1 / 6

Calculating Watts

Calculating Watts. Watt Watt Watt?!?!. A watt is the basic unit of power. Power is the rate at which electrical energy is delivered to a circuit. “How many watts?” is a question often asked about speakers, sound systems, hair dryers, and light bulbs . OHMMMMM….

peony
Download Presentation

Calculating Watts

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Calculating Watts

  2. Watt Watt Watt?!?! • A watt is the basic unit of power. • Power is the rate at which electrical energy is delivered to a circuit. • “How many watts?” is a question often asked about speakers, sound systems, hair dryers, and light bulbs.

  3. OHMMMMM…. • Ohms law states that voltage is the product of current and resistance. If you know two of the values, you can calculate the third. • The power formula is related to Ohms law. Use the power formula to calculate the current flow when a lamp is on. • The power formula is stated as: • P=E(I) • Where, • P=Power in Watts (W) • E=Operating Voltage • I=Current in amperes

  4. What is the power for a light bulb with a voltage of 12.6 V and a current of 1.04 A? P=E(I) P=12.6V(1.04A)=13.1W Round the wattage to tenths, voltage to tenths, and current to hundredths. Rewrite the power formula in terms of the current. Solve for I. Start with P=E(I) Divide both sides by E. P/E=E(I)/E I=P/E Calculate the current in a bulb where the voltage is 14.5V and the power is 4.9W: I=P/E (4.9W)/(14.5V)=0.34A

  5. A 1154 bulb has a double filament. The operating voltage is 6.4 V and the currents are 2.63 A and 0.75 A? What are the power values for each filament? For the lower-current filament: P=E(I)=6.4V(0.75A)=4.8W For the higher-current filament: P=E(I)=6.4V(2.63A)=16.8W

  6. Don’t Get Frustrated!

More Related