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Unit 4 – Lesson 1 Apply Triangle Sum Properties And Angle Relationships

Unit 4 – Lesson 1 Apply Triangle Sum Properties And Angle Relationships. All sides are . CLASSIFICATION BY SIDES. At least 2 sides . CLASSIFICATION BY SIDES. leg. leg. base. No sides are . CLASSIFICATION BY SIDES. All angles are . CLASSIFICATION BY ANGLES.

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Unit 4 – Lesson 1 Apply Triangle Sum Properties And Angle Relationships

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  1. Unit 4 – Lesson 1 Apply Triangle Sum Properties And Angle Relationships

  2. All sides are  CLASSIFICATION BY SIDES

  3. At least 2 sides  CLASSIFICATION BY SIDES leg leg base

  4. No sides are  CLASSIFICATION BY SIDES

  5. All angles are  CLASSIFICATION BY ANGLES

  6. All angles are acute CLASSIFICATION BY ANGLES

  7. hypotenuse leg One right angle CLASSIFICATION BY ANGLES leg

  8. One obtuse angle and 2 acute angles CLASSIFICATION BY ANGLES

  9. Interior Angles – Angles inside a shape Exterior Angles – Angles outside a shape Corollary – Statement easily proved from another statement

  10. b c a b c a 180° The sum of the measures of a triangle = _______

  11. If two triangles have two angles that are _______, then the third angle is also ___________.  B E 80° 80° 40° 60° 40° 60° A C D F

  12. The measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles. a + b = 180° b + c + d = 180° b + c + d = a + b c + d = a

  13. The acute angles of a right triangle are ______________. complementary a + c + 90 = 180° a a + c = 90° c

  14. Classify the triangle by its sides and angles. right scalene

  15. Classify the triangle by its sides and angles. equilateral equiangular

  16. Classify the triangle by its sides and angles. isosceles obtuse

  17. 4. Find the value of x. Then classify the triangle by its angles. 2x + 3x + 55 = 180 5x + 55 = 180 -55 -55 75° 5x = 125 5 5 50° x = 25° acute

  18. 4. Find the value of x. Then classify the triangle by its angles. 4x – 5 + 3x + 5 + 40 = 180 7x + 40 = 180 -40 -40 75° 7x = 140 65° 7 7 x = 20° acute

  19. 4. Find the value of x. Then classify the triangle by its angles. 2x + 2 + 2x + 2 + 3x + 1 = 180 52° 7x + 5 = 180 52° -5 -5 7x = 175 76° 7 7 x = 25° acute

  20. 5. Find the measure of each exterior angle shown. x + 80 = 3x – 22 -x -x . 80 = 2x – 22 +22 +22 102 = 2x 2 2 51° = x 3(51)– 22 = 131°

  21. 5. Find the measure of each exterior angle shown. 2x + 103 – x = 6x – 7 x + 103 = 6x – 7 -x -x . 103 = 5x – 7 +7 +7 110 = 5x 5 5 22° = x 6(22)– 7 = 125°

  22. 5. Find the measure of each exterior angle shown. 2x + 3 + 51= 4x + 8 2x + 54 = 4x + 8 -2x -2x . 54 = 2x + 8 46 = 2x 23° = x 4(23)+ 8 = 100°

  23. 6. Solve for the variables. 65° 25° y + 90 + 65 = 180 y + 155 = 180 y = 25°

  24. 6. Solve for the variables. 5y + 55 + 70 = 180 5y + 125 = 180 -125 -125 5y = 55 5 5 y = 11° 55°

  25. 7. Find the measure of each missing angle. 120° 30° 60° 30° 60° 120°

  26. HW Problem 4.1 # 26 Ans:

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