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Limiting Reactant

Limiting Reactant. When two or more reactants are reacted, one reactant may be used up before the other. Once you run out of just one of the reactants, the reaction will stop. So the amount of product that can possibly be made is determined by the reactant that is used up first.

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Limiting Reactant

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  1. Limiting Reactant

  2. When two or more reactants are reacted, one reactant may be used up before the other. Once you run out of just one of the reactants, the reaction will stop. So the amount of product that can possibly be made is determined by the reactant that is used up first. limiting reactant – the reactant that is used up first in a reaction and therefore determines the amount of product that can be made. excess reactant – the reactant that is leftover after the reaction stops.

  3. Analogy: 3 cups flour + 1 cup milk a 10 pancakes Suppose 6 cups flour and 3 cups of milk are available. a) What is the limiting reactant? b) How much of the excess reactant is leftover? c) How many pancakes can be produced?

  4. 3 cups flour + 1 cup milk a 10 pancakes 6 cups flour3 cups of milk a) What is the limiting reactant? Using the 6 cups of flour, figure out how much milk should be used with it. 1 cup of milk 6 cups of flour x = 2 cups of milk are needed 3 cups of flour Do we have that much milk? Yes, we have more than 2 cups. So the milk is the excess reactant and flour is the limiting reactant.

  5. 1 cup of milk 6 cups of flour x = 2 cups of milk are needed 3 cups of flour 3 cups flour + 1 cup milk a 10 pancakes 6 cups flour3 cups of milk b) How much of the excess reactant is leftover? We have 3 cups of milk available. And only two cups are used. 3 cups of milk available - 2 cups of milk used up 1 cup of milk leftover

  6. 3 cups flour + 1 cup milk a 10 pancakes 6 cups flour3 cups of milk c) How many pancakes can be produced? The amount of product (pancakes) is determined by the limiting reactant. 10 pancakes 6 cups of flour x = 20 pancakes can be made 3 cups of flour

  7. N2 + 3 H2a 2 NH3 2.0 mole 5.0 mole available a) What is the limiting reactant? b) How much of the excess reactant is leftover? c) How many moles of NH3 can be produced?

  8. N2 + 3 H2a 2 NH3 2.0 mole 5.0 mole available Starting with the 2.0 mole N2, figure out how much of the other reactant is needed. 3 mole H2 2 mole N2 x = 6 mole of H2 are needed 1 mole N2 Since we don’t have that much H2, it is the L. R.

  9. N2 + 3 H2a 2 NH3 2.0 mole 5.0 mole available -1.67 mole Use the limiting reactant to figure out how much of the excess reactant is used up. 1 mole N2 5 mole H2 x = 1.67 mole of N2 are reacted 3 mole H2 2.0 mole N2 available - 1.67 mole N2 used up 0.33 mole N2 leftover

  10. N2 + 3 H2a 2 NH3 ? 3.33 moles 2.0 mole 5.0 mole Use the limiting reactant to figure out how much product is made. 2 mole NH3 5 mole H2 x = 3.33 moles of NH3 are made 3 mole H2

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