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EQUILIBRIUM BASICS. Chapter 14.1-14.3. Lesson Objectives. Which of the following is NOT true about a reaction at equilibrium? N 2 O 4 2NO 2. [N 2 O 4 ] = 2 [NO 2 ] The rate of the forward and reverse reactions are the same
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EQUILIBRIUM BASICS Chapter 14.1-14.3
Which of the following is NOT true about a reaction at equilibrium?N2O4 2NO2 • [N2O4] = 2 [NO2] • The rate of the forward and reverse reactions are the same • The equilibrium constant will describe whether the process favors reactants or products • [N2O4] and [NO2] remain constant. • For every 2 molecules of NO2 reacted, 1 molecule of N2O4 is produced
AT EQUILIBRIUM • Two reactions are occurring (forward and reverse) indicated by double arrow. • Equilibrium definition: a reaction has reached equilibrium (balance) when the forward and reverse reactions occur at the same RATE. • This means that concentrations of reactants and products stay CONSTANT over time
An Equilibrium Example See this interactive tutorial here
Equilibrium factors: • Equilibrium IS dependent on • TEMPERATURE (affects the equilibrium constant, K) • It is NOT dependent on • Original concentrations • Volume of the container • Total pressure of the system • Remember – the partial pressure of a gas in a mixture is proportional to the mole fraction of that gas in the mixture!
The following data are for the system A(g) 2B(g) How long does it take the system to reach equilibrium?
K: equilibrium constant • Tells us the extent to which the reaction will go until it reaches equilibrium • Large K means the reaction goes mostly to product • Small K means the reaction stays mostly as reactant
For a reaction2A(g) + B(g) 2C(g) K = 1 x 1083which of the following can be concluded? • At equilibrium, [A] = ½[B] = [C] • At equilibrium, the largest concentration is [A] • At equilibrium, the largest concentration is [C] • This reaction favors the reactants • This reaction happens very quickly
Writing K expression (equilibrium expression) • Uses only gaseous or aqueous products and reactants (no solids or liquids; their concentrations do not change during reactions) • Coefficients become exponents • Products over reactants • For aA + bBcC + dD Kp = or Kc= • Relate to each other: Kp = Kc(RT)Δng • R = gas law constant (0.0821 atm·L/mol·K) • Δng = change in moles of gas (products – reactants) (PC)c x (PD)d [C]c [D]d [A]a [B]b (PA)a x (PB)b
Which of the following species should NOT be included in the equilibrium constant expression for the reaction?2A(s) + B(aq) 2C(l) + D(g) • A, B, C • B, C • A, C • A, C, D • B, D
For a reaction 2A + B 2CWhen equilibrium is established, the ratio of products to reactants (K) = 0.5. Which of the following initial conditions could be changed to cause a different equilibrium constant value? • Start with more A • Dilute the reaction by adding water • Increase the temperature of the reaction • Add a catalyst
To calculate Kp from Kc for the reactionA(g) + 2B(g) C(g)what would be the exponent to which Kc(RT) is raised? • -2 • -1 • 0 • 1 • 2
Write the equilibrium constant (K) expressions for the following reactions: I2(g) + 5F2(g)2 IF5(g) SnO2(s) + 2H2(g)Sn(s) + 2H2O(l)
For the reaction2 NO(g) + O2(g) 2 NO2(g)determine the Kp at 298K if Kc is 4.67 x 1013
True or False? • Given the equation below, N2 + 3H2 2 NH3 if one mole of N2 is mixed with 3 moles of H2, 2 moles of NH3 will form.
True or False? • Given the equation below, N2 + 3H2 2 NH3 for every 1 mole of N2 that reacts, 3 moles of H2 will also react and 2 moles of NH3 will form.
Calculate K for the reactionNH4CO2NH2(s) 2 NH3(g) + CO2(g) if at equilibrium there are 0.159 g of NH4CO2NH2 and pressures of 0.0451 atm of CO2 and 0.0961 atm NH3
K depends on the form (coefficients) of the balanced equation! • This means that K changes when: • The coefficients are multiplied • Reactions are reversed • Reactions are added together (mechanism)
Coefficient rule: • If coefficients are multiplied by a factor (n), then K is RAISED TO THE (n) EXPONENT • A2 (g) + 2B (g) 2AB (g) K = • 3A2 (g) + 6B (g) 6AB (g) K = PAB2 PA x PB2 PAB6 PA3 x PB6
Calculate K for the formation of 2 moles of ICl(g)ICl (g) ½I2 (g) + ½Cl2 (g) K = 2.2x10-3
Reciprocal rule: • If the reaction is reversed, K of the forward and K of the reverse are reciprocals of each other (new K = 1/old K) • A2 (g) + 2B (g) 2AB (g) K = • 2AB (g) A2 (g) + 2B (g) K = PAB2 PA x PB2 PA x PB2 PAB2
Rule of multiple equilibria • If multiple reactions are added together to get an overall reaction, the overall K is the PRODUCT of the individual K’s A2 (g) + 2B (g) 2AB (g) 2AB (g) + C (g) A2B2C (g) A2 (g) + 2B (g) + C (g) A2B2C (g) Find overall K it by multiplying individual K’s:
Given the reactions below and their constants, calculate K for the rxn:Fe(s) + H2O(g) FeO(s) + H2(g) H2O(g) + CO(g) H2(g) + CO2(g) K = 1.6 FeO(s) + CO(g) Fe(s) + CO2(g) K = 0.67
Determining K • K must use values AT EQUILIBRIUM! • When given initial concentrations or pressures in a problem , you must determine what the values will be at equilibrium before you can calculate K • Use an ICE Chart to determine how the initial values will increase or decrease to get to equilibrium, then solve for K. • Solids and liquids have no effect on equilibrium, so they don’t need values in your ICE chart.
The ICE Chart • Initial/Change/Equilibrium • Given initial pressures, find equilibrium constant A2= 0.1 atm B = 0.2 atm A2(g) + 2B(g) 2AB(g) I C E 0.0 atm 0.2 atm 0.1 atm +2x -x -2x 0.1 - x 2x 0.2 - 2x
For the decomposition reactionNH4HS(s) NH3(g) + H2S(g) • In a sealed flask are 10.0 g of NH4HS, NH3with a partial pressure of 0.692 atm and H2S with a partial pressure of 0.0532 atm. When equilibrium is established, it is found that the partial pressure of NH3 has increased by 12.4%. Calculate K for this reaction.