370 likes | 443 Views
Genotype x Environment Interactions. Analyses of Multiple Location Trials. Why do researchers conduct multiple experiments?. Effects of factors under study vary from location to location or from year to year. To obtain an unbias estimate.
E N D
Genotype x Environment Interactions Analyses of Multiple Location Trials
Why do researchers conduct multiple experiments? • Effects of factors under study vary from location to location or from year to year. To obtain an unbias estimate. • Interest in determining the effect of factors over time. • To investigate genotype (or treatment) x environment interactions.
What are Genotype x Environment Interactions? • Differential response of genotypes to varying environmental conditions. • Delight for statisticians who love to investigate them. • The biggest nightmare for plant breeders (and some other agricultural researchers) who tryto avoid them like the plague.
A No interaction Yield B Locations
A No interaction Yield B Locations A Cross-over interaction Yield B Locations
A No interaction Yield B Locations A Cross-over interaction Yield B Locations A Scalar interaction Yield B Locations
Examples of Multiple Experiments • Plant breeder grows advanced breeding selections at multiple locations to determine those with general or specific adaptability ability. • A pathologist is interested in tracking the development of disease in a crop and records disease at different time intervals. • Forage agronomist is interested in forage harvest at different stages of development over time.
Types of Environment • Researcher controlled environments, where the researcher manipulates the environment. For example, variable nitrogen. • Semi-controlled environments, where there is an opportunity to predict conditions from year to year. For example, soil type. • Uncontrolled environments, where there is little chance of predicting environment. For example, rainfall, temperature, high winds.
Why? • To investigate relationships between genotypes and different environmental (and other) changes. • To identify genotypes which perform well over a wide range of environments. General adaptability. • To identify genotypes which perform well in particular environments. Specific adaptability.
How many environments do I need? Where should they be?
Number of Environments • Availability of planting material. • Diversity of environmental conditions. • Magnitude of error variances and genetic variances in any one year or location. • Availability of suitable cooperators • Cost of each trial ($’s and time).
Location of Environments • Variability of environment throughout the target region. • Proximity to research base. • Availability of good cooperators. • $$$’s.
Points to Consider before Analyses • Normality. • Homoscalestisity (homogeneity) of error variance. • Additive. • Randomness.
Points to Consider before Analyses • Normality. • Homoscalestisity (homogeneity) of error variance. • Additive. • Randomness.
Bartlett Test(same degrees of freedom) 2n-1 = M/C M = df{nLn(S) - Ln2} Where, S = 2/n C = 1 + (n+1)/3ndf n = number of variances, df is the df of each variance
Bartlett Test(same degrees of freedom) S = 101.0; Ln(S) = 4.614
Bartlett Test(same degrees of freedom) S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083
Bartlett Test(same degrees of freedom) S = 100.0; Ln(S) = 4.614 M = (5)[(4)(4.614)-18.081] = 1.880, 3df C = 1 + (5)/[(3)(4)(5)] = 1.083 23df = 1.880/1.083 = 1.74 ns
Bartlett Test(different degrees of freedom) 2n-1 = M/C M = ( df)nLn(S) - dfLn2 Where, S = [df.2]/(df) C = 1+{(1)/[3(n-1)]}.[(1/df)-1/ (df)] n = number of variances
Bartlett Test(different degrees of freedom) S = [df.2]/(df) = 13.79/37 = 0.3727 (df)Ln(S) = (37)(-0.9870) = -36.519
Bartlett Test(different degrees of freedom) M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057
Bartlett Test(different degrees of freedom) S = [df.2]/(df) = 13.79/37 = 0.3727 (df)Ln(S) = (37)(=0.9870) = -36.519 M = (df)Ln(S) - dfLn 2 = -36.519 -(54.472) = 17.96 C = 1+[1/(3)(4)](0.7080 - 0.0270) = 1.057 23df = 17.96/1.057 = 16.99 **, 3df
Significant Bartlett Test • “What can I do where there is significant heterogeneity of error variances?” • Transform the raw data: Often ~ cw Binomial Distribution where = np and = npq Transform to square roots
Significant Bartlett Test • “What else can I do where there is significant heterogeneity of error variances?” • Transform the raw data: Homogeneity of error variance can always be achieved by transforming each site’s data to the Standardized Normal Distribution [xi-]/
Significant Bartlett Test • “What can I do where there is significant heterogeneity of error variances?” • Transform the raw data • Use non-parametric statistics
Model ~ Multiple sites Yijk = + gi + ej + geij + Eijk igi = jej = ijgeij Environments and Replicate blocks are usually considered to be Random effects. Genotypes are usually considered to be Fixed effects.
Models ~ Years and sites Yijkl = +gi+sj+yk+gsij+gyik+syjk+gsyijk+Eijkl igi=jsj=kyk= 0 ijgsij=ikgyik=jksyij = 0 ijkgsyijk = 0