mult-all (rest lst))))) (define (add-up lst) (fold-right + 0 lst)) (define (FOLD-RIGHT op init lst) (if (null? lst) init (op (first lst) (fold-right op init (rest lst))))) 6.001 SICP
Lists and higher-order procedures x => (()) y => (1 2 3) z => (1 (2 3) ((4))) w => (1 2 3 4 5) (map (lambda (x) (cons x nil)) y) ((1) (2) (3)) (map inc w) (2 3 4 5 6) (filter odd? w) (1 3 5) (map inc (filter odd? w)) (2 4 6) (filter odd? (map inc w)) (3 5) (fold-right + 0 (map inc (filter odd? w))) 12 6.001 SICP
For lists, car has type List<A>->A, cdr has type List<A>->List<A> , and assume nil is an element of type List<A>… What are the types of these procedures? 1.length List<A>->number 2.list-ref List<A>,number->A 3.map (A->B),List<A>->List<B> 4.filter (A->boolean),List<A>->List<A> 5.fold-right (A,B->B),B,List<A>->B 6.001 SICP
Uniqueness Given (define x (list 1 2 2 3 1 5 4 3 4)) To select the unique elements from this list, (unique x) (1 2 3 5 4) Start with function remove (e.g. (remove 3 (list 3 4 5)) (4 5) (define (remove el lst) (filter (lambda (x) (not (= x el))) lst) 6.001 SICP
Uniqueness (define (unique lst) (if (null? lst) nil (cons (car seq) (unique (remove (car lst) (cdr lst)))) 6.001 SICP
Remember… • calendar… 6.001 SICP