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CENG 241 Digital Design 1 Lecture 5. Amirali Baniasadi amirali@ece.uvic.ca. This Lecture. Lab Review of last lecture: Gate-Level Minimization Continue Chapter 3:XOR functions, Hardware Description Language HW 2: Due Thursday May 31st. FIRST MIDTERM: THURSDAY JUNE 14, IN CLASS. Midterm 1.
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CENG 241Digital Design 1Lecture 5 Amirali Baniasadi amirali@ece.uvic.ca
This Lecture • Lab • Review of last lecture: Gate-Level Minimization • Continue Chapter 3:XOR functions, Hardware Description Language • HW 2: Due Thursday May 31st. • FIRST MIDTERM: THURSDAY JUNE 14, IN CLASS.
Midterm 1 • CENG 241 Digital Design 1 Midterm #1 (sample) • Important Note: Show your work for all sections. • Consider the following Boolean function: • F(A, B, C, D, E) = Σ (8,10,13,15,16,18,21,23,25,27) and d(A, B, C, D, E) = Σ (0,2,5,7,29,31) • Use the 1’s in the map to find the simplest Boolean function and implement it using only NAND gates. Draw the logic.(10 points) • Use the 0’s in the map to find the simplest Boolean function and implement it using only NOR gates. Draw the logic. (10 points) • NOTE: Each gate may have up to 3 inputs.
Multilevel NAND circuits • Sum of Products and Product of Sums result in two level designs • Not all designs are two-level e.g., F=A.(C.D+B)+B.C’ • How do we convert multilevel circuits to NAND circuits? • Rules • 1-Convert all ANDs to NAND gates with AND-invert symbol • 2-Convert all Ors to NAND gates with invert-OR symbols • 3-Check the bubbles, insert bubble if not compensated
Multilevel NAND circuits B’ BC’
Exclusive-OR Function X XOR Y = X’.Y+X.Y’ two input XOR IS 1 if both inputs are not similar
Three-input XOR Function F = A XOR B XOR C Multiple input XOR is 1 only if the number of 1 variables is odd: ODD function
Four-input XOR Function F detects odd number of 1s, F’ detects even number of 1’s
Parity Generation and Checking • Parity bit: extra bit to ensure correct transmission of data • Parity bit is included in the message to make the number of 1s either odd (odd parity) or even (even parity). • We can use XOR to see if the number of 1’s is odd. • We can use XOR-invert to see if the number of 1’s is even. • We include the XOR output in the message • Later at receiver we check the number of 1 bits to see if the transmission is correct.
Hardware Description Language • Hardware Description Language explains hardware in textual form • Represents digital circuits • HDL has two applications: 1-Simulation: represents structure and behavior of digital circuits 2-Synthesis:Derives a list of components and interconnections from HDL. Two examples of HDL: VHDL, Verilog We use verilog since its easier to learn.
Hardware Description Language-example //HDL Example 3-1 //-------------------------- //Description of the simple circuit of Fig. 3-37 module smpl_circuit(A,B,C,x,y); input A,B,C; output x,y; wire e; and g1(e,A,B); not g2(y, C); or g3(x,e,y); endmodule
Hardware Description Language-example //HDL Example 3-2 //--------------------------------- //Description of circuit with delay module circuit_with_delay (A,B,C,x,y); input A,B,C; output x,y; wire e; and #(30) g1(e,A,B); or #(20) g3(x,e,y); not #(10) g2(y,C); endmodule How do we take into account gate delays?
Test bench • To simulate circuits we need input signals. • The HDL description that provides the input/stimulus is called a test bench
Test bench example //HDL Example 3-3 //---------------------- //Stimulus for simple circuit module stimcrct; reg A,B,C; wire x,y; circuit_with_delay cwd(A,B,C,x,y); initial begin A = 1'b0; B = 1'b0; C = 1'b0; #100 A = 1'b1; B = 1'b1; C = 1'b1; #100 $finish; end endmodule //Description of circuit with delay module circuit_with_delay (A,B,C,x,y); input A,B,C; output x,y; wire e; and #(30) g1(e,A,B); or #(20) g3(x,e,y); not #(10) g2(y,C); endmodule
Combinational Logic Combinational Logic: Output only depends on current input Sequential Logic:Output depends on current and previous inputs
Design Procedure • 1.The number of inputs and outputs? • 2.Derive the truth table • 3.Obtain the Boolean Function • 4.Draw the logic diagram, verify correctness
Design Procedure example • Binary Adder-Subtractor • Basic block is a half adder. • Half Adder Design: • 1.needs 2 inputs 2 outputs • 2. Truth Table: x y C S 0 0 0 0 0 1 0 1 1 0 0 1 1 1 1 0 • 3. S=x’y+xy’ C=xy
Full Adder? • Truth Table: • x y z C S • 0 0 0 0 0 • 0 0 1 0 1 • 0 1 0 0 1 • 0 1 1 1 0 • 1 0 0 0 1 • 1 0 1 1 0 • 1 1 0 1 0 • 1 1 1 1 1
Full Adder Circuit Half adder ?
4-bit Adder Circuit But this is slow...
Summary • Implementation, XOR, Parity Checking, HDL • Reading up to page 121-end of chapter 3 • Homework 2: problems 3-11, 3-15, 3-20, 3-23 and 3-24 from textbook