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Catalyst : 2C 8 H 18 + 25 O 2 → 16 CO 2 + 18 H 2 O ΔH = −10,900 kJ

Have out compound unit worksheet and 245 if not checked. Objective : Determine the heat of combustion for equations, grams, and moles of a substance. Catalyst : 2C 8 H 18 + 25 O 2 → 16 CO 2 + 18 H 2 O ΔH = −10,900 kJ.

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Catalyst : 2C 8 H 18 + 25 O 2 → 16 CO 2 + 18 H 2 O ΔH = −10,900 kJ

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  1. Have out compound unit worksheet and 245 if not checked.Objective: Determine the heat of combustion for equations, grams, and moles of a substance. Catalyst: 2C8H18+ 25 O2 → 16 CO2 + 18 H2O ΔH = −10,900 kJ If the reaction 2 moles of C8H18 produces 10,900 KJ, how many grams of octane would be required to produce 700,000 kJ?

  2. Heat of Combustion • How much energy is given off per amount of substance burned. • Heat of combustion: kJ/g (kilojoules per gram) • Molar heat of combustion: kJ/mol (kilojoules per mole)

  3. A substance burns and gives off 1,000 kJ of heat. If 20 g of the substance burned, what is the heat of combustion? 3,500 kJ of heat were given off after 72 g of a substance burned. What is the heat of combustion? 3.5 moles of a substance is burned and 7,000 kJ is released. What is the molar heat of combustion?

  4. 2C8H18+ 25 O2→ 16 CO2+ 18 H2OΔH = −10,900 kJ What is the molar heat of combustion of octane? 10,900 kJ per 2 moles = What is the heat of combustion of octane?

  5. 2C8H18+ 25 O2→ 16 CO2+ 18 H2OΔH = −10,900 kJ • How many grams of octane would be required to produce 150,000 kJ? • If 1.5 moles of octane were burned, how many kJ of energy would be released? kJ

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