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Mole/Stoichiometry. The awesome team of Alyssa H, Lauren F, and Dylan R. Stoichiometry:. A balanced equation can be in terms of particles, mass, and moles Study relationships or ratios between two or more substances going under a physical or chemical change. Mole:.
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Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R
Stoichiometry: • A balanced equation can be in terms of particles, mass, and moles • Study relationships or ratios between two or more substances going under a physical or chemical change
Mole: • The SI based unit used to measure the amount of a substance whose number of particles is the same as the number of atoms of Carbon in exactly 12 grams of Carbon 12 • When you convert from moles to moles use the molar ratio
Mole to Mole Ratio • The coefficient in front of the balanced equation is the # of moles • A mole ratio is required. A mole ratio is the ratio between moles of one substance to moles of another • ex.)__H2 +__ O2 ---> __ H2O How many moles of H2O are produced when 5.00 moles of oxygen are used?
1.) Balance the equation 2H2 + O2 ---> 2H2O 2.) Set up the equation with mole ratio 5 mole O2 2 H2O 1 O2 3.) Cancel out the O2 because they are across from each other.(Cross Multiply) 4.) This leaves you with 10 moles H2O Mole Ratio
Mole to Mass Walkthrough What is the mass of 2.4 moles of Lithium hydroxide (LiOH) 1. find the formula mass for LiOH- 23.95g 2. set up the equation so moles will cancel 2.4 mole LiOH X 23.95g LiOH = 57 grams LiOH 1 mole LiOH 3. multiply across
Mole to mass practice 1.) 3.79 moles of NaCl, what is the mass 3.79moles NaCl X 58.44g. NaCl=221g. NaCl 1 mole NaCl 2.) 1.63 moles of Hg2Cl, what is the mass 1.63moles Hg2Cl X 436.64g.Hg2Cl = 712g. Hg2Cl 1 mole Hg2Cl
Mole to Particles Walkthrough There is 2.4 moles of LiOH, how particles are there 1. use avogadro's number- 6.02 X 10^23 2. set up equation 2.4 mole LiOH X 6.02 X 1023 LiOH = 1.4 X 10^24 LiOH 1 mole LiOH 3. multiply across
Mole to particle practice 1.) 3.79 moles of NaCl, how many particles 3.79moles NaCl X 6.02 X 1023 NaCl=2.28X1024NaCl 1 mole NaCl 2.) 1.63 moles of Hg2Cl, how many particles 1.63moles Hg2Cl X 6.02 X 1023Hg2Cl =2.28X1024Hg2Cl 1 mole Hg2Cl
Moles to volume Walkthrough What is the volume of 2.4 moles of Lithium hydroxide (LiOH) 1. use 22.4 liters 2. set up the equation so moles will cancel 2.4 mole LiOH X 22.4 L LiOH = 53.76 L LiOH 1 mole LiOH 3. multiply across
Mole to volume practice 1.) 3.79 moles of NaCl, how many liter 3.79moles NaCl X 22.4 L NaCl =84.9 L NaCl 1 mole NaCl 2.) 1.63 moles of Hg2Cl, how many liters 1.63moles Hg2Cl X 22.4 L Hg2Cl = 36.5 L Hg2Cl 1 mole Hg2Cl
Mass to Moles Walkthrough 15g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 15g NH4NO3 how many moles of NH4NO3 do you have? 1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound) 2.) Simply multiply and BAM you found your answer. 3.) Now you know how to go from grams to moles 0.19 moles NH4NO3
Mass to Moles Practice 25g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 25g NH4NO3 how many moles of NH4NO3 do you have? 0.31 moles NH4NO3
Mass to Moles Practice 583g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 583g NH4NO3 how many moles of NH4NO3 do you have? 7.28 moles NH4NO3
Particle: • To go from moles to particles or particles to moles use Avagadros number • 6.02 10^23 particles/mole
Mass to Particles Walkthrough 15g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 15g NH4NO3 how many particles of NH4NO3 do you have? 1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound) 2.) Next multiply the third block which is 6.02 X 1023 formula units over 1 mole of the compound. 3.) You can plug this into your wiz bang and BAM you have found formula units from moles 6.02 X 1023 formula units 1 mol NH4NO 1.13 X 1023 formula units NH4NO3 X
Mass to Particles Practice 73g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 73g NH4NO3 how many particles of NH4NO3 do you have? 5.49 X 1023 formula units NH4NO3 6.02 X 1023 formula units 1 mol NH4NO X
Mass to Particles Practice 68g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 68g NH4NO3 how many particles of NH4NO3 do you have? 5.11 X 1023 formula units NH4NO3 6.02 X 1023 formula units 1 mol NH4NO X
Mass to Mass Walkthrough 30g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 30g NH4NO3 how many grams of H2O do you have? NH4NO3 N2O + H2O 1.) Balance the equation. NH4NO3 N2O + 2H2O 2.) Multiply the grams of what you're given (30g) by 1 mole of the compound you're given over the formula mass of that compound 3.) Next multiply by the mole ratio using the balanced formula 4.) Finally multiply by the formula mass of what you're finding of 1 mole of what you're finding 5.) Shazaam you've just converted from mass to mass 2 mol H2O 1 mol NH4NO3 18.02g H2O 1 mol H2O 13.5g H2O X X Formula Mass of NH4NO3 Formula Mass of H2O Mole Ratio
Mass to Mass Practice: 60g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 60g NH4NO3 how many grams of H2O do you have? NH4NO3 N2O + H2O 2 mol H2O 1 mol NH4NO3 18.02g H2O 1 mol H2O 27.02g H2O X X
Mass to Mass Practice: 78g NH4NO3 X 1 mol NH4NO 80.04g NH4NO3 If you have 78g NH4NO3 how many grams of H2O do you have? NH4NO3 N2O + H2O 2 mol H2O 1 mol NH4NO3 18.02g H2O 1 mol H2O 35.12g H2O X X
Particle to Mole Walkthrough 2NH3+H2SO4 (NH4)2SO4 If you have 4X1024 particles of NH3 how many moles of NH3 are there? 1.)Check to make sure the equation is balanced 2.)Multiply 4X1024 by Avogadro's Number 3.) Make sure to place Avogadro's Number on the numerator or denominator in order to cancel out units and leave moles 1moleNH3 6.02X1023particlesNH3 6.6molsNH3 4X1024 particlesNH3
Particle to Mole Practice 2NH3+H2SO4 (NH4)2SO4 1.)There is 8.76X1022 particles of H2SO4 convert to moles. 1moleH2SO4 6.02X1023particlesH2SO4 .146molsH2SO4 8.76X1022 particles H2SO4 2.)How many moles is 2.49X1017 particles of (NH4)2SO4? 1mole(NH4)2SO4 6.02X1023particles(NH4)2SO4 4.13X10-7mols (NH4)2SO4 2.49X1017particles (NH4)2SO4
Particle to Mass Walkthrough O2+2H2 2H2O If you have 6.82X1020 particles of O2 how many grams of O2 are there? 1.)Check to make sure the equation is balanced 2.)Multiply 6.82X1020 by Avogadro's Number and 1mole and make particle units cancel 3.)Multiply again by formula mass of O2 over 1mole to cancel out mole units leaving gramsO2 32gO2 1moleO2 1moleO2 6.02X1023particlesO2 6.82X1020 particlesO2 .0363gO2
Particle to Mass Practice O2+2H2 2H2O 1.)1.67X1018particlesH2 is how many grams? 2.016gH2 1moleH2 1moleH2 6.02X1023particlesH2 1.67X1018 particlesH2 5.59X10-6gH2 2.)8.43X1022particlesH2O is how many grams? 1moleH2O 6.02X1023particlesH2O 18.016gH2O 1moleH2O 8.43X1022 particlesH2O 2.52gH2O
Particle to Particle Walkthrough 2Fe+3Cl2 2FeCl3 If you have 6X1015 particles of Fe how many particles of FeCl3 are there? 1.)Check to make sure the equation is balanced 2.)Multiply by Avogadro's Number 3.)Multiply by the mole to mole ratio 4.)Go back to particles by multiplying by Avogadro again 5.)cancel out units and leave particlesFeCl3 2molFeCl3 2molFe 1molFe 6.02X1023particlesFe 6.02X1023particlesFeCl3 1molFeCl3 6X1015 part.Fe 6X1015particlesFeCl3
Particle to Particle Practice 2Fe+3Cl2 2FeCl3 1.)8X1020particles Cl2 is___ particles of Fe? 2molFe 3molC2 1molCl2 6.02X1023particlesCl2 6.02X1023particlesFe 1molFe 8X1020 part.Cl2 5.3X1020particlesFe 2.)1.7X1019particlesFe is ___ particles of Cl2? 3molCl2 2molFe 1molFe 6.02X1023particlesFe 6.02X1023particlesCl2 1molCl2 1.7X1019 part.Fe 2.55X1019particlesCl2
Volume to Mole Walkthrough 2As2O3+3C 3CO3+4As If you have 8L of Carbon how many moles are there? 1.)Check to make sure the equation is balanced 2.)Multiply 8L by 22.4L/moles 3.) Make sure to place the correct unit on the numerator or denominator in order to cancel out units and leave moles 1moleC 22.4LC .4molsC 8LC
Volume to Mole Practice 2As2O3+3C 3CO3+4As 1.) If you have 2.5L of As2O3 how many moles is it? 1moleAs2O3 22.4LAs2O3 .11molesAs2O3 2.5LAs2O3 2.) There is 11L of CO2 what is that in moles? 1moleCO2 22.4LCO2 .49molesCO2 11LCO2