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Limiting reactant. Limiting Reactant. Limiting Reagent The reactant that is totally used up during the chemical reaction Limits the amount of product produced . Excess Reactant. Excess Reagent
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Limiting Reactant • Limiting Reagent • The reactant that is totally used up during the chemical reaction • Limits the amount of product produced
Excess Reactant • Excess Reagent • The reactant present in a quantity that is greater than what is needed to react with the limiting reactant • Remains after the limiting reactant has been used up
What is the limiting reactant? • What are the excess reactants?
Steps • Balance the equation • Identify the givens (there are 2!) • Identify what you want to find • Use stoichiometry to solve • The reactant with a smaller amount of product produced is the limiting reactant • The other reactant is in excess
How many grams of silver bromide (AgBr) can be formed when solutions containing 50.0 g of MgBr2 and 100.0 g of AgNO3 are mixed together? What is the limiting reactant? What is in excess? 1 MgBr2+ 2AgNO3 2 AgBr+ 1 Mg(NO3)2 100.0g AgNO3 1 molAgNO32 molAgBr 187.77 g AgBr 169.88 g AgNO32molAgNO31 molAgBr 50.0g MgBr2 1 molMgBr22 molAgBr 187.77 g AgBr 184.11 g MgBr21molMgBr21 molAgBr = 102 g AgBr = 110.5 g AgBr Limiting Reactant (LR) = MgBr2 Excess Reactant (ER) = AgNO3
How many grams of hydrogen chloride can be produced from 1.00 g of hydrogen and 55.0 g of chlorine? What is the limiting reactant? What is in excess? H2 + Cl2HCl 55.0g Cl2 1 molCl22 molHCl 36.46 g HCl 70.90 g Cl21molCl21 molHCl 1.00g H2 1 molH2 2 molHCl 36.46 g HCl 2.02 g H21molH21 molHCl = 56.6 g HCl = 36.1g HCl Limiting Reactant (LR) = H2 Excess Reactant (ER) = Cl2
How many grams of barium sulfate (BaSO4) will be formed from 200.0 g of barium nitrate (Ba(NO3)2) and 150.0 g of sodium sulfate (Na2SO4)? What is the limiting reactant? What is in excess? Ba(NO3)2 + Na2SO4 BaSO4 + NaNO3 150.0g Na2SO4 1 molNa2SO42 molBaSO4 233.40 g BaSO4 142.05 g Na2SO42molAgNO31 molBaSO4 200.0g Ba(NO3)2 1 molBa(NO3)2 1 molBaSO4233.40 g BaSO4 261.35 g Ba(NO3)21molBa(NO3)2 1 molBaSO4 = 246.5 g BaSO4 = 178.6 g BaSO4 Limiting Reactant (LR) = Ba(NO3)2 Excess Reactant (ER) = Na2SO4