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Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL

Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL. http://www.neosci.com/demos/10-1041_cell%20processes/Presentation%20Images/tutorials/3.01.jpg. Ψ = pressure potential ( Ψ p ) + solute potential ( Ψ s ) .

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Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL

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  1. Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL http://www.neosci.com/demos/10-1041_cell%20processes/Presentation%20Images/tutorials/3.01.jpg

  2. Ψ = pressure potential (Ψp) + solute potential (Ψs) • Pressure potential ψp= amount of pressure on the container surrounding the solution • Water is less likely to move • into container if ψpis high • Increasing pressure potential Ψpincreases Ψ http://www.phschool.com/science/biology_place/labbench/lab1/watpot.html

  3. Ψ = pressure potential (Ψp) + solute potential (Ψs) PLANTSWater moving into plant cell puts pressure on cell wall. INCREASESPRESSURE POTENTIALwhich INCREASESWATER POTENTIAL http://www.phschool.com/science/biology_place/labbench/lab1/watpot.html

  4. Adding solute lowers SOLUTE POTENTIAL (ALSO CALLED OSMOTIC POTENTIAL) Makes it more _____________ Overall WATER POTENTIAL decreases too Water = more likely to flow toward areas with low water potential SOLUTE SUCKS! Ψ = pressure potential (Ψp) + solute potential (Ψs) NEGATIVE animation

  5. In open system (like beaker)pressure potential Ψp= O In closed system (like plant cell with rigid cell wall) pressure potential Ψp can be a positive or negative number, or zero.

  6. SI UNITS 1 Bar = 1 Atm1 Bar = 0.1 Megapascals (Mpa) Ψ of pure distilled water at 1 atmosphere pressure = 0 bars http://www.neosci.com/demos/10-1041_cell%20processes/Presentation_4.html

  7. Ψ = pressure potential (Ψp) + solute potential (Ψs) ) • PURE WATER in an OPEN CONTAINER • Water Potential Ψ = ZERO

  8. http://www.cetbiology.com/biology-photographs/waterpotential.jpghttp://www.cetbiology.com/biology-photographs/waterpotential.jpg

  9. The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at 27 degrees. Round your answer to the nearest hundredth. • Ψs= -iCRT= -(1) (0.3 mole/L) (0.0831 liter bar/mole K) (300 K) = -7.48bars Now that you know the Ψs you can calculate the water potentialΨ of this beaker of liquid. Ψ = pressure potential (Ψp) + solute potential (Ψs) Ψ = 0 + -7.48 bars Ψ = -7.48 bars

  10. http://www.phschool.com/science/biology_place/labbench/lab1/quiz.htmlhttp://www.phschool.com/science/biology_place/labbench/lab1/quiz.html What is the water potential of the distilled water? What is the water potential of the beet core? Which way will water move? • Ψ = pressure potential (Ψp) + solute potential (Ψs) • Ψ = 0 + 0 = 0 bars Ψ = 0.2 + -0.4 = -0.2 bar From higher Ψ to lowerΨ - move from distilled (0) in beaker into beet core (-0.2)

  11. http://www.phschool.com/science/biology_place/labbench/lab1/quiz.htmlhttp://www.phschool.com/science/biology_place/labbench/lab1/quiz.html

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