1 / 20

Single and Multiple Bonds in Carbon Compounds

Single and Multiple Bonds in Carbon Compounds. sp 3 hybridization on C leads to 4 bonds. CH 4 is a good example. CH 3 (CH 3 ) is another example:. 1 C-C sp 3 /sp 3 bond. CH 3. C. H. H. H. sp 2. sp 2. C. sp 2. sp 2. C. sp 2. sp 2.

kert
Download Presentation

Single and Multiple Bonds in Carbon Compounds

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Single and Multiple Bonds in Carbon Compounds sp3 hybridization on C leads to 4 bonds. CH4 is a good example. CH3(CH3) is another example: 1 C-C sp3/sp3 bond CH3 C H H H

  2. sp2 sp2 C sp2 sp2 C sp2 sp2 Carbon can also exhibit sp2 hybridization: C2H4 (ethylene) H H H H

  3. C C 2 of sp2 orbitals on each C form C-H bonds ( total of 4 ) Remaining sp2 on each c overlap each other  gives C-C bond This uses 3 valence e - from each C to form 5 sp2 bonds ( bonds) H H 120˚ 120˚ H H (EachC contributes 1 valence e - to C-C bond.)

  4. + C C – Up to this point, need not be planar because  bond symmetric under rotation. 2p + + C C – –  bond

  5. C C  bond H H + + sp2 sp2 120˚ - - H H

  6. C C H H sp2 sp2 H H Planar Ethylene

  7. C C H H – + + – H H Nodal Line  * transitions in ethylene occur around 1700 Å (58,500 cm-1) Corresponds to an energy of about 600 kJoules/mole 

  8.  States in Ethylene * E 2py 2py C (Atom) C (Atom)  Molecule E = h = hc/ 1700 Å * Photon E = h 

  9. H H + H C C H H H Saturated carbons form only  bonds, and * higher in energy than π* (start to absorb ~ 1600 Å)  bond formed from two sp3 hybridized orbitals Cylindrically symmetrical about C-C bond.

  10. C sp sp sp sp C Carbon sp hybrids: Acetylene and the Triple bond C2H2 is H-CC-H + H - + - H

  11. H-C-C-H 2py 2py 2px sp H H C C 2px

  12. Short Comparison of Bond Order, Bond Length, Bond Energy C-C C-C C-C Molecule Bond Order Bond Length Bond E, kcal/mole Ethane, C2H6 1 (1 ) 1.54Å 83 Ethylene, C2H4 2 (1, 1π) 1.35Å 125 Acetylene, C2H2 3 (1, 2π) 1.21Å 230

  13. Although energy of π* in ethylene < *, conjugated polylenes have even lower energy π* levels. These absorb light at longer wavelength- sometimes even in visible (human eye’s light perception). Conjugated polyenes: C=C-C=C-C=C polyene

  14. C C C C C C C C C C C C MO = (Const)[2py(1) + 2py(2) + 2py(3) + 2py(4) +2py(5) + 2py(6) +………]. Add 2py Atomic Orbitals on each C This gives delocalized structure

  15. C C C C Energy H2C=CH-HC=CH2 * antibonding levels E=h (photon) 2p orbitals (one each on 4 carbons) bonding levels E=h for butadiene << E=h for ethylene Molecular Orbital Energies

  16. C C C C C C H H Electron Delocalization in Carbon Ring Compounds 120˚ sp2 H H H H

  17. or  This islocalized picture!

  18. + + + + + + – – – – – – Delocalized Picture H H H H Can form  bonds with these p orbitals. H H MO = (Const)[2py(1) + 2py(2) + 2py(3) + 2py(4) +2py(5) + 2py(6)] Add 6 2py Atomic Orbitals on each C There are 6 such combinations!

  19. MO = (Const)[2py(1) + 2py(2) + 2py(3) + 2py(4) +2py(5) + 2py(6)] Add 6 2py Atomic Orbitals on each C

  20. Can actually form a total of 6 delocalized M.O.’s for benzene (6 2p Atomic Orbital’s  6 M.O.’s).  Energy + Antibonding orbitals 0 (isolated C 2p) π2b π3b Bonding orbitals _ π1b

More Related