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Engineering Tutorial: Analysis of 5 Degree of Freedom for Hanging Sign

Learn how to determine cable tensions and reaction components required to maintain equilibrium for a 2000N hanging sign, with MATLAB code examples and results.

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Engineering Tutorial: Analysis of 5 Degree of Freedom for Hanging Sign

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  1. Engineering 25 Tutorial:5 DoF, 3DAnalysis Bruce Mayer, PE Licensed Electrical & Mechanical EngineerBMayer@ChabotCollege.edu

  2. Hanging Sign • Determine the tensions in the cables and the components of reaction acting on the smooth collar at G necessary to hold the 2000 N sign in equilibrium. • The sign weight may concentrated at the center of gravity.

  3. 2000N

  4. MATLAB CrossProd • The Script-File Code % Bruce Mayer, PE * ENGR36 * 19Jul12 % ENGR36_H13_Tutorial_3D_5DoF_HangingSign_1207.pptx % clear clc MagV = @(z) sqrt(dot(z,z)) AHv = [-2 2 1] AHm = MagV(AHv) uAH = AHv/AHm EIv = [-2 2 -1] EIm = MagV(EIv) uEI = EIv/EIm rGH = [0 2 4] MAH = cross(rGH,3*uAH) rGI = [0 2 -3] MGI = cross(rGI,3*uEI) rGW = [2 0 0.5] uW = [0 -1 0] Mw = cross(rGW,uW)

  5. MATLAB Results • For the Moment Cross-Prods >> MAH = cross(rGH,3*uAH) MAH = -6 -8 4 >> MGI = cross(rGI,3*uEI) MGI = 4 6 4 >> Mw = cross(rGW,uW) Mw = 0.5000 0 -2.0000

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