1 / 9

Warm - up 6.4

Warm - up 6.4. Factor:. 1. 4x 2 – 24x. 4x(x – 6). 2. 2x 2 + 11x – 21. (2x – 3)(x + 7). 3. 4x 2 – 36x + 81. (2x – 9) 2. Solve:. 4. x 2 + 10x + 25 = 0. x = -5. 5. 6x 2 + x = 15. x = 3 / 2 and - 5 / 3. 6.4 solving polynomial equations.

misae
Download Presentation

Warm - up 6.4

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Warm - up 6.4 Factor: 1. 4x2 – 24x 4x(x – 6) 2. 2x2 + 11x – 21 (2x – 3)(x + 7) 3. 4x2 – 36x + 81 (2x – 9)2 Solve: 4. x2 + 10x + 25 = 0 x = -5 5. 6x2 + x = 15 x = 3/2 and-5/3

  2. 6.4 solving polynomial equations Objective – To be able to factor and solve polynomial expressions. CA State Standard - 3.0 Students are adept at operations on polynomials, including long division. - 4.0Students factor polynomials representing the difference of squares, perfect square trinomials, and the sum and difference of two cubes. by Jason L. Bradbury

  3. 6.4 solving polynomial equations 2x2 – 5x – 12 In Ch. 5 we learned how to factor: - A General Trinomial (2x + 3)(x – 4) - A Perfect Square Trinomial x2 + 10x + 25 (x + 5)(x + 5) = (x +5)2 - The Difference of two Squares 4x2 – 9 (2x)2 – 32 (2x + 3)(2x – 3) - A Common Monomial Factor 6x2 + 15x 3x(2x + 5)

  4. Example 1 Factor a) x4 – 6x2 – 27 (x2 + ?)(x2 – ?) (x2 + 3)(x2 – 9) (x2 + 3)(x – 3)(x + 3) b) x4 – 3x2 – 10 (x2 + ?)(x2 – ?) (x2 + 2)(x2 – 5)

  5. Sum of Two Cubes ** Special Factoring Patterns a3 + b3 = (a + b)(a2 - ab + b2) a = x x3 + 23 ex. x3 + 8 b = 2 (x + 2)(x2 – 2x + 4) Difference of Two Cubes a = 2x a3 – b3 = (a – b)(a2 + ab + b2) b = 1 ex. 8x3 – 1 (2x – 1)(4x2 + 2x + 1) (2x)3 – (1)3 Example 2 x3 + 125 a3 + b3 = (a + b)(a2 - ab + b2) x3 + 53 = (x + 5)(x2 – 5x + 25)

  6. Example 3 Factor a) x3 – 27 a3 – b3 = (a – b)(a2 + ab + b2) x3 – 33 = (x – 3)(x2 + 3x + 9) b) 8x3 + 64 a3 + b3 = (a + b)(a2 - ab + b2) (2x)3 + (4)3 = (2x + 4)(4x2 – 8x + 16)

  7. Must be the same Extra Example 2 Factor by grouping x3 – 2x2 – 9x + 18 x2(x – 2) -9(x – 2) (x2 – 9)(x – 2) (x – 3)(x + 3)(x – 2)

  8. 6.4 Homework Page 336 – 337 12 – 14, 21 – 27, and 31

  9. 6.4 Guided Practice Page 336 – 337 12 – 14 and 21 – 24

More Related