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Esercitazione 2/2/07

Esercitazione 2/2/07. 1) OpAmp modello 0. ******************************************************************************* descrizione operazionale ideale .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 + AD=400k E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS

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Esercitazione 2/2/07

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  1. Esercitazione 2/2/07

  2. 1) OpAmp modello 0 ******************************************************************************* descrizione operazionale ideale .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 + AD=400k E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS *******************************************************************************

  3. 2) OpAmp ad anello aperto operazionale ad anello APERTO * descrizione operazionale ideale .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 AD=400k E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS VIN 1 0 DC 0 AC 1 SIN (0 3u 50 0 0 0) XAMP 1 0 3 OPAMP PARAMS: AD=500k RLOAD 3 0 1k .OP .TRAN 10u 60m 0 1u .DC LIN VIN -1.5 1.5 10m .AC DEC 100 1 100k .PROBE V(1) V(3) .END

  4. 3) OpAmp ad anello chiuso operazionale ad anello CHIUSO * descrizione operazionale ideale .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 AD=400k E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS VIN 2 0 DC 0 AC 1 SIN (0 3u 50 0 0 0) XAMP 2 1 3 OPAMP PARAMS: AD=500 R1 1 0 100 R2 3 1 10k .TRAN 10u 20m 0 1u .DC LIN VIN -1.5 1.5 10m .AC DEC 100 1 1k .PROBE V(1) V(3) .END

  5. 5) Bipolo S con OpAmp bipolo S con opamp .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 AD=400K E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS R1 1 0 500 R2 1 2 500 R3 3 0 1k XAMP 3 1 2 OPAMP PARAMS: AD=500k IIN 2 3 DC 0 .DC LIN IIN -20m 20m 100u .PROBE V(3,2) .END

  6. 6) Esercizio esercizio .SUBCKT OPAMP INP INM OUT PARAMS: VUMP=10 VUMM=-10 AD=400K E1 OUT 0 VALUE={MAX(MIN(AD*V(INP,INM),VUMP),VUMM)} .ENDS R1 1 0 500 R2 1 2 500 R4 3 2 1k XAMP 3 1 2 OPAMP PARAMS: AD=500k VIN 3 0 DC 0 .DC LIN VIN -20 20 10m .PROBE .END

  7. 7) Bipolo S con BJT bipolo S con BJT .MODEL bjt NPN IS=1fA BF=100 Q1 2 0 1 bjt Q2 3 2 4 bjt R1 3 2 100 VDD 3 0 DC 3.3 I1 1 0 DC 1m RP1 1 0 1Meg I2 4 0 DC 1m RP2 4 0 1Meg IIN 4 1 DC 0 .DC LIN IIN 1m -1m 0.0001m .PROBE V(1,4) I(IIN) .END

  8. 8) Bipolo S con MOS bipolo S con NMOS .MODEL NMOD NMOS LEVEL=1 VTO=0.6 MN1 2 0 1 0 NMOD W=500u L=1u MN2 3 2 4 0 NMOD W=500u L=1u R1 3 2 30k VDD 3 0 DC 3.3 I1 1 0 DC 0.5m RP1 1 0 1Meg I2 4 0 DC 0.5m RP2 4 0 1Meg IIN 4 1 DC 0 .DC LIN IIN 0.5005m -0.503m 0.0001m .PROBE V(1,4) I(IIN) .END

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