HBr Study plan (2+n) and (3+n) REMPI

Aug 28, 2014

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HBr Study plan (2+n) and (3+n) REMPI.

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HBr Study plan (2+n) and (3+n) REMPI

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HBr Study plan (2+n) and (3+n) REMPI

T(n) = 4 T(n/3) +  (n)

T(n) = 4 T(n/3) +  (n) T(n) = 2 T(n/2) +  (n) E[X i ] = n/(n-i) X=X 0 + … + X n/2-1 E[X]=  n/(n-i) =  (n) 1  n/(n-i)  2 for i  n/2 n/2-1 i=1 compute the median m of A check if m occurs in A more than n/2 times  n/2  m  n/2  -1 n/2  n/2   n/2

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N-2

M. G. T. N. N-2. I-2. A-2. I-3. I. A. O.

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N 3

O. F. H. N 3. O. H. N 1. dRib P. The synthesis of thymine by thymidilate synthetase. O. H. N. N. H 2 N. H. H. CH 2. +. N 3. N 5 , N 10 -Methylene tetrahydrofolate. H. N. H. H. CH 2. O. N. N 1. O. 2 HC. N. dRib P. dUMP. R. thymidilate synthetase. FdUMP.

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HBr , angular distribution analysis E(0 ) Updated , 24.12.2013

HBr , angular distribution analysis E(0 ) Updated , 24.12.2013. Peak “A”. E0,J´=3. E0,J´=4. E. 4 h n ionization / H + formation. H + + Br*. H + + Br. H* + Br*. 3 h n dissociation / H* formation. H* + Br. J´ v´. 2 h n resonance excitation. v´,J´. HX**. Rydb .

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Consecutive Numbers 1 +1 2 +1 3 +1 4 n n+1 n+2 n+3

Consecutive Numbers 1 +1 2 +1 3 +1 4 n n+1 n+2 n+3 Even Consecutive Numbers 2 +2 4 +2 6 +2 8 n n+2 n+4 n+6 Odd Consecutive Numbers 1 +2 3 +2 5 +2 7

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n i = 1 → n f = 3 n i = 6 → n f = 5 n i = 4 → n f = 2 n i = 3 → n f = 6

Which one of these transitions in the Bohr hydrogen atom model leads to the emission of the photon with the longest wavelength? . n i = 1 → n f = 3 n i = 6 → n f = 5 n i = 4 → n f = 2 n i = 3 → n f = 6 n i = 5 → n f = 1.

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n = n 0, 0 + n 1, 0 + n 0, 2 + n 1, 2

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n=22 n=3

**. immune responses in brain. immune responses in spleen. n=22 n=3. b. a. n=28 n=7. *. *. *. n=22 n=3. c. d. n=28 n=7. *. *. *. e. f. n=22 n=3. n=28 n=7. *. *. *. **. *. *. *.

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n=3

B. A. n=3. n=2.

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N 3

N 3. Name: AA 60 yrs. Male Architect. K/C/O: I.H.D, H.T & D.M. C/O: Sudden CHEST PAIN with perspiration & Dyspnoea 2 nd episode since last 6 months Diagnosed as A.M.I. WITH C.C.F. WITH ARRYTHMIA. All cardiac enzymes increased

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To prove by induction that n! > 2 n for n > 3, n  N

To prove by induction that n! > 2 n for n > 3, n  N. Next. To prove by induction that n! > 2 n for n > 3, n  N. Prove : n! > 2 n for n = 4 n! = 4! = 24 2 4 = 16 24 > 16 True for n = 4. Next. To prove by induction that n! > 2 n for n > 3, n  N.

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1+2+3+…+n = n(n+1)/2

1+2+3+…+n = n(n+1)/2. We want to prove the above statement by mathematical Induction for all natural numbers (n=1,2,3,…). Slide 1. Next Slide. Step #1: Prove for n=1. 1+2+3+…+n = n(n+1)/2. We need to show that for n=1 the statement is true. Previous Slide. Slide 2. Next Slide.

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N 2 + H 2  NH 3

1. N 2 + H 2  NH 3. 2. S 8 + O 2  SO 3. 3. HgO  Hg + O 2. 4. Zn + HCl  ZnCl 2 + H 2. 5. Fe 2 (SO 4 ) 3 + KOH  K 2 SO 4 + Fe(OH) 3. 6. Na + H 2 O  NaOH + H 2. 7. PCl 5 + H 2 O  HCl + H 3 PO 4. 8. KClO 3  KClO 4 + KCl. 9.

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Proposition n°1 Proposition n°2 Proposition n°3 Proposition n°4 Proposition n°5

Question n°1. Proposition n°1 Proposition n°2 Proposition n°3 Proposition n°4 Proposition n°5.

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Mg + N 2  Mg 3 N 2

Practice. Magnesium metal is burned in nitrogen. Mg + N 2  Mg 3 N 2. Lead foil is immersed in silver nitrate. Pb + Ag +  Pb 2+ + Ag. A solution of ammonium sulfate is added to a saturated solution of barium hydroxide. NH 4 + + SO 2+ + Ba 2+ + OH -  BaSO 4 + NH 3 + H 2 O.

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MTH 213 Week 3 Study plan//tutorfortune.com

MTH 213 Week 3 Study plan//tutorfortune.com Click on below link to buy https://tutorfortune.com/products/mth-213-week-3-studyplan MTH 213 Week 3 Studyplan Click on below link to buy https://tutorfortune.com/products/mth-213-week-3-studyplan

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N 3

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HBr Study plan (2+n) and (3+n) REMPI

HBr Study plan (2+n) and (3+n) REMPI

Presentation Transcript

T(n) = 4 T(n/3) +  (n)

N-2

N 3

HBr , angular distribution analysis E(0 ) Updated , 24.12.2013

Consecutive Numbers 1 +1 2 +1 3 +1 4 n n+1 n+2 n+3

n i = 1 → n f = 3 n i = 6 → n f = 5 n i = 4 → n f = 2 n i = 3 → n f = 6

n = n 0, 0 + n 1, 0 + n 0, 2 + n 1, 2

n=22 n=3

n=3

N 3

To prove by induction that n! &gt; 2 n for n &gt; 3, n  N

1+2+3+…+n = n(n+1)/2

N 2 + H 2  NH 3

Proposition n°1 Proposition n°2 Proposition n°3 Proposition n°4 Proposition n°5

Mg + N 2  Mg 3 N 2

MTH 213 Week 3 Study plan//tutorfortune.com

N 3

To prove by induction that n! > 2 n for n > 3, n  N