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ENERGY METABOLISM. ENERGY METABOLISM. The study of how the body uses, stores and burns energy. Carbohydrates Fats Proteins. ENERGY BALANCE. ENERGY INPUT = ENERGY OUTPUT. Calories from food intake. = Digestion, metabolism, transport of nutrients, physical activity.
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ENERGY METABOLISM The study of how the body uses, stores and burns energy Carbohydrates Fats Proteins
ENERGY BALANCE ENERGY INPUT = ENERGY OUTPUT Calories from food intake = Digestion, metabolism, transport of nutrients, physical activity Maintenance of energy balance - contributes to health and well being - prevents the risk of developing many common health problems
ENERGY BALANCE • Equilibrium input = output, no weight change • Positive energy balance input > output, increase in weight (necessary during pregnancy, for infants and children) • Negative energy balance input < output, decrease in weight
Energy balance – Some questions?? • How much energy is contained a particular meal? Different foods? • How can the energy in foods be measured? • How can energy expended by an individual be measured? i.e., how would you measure energy input and out put???
production CALORIMETRY Good agreement between direct and indirect calorimetry
ENERGY VALUES OF FOODS 1 Kilocalorie = amount of heat required to raise the temperature of 1 kg of water through 1˚C (15˚ to 16˚C). 1 kcal = 1 Calorie (capital C) in nutrition 1 kcal = 4.184 kilojoules
ENERGY VALUES OF FOODS * The difference is due to energy content of urea, which cannot be further metabolized in the body
Question Mr. I.L. Nihari consumes 585 g carbohydrates, 150 g protein 110 g fat How many calories a day is he consuming? 585 x 4 = 2,340 kcal 150 x 4 = 600 kcal 110 x 9 = 990 kcal TOTAL = 3930 kcal/day
CO2 O2
INDIRECT CALORIMETRY Respiratory Quotient Vol of CO2 produced Vol of O2 consumed C6H12O6 + 6O2 6CO2 +6H2O + Heat 664 Kcal Therefore R.Q. for glucose oxidation = 6/6 = 1 C15H31COOH + 23O2 16CO2 + 16H2O + 2313Kcal Therefore R.Q. for Palmitic acid oxidation = 16/23 = 0.7 =
RESPIRATORY QUOTIENT CARBOHYDRATE = 1.0 FATS = 0.7 Proteins = 0.8 Mixed diet = 0.85 R.Q. > 1.0 Carbohydrates Fats R. Q. = 0.7 Starvation, Diabetes
DAILY ENERGY EXPENDITURE DEE = Basal metabolic rate + physical activity + Thermic effect of food + Thermogenesis
BASAL METABOLIC RATE (BMR)/ RESTING METABOLIC RATE (RMR) • BMR: The energy expenditure of a person mentally and bodily at rest in a thermoneutral environment 12-18 hours after a meal • For a sedentary person BMR accounts for 60% to 70% of the total body energy expenditure • Functioning of lungs, heart, kidneys, brain; maintenance of ionic gradients; reactions of metabolic reactions….. • RMR: If a person is not fasting or completely rested • Typically 6% higher than the BMR
BASAL METABOLIC RATE (BMR)/ RESTING METABOLIC RATE (RMR) • BMR is calculated by measuring O2 consumption for 6 min and using the following factor one liter of O2 consumed = 4.825 kcal Q: If 1.5 liters of O2 are consumed in 6 minutes calculate the BMR of a patient . • Approx equal to 25 kcal/kg/day Males 1600 -1800 kcal/day Females 1200 – 1450 kcal/day
FACTORS AFFECTING BMR Increase • Lean body mass • Larger surface area • Sex (M > F) • Body temperature: in fever 30-35% at 40˚C (104oF) • Nervous sytem activity (release of norepinephrine) • Hormones, esp. Thyroid hormone • pregnancy and lactation Decrease • Low calories intake • Aging
DAILY ENERGY EXPENDITURE DEE = Basal metabolic rate + physical activity + Thermic effect of food + Thermogenesis
PHYSICAL ACTIVITY • Most important factor in determining the DEE of an individual Modest = 0.3 x BMR Moderate = 0.4 x BMR Heavy = 0.5 x BMR
DAILY ENERGY EXPENDITURE DEE = Basal metabolic rate + physical activity + Thermic effect of food + Thermogenesis
Thermic effect of food • Energy required to digest, process and absorb food • Also known as Specific Dynamic Action • O2 consumption associated with digestion and absorption of foods • Protein 12% of total energy expenditure • Carbohydrates 6% of total energy expenditure • Fats 2% of total energy expenditure • Mixed diets 5-10% of total energy expenditure • 3000 Kcal diet, TEF 150-300 kcal
DAILY ENERGY EXPENDITURE DEE = Basal metabolic rate + physical activity + Thermic effect of food + Thermogenesis
FACTORS AFFECTING ENERGY REQUIREMENTS 1. BODY SIZE: with an in muscle mass 2. AGE : 22 – 50 yrs supposing at 2000 Kcal 51- 75 yrs 90% of age 22-50 yrs – 1800 Kcal >75 yrs 75-80% of age 22-50 yrs – 1500/1600 Kcal
FACTORS AFFECTING ENERGY REQUIREMENTS PHYSICAL ACTIVITY: The most important factor For person with very heavy physical activity add 600-900 Kcal PREGNANCY AND LACTATION: Pregnancy (2nd and 3rd Trimester) +300 Kcal Lactation + 500 Kcal
ENERGY REQUIREMENTS * MOST COMMONLY USED METHOD (TEF is ignored) Energy REQ = BMR + Physical Activity 1. BMR = wt (kg) x 25 Kcal 2. Physical Activity: Modest = 0.3 x BMR Moderate = 0.4 x BMR Heavy = 0.5 x BMR
ENERGY REQUIREMENTS Example: 70 Kg Man, Moderately Active BMR = 70 x 25 = 1750 Kcal Physical activity = 0.4 x 1750 = 700 Kcal Total = 2450 Kcal/day
CASE Mr I. L. Nihari He is 5’9’’ tall & weighs 264 lbs (120 kg). The doctor has advised him to lose 10 kg over a period of 5 months. Q. what should be his caloric intake to reduce the weight? Q. How many calories would he need to decrease per day to achieve the desired target? Q. What weight reduction plan would you advise this patient?
Diagnosis of Overweight and Obesity • Height-weight tables • Light, medium & heavy frame • Skin-fold thickness (specific areas) Triceps • Body Mass Index
Body Mass Index (BMI) Most commonly used to assess obesity- BMI = Wt (Kg)/Ht (m2) Underweight < 20.0 Normal (healthy) 20.0 – 24.9 Overweight 25.0 -29.9 Obese ≥ 30 Morbidly Obese > 45.1
STEP 1 Calculate his BMI: BMI = Body wt. in Kg Height in m2 = 120/(1.734)2 = 40.0
STEP 2 Calculate his caloric requirement on the basis of current body weight Caloric requirement = BMR + Physical activity (modest) (BMR x 0.3) 120 x 25 = 1875 + 900 = 3,900 kcal
STEP 3 Calculate his ideal body weight Ideal body weight = 100 + (5 x 3) (100 lbs for 5 ft; 5 lbs for every inch above 5 ft for women 106 lbs for 5 ft; 6 lbs for every inch above 5 ft for men) = 160 lbs (~73 kg)
STEP 4 Calculate his adjusted body weight adjusted body weight = Ideal body weight + 25% of (current body weight - ideal body weight) 73 + 11.8 = 84.8 kg
STEP 5 Calculate his caloric requirement on the basis of adjusted body weight Caloric requirement = BMR + Physical activity (modest) (BMR x 0.3) 84.8 x 25 = 2120 + 636 = 2756 kcal/day
STEP 6 How many grams of body weight does he need to reduce per day? (10 kg in 5 months) 10 kg in 5 months = 2 Kg / month = 2000/30 = 67g/day Caloric value of 67g adipose tissue (85% fat, 15% water) = ? 67 x 9 x 0.85 = 513 Kcal
STEP 7 Caloric Intake needed/day = 2756 – 513 = 2243 ≈2250 Kcal/day (2756 = Adjusted body wt. basis)
Comparison of energy requirements at various body weights • Current body weight = 3900 - 513 = 3387 Kcal • Ideal Body weight = 2372 - 513 = 1859 Kcal • Adjusted body weight = 2756 – 513 = 2250 Kcal
ADVICE FOR CHANGE IN LIFE STYLE • DIET: Eat a balanced diet, low in Calories FAD DIETS DON’T WORK • ↓ intake of high caloric density foods • Fried foods, sweets etc. • Substitute low fat milk for whole milk • Low fat yogurt for full fat yogurt • the intake of vegetables & fruits (Foods with high fiber content, Rich in vitamins & minerals
ADVICE FOR CHANGE IN LIFE STYLE • EXERCISE : Exercise (walk 1-2 miles/day or other physical activities) • BEHAVIOUR MODIFICATION