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Kinetic Model of Gases. Section 1.9, 1.11. Assumptions. A gas consists of molecules in ceaseless random motion The size of the molecules is negligible in the sense that their diameters are much smaller than the average distance traveled between collisions
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Kinetic Model of Gases Section 1.9, 1.11
Assumptions • A gas consists of molecules in ceaseless random motion • The size of the molecules is negligible in the sense that their diameters are much smaller than the average distance traveled between collisions • The molecules do not interact, except during collisions
Pressure of a gas • M molecular weight; V volume • c root-mean-square speed (rms speed)
Speed of gases • r.m.s. speed • mean speed
Average speed of gas molecules • Effect of Molecular Weight • Temperature Effect
Kinetic Energy of Molecules • Ek = 3/2 RT Ekkinetic energy; T temperature; R gas constant • The average kinetic energy per molecule kB Boltzmann constant = R/6.021023
Partial Pressure • Dalton’s Law The total pressure observed for a mixture of gases is equal to the sum of the pressures that each individual component gas would exert Ptotal = P1+P2+P3+…+PJ PJ = xJ Ptotal Ptotal total pressure; PJ partial pressure of component J;cJ molar fraction of component J.
Diffusion & Effusion • Diffusion Molecule of different substances mingle with each other. • Effusion Escape of a gas through a small hole.
Diffusion & Effusion • Rates of diffusion and effusion of gases increase with increasing temperature. • For effusion the rate decreases with increasing molar mass.
Diffusion & Effusion • Graham’s Law At a given pressure and temperature, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Diffusion & Effusion • The rate at which hydrogen and carbon dioxide effuse under the same conditions of pressure and temperature are in the ratio
Diffusion & Effusion • Separation of uranium-235 from uranium-238, in the form of volatile solids UF6 http://www.columbia.edu/itc/chemistry/chem-c1403/text_chapters/nukes.html http://www.uic.com.au/uicchem.htm http://www.uilondon.org/index.htm
Effusion as a separation technique Use porous membranes to separate light gases from heavy ones • average speed of gas molecules depends on the masses of their molecules • heavy molecules in a mixture move slower on average than light ones • gases made of light molecules diffuse through pores in membranes faster than heavy molecules Differences from dialysis • membrane is permeable, not semipermeable: all gas molecules in the mixture can pass through it • size of molecules isn't usually important: pores in membrane are much larger than gas molecules • ...molecular velocity (and so, molecular mass) is the basis for separation, not size Examples • separating helium from oxygen • separating uranium isotopes as volatile UF6
Molecular Collisions • C= 平均自由路徑 / 飛行時間 = l / [1/ z] =l z • : 平均自由路徑; Z : 碰狀頻率 collision frequency • s : 碰狀截面積; s = pd2 • p : 壓力; T: 溫度; • NA: 亞佛加厥常數 l=RT / [21/2NAsp] Z=[21/2NAsc p] / RT
Molecule Collisions • l 1/p平均路徑隨壓力減少而增加 • l 1/s 分子之碰狀截面積越大, 平均自由路徑隨之減短 • zp 碰撞頻率隨壓力增加而增大 • z c 分子量越大的分子其碰撞頻率會低於分 子量小的分子
Maxwell distribution of speeds The Maxwell distribution of speeds f = F (s) DS F (s) = 4p[m / 2pkBT](3/2) s2 e-(ms2/2kBT) f : 運動速率在某個範圍內的分子之比例 s: 分子運動速率 speed; • Ds : 速率的範圍 interval of speed • KB: Boltzmann Constant
Maxwell distribution of speeds f = F (s) DS F (s) = 4p[m/ 2pkBT](3/2) s2 e-(ms2/2kBT) fDS 當設定的速率範圍增大時, 所含蓋的分子比例也隨之增加
Maxwell distribution of speeds • s2 當速率值趨向極小質 s2 趨於0.這表示具有極低 運動速率分子所佔的比力是非常小的. f = F (s) DS F (s) = 4p[m / 2pkBT](3/2)s2 e-(ms2/2kBT)
Maxwell distribution of speeds e -x(x =ms2/2kBT) • 這是一個"衰減"函數.當速率 (s) 非常大的時候指數值就相當小.也就是說具有極高運動速率的氣體分子比例是非常小的. • 分子量(M)越大, 指數值就越小. 大分子具有高運動速率的比例較小. • 溫度(T)升高, 指數值越大. 溫度越高具有較快運動速率的分子比例也越大. f = F (s)DS F (s) = 4p[m / 2pkBT](3/2) s2e-(ms2/2kBT)
Maxwell distribution of speeds 4p[m / 2pkBT](3/2) 使分子比例的呈現在0與1之間 f = F (s)DS F (s) = 4p[m / 2pkBT](3/2) s2 e-(ms2/2kBT)
Distribution of Translational Energy • Maxwell-Boltzmann Distribution Law • ekinetic energy (=1/2 mu2) f = F (e) De F (e) = 2p / (pkBT)(3/2)e1/2 e-(e/kBT)