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DIMENSION IN ACTION AND THE PROBLEM OF BEHAVIORAL UNITS M. Jackson Marr mm27@prism.gatech.edu. KINETIC ENERGY = 1/2 m v 2 = M L 2 /T 2 POTENTIAL ENERGY = m g h = M L 2 /T 2 TOTAL ENERGY = K + P (conserved) TOTAL ENERGY IS A CONSTANT OF MOTION. DIMENSIONAL CONSISTENCY?.
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DIMENSION IN ACTIONANDTHE PROBLEM OF BEHAVIORAL UNITSM. Jackson Marrmm27@prism.gatech.edu
KINETIC ENERGY = 1/2 m v2 = M L2/T2 POTENTIAL ENERGY = m g h = M L2/T2 TOTAL ENERGY = K + P (conserved) TOTAL ENERGY IS A CONSTANT OF MOTION
DIMENSIONAL CONSISTENCY? B = k r / (r + ro) Rout = {ln [1+(PB/γPR)(exp [1/Rin] – 1]} -1
log [cabin] = ?! But, log [4 cabins / 2 cabins] = log 2 = 0.30103.
Dimensional Analysis Period of a Pendulum T= f (L, g, m)? T1 = La (L T-2)b Mc in units of length, mass, and time. Solve for a, b, and c to yield dimensional consistency. a =1/2, b = -1/2, c =0, gives: T = k (L/g)1/2 , where k is dimensionless. In fact, k = 2π.
If f (x) = c xα then, log f (x) = log c + α log x. This is a linear function on a log-log-scale.
Scaling in IRT>t Schedules IRT>t Scheduled Value
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Baum’s Law (B1 / B2) = b(r1 / r2)a b: bias a: sensitivity