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Clickers!

Clickers!. We will work out a synthetic route to achieve the following overall transformation in four steps. Clickers!. A: 1) B 2 H 6 , THF 2) NaOH, H 2 O 2 aq. B: 1) O 3 , CH 2 Cl 2 2) Zn/HOAc C: m CPBA, CH 2 Cl 2 D: KMnO 4 , H 3 O + E: Hg(OAc) 2 , H 2 SO 4 (aq.). Clickers!.

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Clickers!

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  1. Clickers! We will work out a synthetic route to achieve the following overall transformation in four steps.

  2. Clickers! A: 1) B2H6, THF 2) NaOH, H2O2 aq. B: 1) O3, CH2Cl2 2) Zn/HOAc C: mCPBA, CH2Cl2 D: KMnO4, H3O+ E: Hg(OAc)2, H2SO4 (aq.)

  3. Clickers! KMnO4, H3O+

  4. Clickers! KMnO4, H3O+

  5. Clickers! KMnO4, H3O+ A: pTsOH, toluene, D B: CrO3, H2SO4 (aq.) C: mCPBA, CH2Cl2 D: Sn, HOAc

  6. Clickers! KMnO4, H3O+ pTsOH, toluene, D

  7. Clickers – Spectroscopy. Data on an unknown organic compound whose formula is C6H8O2 will be presented. The questions will follow.

  8. IR Spectrum

  9. Clicker question: The degree of unsaturation in this compound is: A: 1 B: 2 C: 3 D: 4

  10. Clicker question: The degree of unsaturation in this compound is: A: 1 B: 2 C: 3 D: 4

  11. Clicker question: From the IR spectrum, what functional group is likely to be present? A: Ester B: Ketone C: Carboxylic acid D: Nitrile

  12. Clicker question: From the IR spectrum, what functional group is likely to be present? A: Ester B: Ketone C: Carboxylic acid D: Nitrile

  13. NMR Spectra.

  14. Clicker question: We know the compound contains a COOH group, and has 3 degrees of unsaturation. Based on this and the NMR spectra, what other functionality is present? A: Aromatic ring B: Alkyne C: Two Alkenes

  15. Clicker question: We know the compound contains a COOH group, and has 3 degrees of unsaturation. Based on this and the NMR spectra, what other functionality is present? A: Aromatic ring B: Alkyne C: Two Alkenes

  16. Clicker question: What is the structure of the unknown compound?

  17. Clicker question: What is the structure of the unknown compound?

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