1 / 21

Warm Up

Warm Up. Problem of the Day. Lesson Presentation. Lesson Quizzes. 3. 8+ 144 4. 7 289. Warm Up Find the two square roots of each number. Evaluate each expression. 1. 144 2. 256.  12.  16. 20. 119. Problem of the Day

karyn-sheppard
Download Presentation

Warm Up

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Warm Up Problem of the Day Lesson Presentation Lesson Quizzes

  2. 3. 8+ 144 4. 7 289 Warm Up Find the two square roots of each number. Evaluate each expression. 1. 144 2. 256 12 16 20 119

  3. Problem of the Day A pyramid of blocks is built in layers. The bottom layer has 62, or 36, blocks. The next layer has 52 blocks, and so on until the top layer has 1 block. How many blocks are there in all? 91 blocks

  4. Sunshine State Standards MA.8.A.6.2 Make reaonable approximations of square roots…,and use them to estimate solutions to problems…

  5. 55 is between 7 and 8 because 55 is between 49 and 64. Additional Example 1A: Estimating Square Roots of Numbers The square root is between two integers. Name the integers. Explain your answer. Think: What are perfect squares close to 55? 55 49 < 55 72 = 49 64 > 55 82 = 64

  6. – is between –9 and –10 because 90 is between 81 and 100. 90 Additional Example 1B: Estimating Square Roots of Numbers Continued The square root is between two integers. Name the integers. Explain your answer. Think: What are perfect squares close to 90? – 90 81 < 90 –92 = 81 100 > 90 –102 = 100

  7. Check It Out: Example 1A Each square root is between two consecutive integers. Name the integers. Explain your answer. 80 80 82 = 64 and 92 = 81; 80 is between 64 and 81, so 80 is between 8 and 9.

  8. Check It Out: Example 1B Each square root is between two consecutive integers. Name the integers. Explain your answer. 105 105 102 = 100 and 112 = 121; 105 is between 100 and 121, so 105 is between 10 and 11.

  9. The length of each side of the square is √500 . Additional Example 2: Application You want to sew a fringe on a square tablecloth with an area of 500 square inches. Calculate the length of each side of the tablecloth and the length of fringe you will need to the nearest inch. 484 < 500 < 529 List the perfect squares nearest 500. Find the square roots of the perfect squares. The number will be between 22 and 23. The length of each side of the table is about 22 in., and you will need about 88 in. of fringe.

  10. 152 = 225 and 162 = 256; √250 is much closer to 16. Check It Out: Example 2 You want to build a fence around a square garden that is 250 square feet. Calculate the length of one side of the garden and the total length of the fence, to the nearest tenth. 15.82 ≈ 249.64 so ≈ 15.8; side length:15.8 ft; total length: 63.2 ft √250

  11. Additional Example 3: Approximating Square Roots to the Nearest Hundredth Approximate to the nearest hundredth. Step 1: Find the value of the whole number. Find the perfect squares nearest 141. 121 < 141 < 144 Find the square roots of the perfect squares. The number will be between 11 and 12. The whole number part of the answer is 11.

  12. Additional Example 3 Continued Approximate to the nearest hundredth. Step 2: Find the value of the decimal. Find the difference between the given number, 141, and the lower perfect square. 141 – 121 = 20 Find the difference between the greater perfect square and the lower perfect square. 144 – 121 = 23 20 23 Write the difference as a ratio. Divide to find the approximate decimal value. 20  23 ≈ 0.869

  13. The approximate value of to the nearest hundredth is 11.87. Additional Example 3 Continued Approximate to the nearest hundredth. Step 3: Find the approximate value. Combine the whole number and decimal. 11 + 0.869 = 11.869 Round to the nearest hundredth. 11.869 ≈ 11.87

  14. 154 – 144 169 – 144 Check It Out: Example 3 Estimate 154 to the nearest hundredth. 10 25 = 144 < 154 < 169; = 0.4; 154 ≈ 12.40

  15. Additional Example 4: Using a Calculator to Estimate the Value of a Square Root Use a calculator to find 600. Round to the nearest tenth. Using a calculator, 600 ≈ 24.49489742…. Rounded, 600 is 24.5.

  16. 800 = 28.28427125 ≈ 28.3 Check It Out: Example 4 Use a calculator to find 800. Round to the nearest tenth.

  17. Lesson Quizzes Standard Lesson Quiz Lesson Quiz for Student Response Systems

  18. Lesson Quiz Each square root is between two integers. Name the two integers. 1. 27 2. – 456 5 and 6 –22 and –21 Use a calculator to find each value. Round to the nearest tenth. 9.4 35.0 3. 89 4. 1223 5. A square field has an area of 2000 square feet. To the nearest foot, how much fencing would be needed to enclose the field? 179 ft

  19. Lesson Quiz for Student Response Systems 1. Name the two integers the square root is between. A. 5 and 6 B. 6 and 7 C.8 and 9 D.38 and 40

  20. Lesson Quiz for Student Response Systems 2. Use a calculator to round to the nearest tenth. A. 2.3 B. 4.5 C.6.7 D.9.2

  21. Lesson Quiz for Student Response Systems 3. Name the two integers the square root is between. A. –2 and –3 B. –10 and –11 C. –14 and –15 D. –15 and –16

More Related