200 likes | 395 Views
Think and Tell: What do you see… geometrically speaking?. Far Hills, NJ. Wayne, NJ. Find the perimeter of each figure separately. 4 ft. 6 ft. 20 ft. 20ft. 4 ft. 10 ft. 6 ft. 7 ft. 7 ft. How much of material would be needed to cover those letters on the house?. Hmmmm ….
E N D
Find the perimeter of each figure separately. 4 ft 6ft 20 ft 20ft 4 ft 10 ft 6ft 7ft 7ft
How much of material would be needed to cover those letters on the house? Hmmmm….
Section 1-7: Perimeter, Circumference, & Area Objectives SWBAT: - Find perimeters of regular and irregular polygons. - Find areas of regular and irregular polygons. Vocabulary • Perimeter • Circumference • Area
Objective: Finding Perimeter and Area Perimeter: P = 4s Square Area: A = s2 s = side Perimeter: P = 2b + 2h Rectangle Area: A = bh b = base h = height Circumference: C = d or C = 2r Circle d = diameter r = radius Area: A = r2
Question: What is the difference between perimeter and area? How would an architect or construction worker use these different measurements? Answer: Perimeter is the measure of the distance around an object. Area is the measure of all the space inside an object.
Real-World Connection Fencing. Your pool is depicted in the diagram below. You want to build a fence around the deck. How much fencing will you need? Length of pool and deck: 15 + 3 + 3 = 21 feet Width of pool and deck: 20 + 3 + 3 = 26 feet Solve: P = 2L + 2W Formula = 2(21) + 2(26) Substitute = 94 Simplify You will need 94 feet of fencing.
Real-World Connection a) What is the area of the pool? b) What is the area of the fenced pool? Area= LxW Pool Area= 15(20)= 300 ft² Fenced Area= 21(26)=546 ft²
Real-World and Finding Circumference Biology. In the Pacific Northwest, a red fox has a circular home range with a radius of about 718 meters. What is the area of the home range of a red fox? A = r2 Formula A = (718) 2 Substitute = 1,619,566 Simplify
Finding Area of Irregular Figures Find the area of the figure. Separate the figure into rectangles. Use Area of a Rectangle Formula A1 = 6 ∙ 2 = 12 Total Area = 12 + 8 + 4 = 24 cm2 A2 = 4 ∙ 2 = 8 A3 = 2 ∙ 2 = 4
PERIMETER vs. AREA Each square has dimensions of 1 unit by 1 unit
Perimeter and Area of the Clubhouse Activity
At the end: SUMMARIZE! Homework: ONLINE QUIZ