410 likes | 534 Views
Electron Structure of the Atom. Chapter 7. 7.1 Electromagnetic Radiation and Energy. Electromagnetic Radiation. EM Radiation travels through space as an oscillating waveform . EM Radiation travels through a vacuum at a constant speed of 3.00×10 8 m/s. Properties of EM Radiation.
E N D
Electron Structure of the Atom Chapter 7
Electromagnetic Radiation • EM Radiation travels through space as an oscillating waveform. • EM Radiation travels through a vacuum at a constant speed of 3.00×108 m/s
Properties of EM Radiation • Wavelength (λ, measured in nm) • Frequency (υ, measured in Hertz, Hz)
Mathematical Relationships υλ = c υ = Frequency of the light (1/s, or Hz) λ = Wavelength of light (nm or m) c = CONSTANT, Speed of light (3.00×108 m/s)
Mathematical Relationships Ephoton=hυEphoton=(hc)/λ υ = Frequency of the light (1/s, or Hz) λ = Wavelength of light (nm or m) c = CONSTANT, Speed of light (3.00×108 m/s) h = Planck’s Constant (6.626×10-34 J×s) Ephoton = Energy of a single photon (J)
Example • Assume we want to determine the frequency of orange light and the energy of a single photon of this light. • Orange light = 600 nm = 6.00×10-7 m • υλ = c, therefore υ= c/λ • = 5.00×1014 Hz • Ephoton=hυ=(6.626×10-34J×s)(5.00×1014Hz) • Ephoton=3.31×10-19 J
PROBLEM • Calculate the frequency and photon energy for an X-ray of wavelength 1.00 nm. • X-Ray= 1.00 nm = 1.00×10-9m • υλ = c, therefore υ= c/λ • = 3.00×1017Hz • Ephoton=hυ=(6.626×10-34J×s)(3.00×1017Hz) • Ephoton=1.99×10-16J
PROBLEM • What color is laser with a frequency of 6.0×1014 Hz? • therefore • = 5.00×10-7 m = 500 nm • 500 nm = Green Light
Bohr Model of the Atom • Propsed by Niels Bohr • Explains the Emission Spectrum of Hydrogen • Relies of quantitizedenergy levels. • Does not work for atoms with more than one electron.
Orbitals and Orbits • Bohr’s model had electrons orbit in tight paths, but this only worked for Hydrogen. • Schrödinger expanded the model by using 3 dimensional orbitals
Energy Levels and Orbital Shape • Electrons are still in quantitized energy levels. • Orbitals of roughly the same size are in the same overarching, or principal, energy level. • There are four ground state orbital geometries: s, p, d and f.
Naming Orbitals • Orbitals are named for their principal energy level and their orbital geometry. • The n=1 principal energy level has only one geometry, s. • The n=2 principal energy level has two geometries, s and p. • n=3 is composed of s, p, and d • n=4 is composed of s, p, d and f.
Rules for Filling in Orbitals • Ground State Atoms have the same number of electrons as protons. • Aufbau Principle – Start with the lowest energy level. • Pauli Exclusion Principle – Max of two electrons in each orbital with opposite spins • Hund’s Rule – Electrons are distributed in orbitals of the same energy as to maximize the number of unpaired electrons.
Example Sodium p= 11 e= 11
PROBLEM Carbon
PROBLEM Titanium
Electron Configurations • Orbital diagrams are informative but take a lot of space. • Electron Configurations are a shorthand for these diagrams. • Though they convey the same information, they do not show sublevel organization.
Example Sodium p= 11 e= 11 Na 1s2 2s2 2p6 3s1
PROBLEM Nitrogen
PROBLEM Iron
Valance Electrons • Valance Electrons are those electrons in the last filled principal energy level. • Core Electrons are those below the valance level. • Valance Electrons for Main Group Elements are those in the highest s and p orbitals. • Main Elements in the same group have the same number of valance electrons.
Example Sodium ion p= 11 e= 10 Na 1s2 2s2 2p6
Ion Electron Configurations • Ion charges are as they are due to the role of orbitals. • Ions are stable at 1+, 2+, or such because that gets the electron configuration to a completed principal energy shell (for main group elements). • Na (1+) is isoelectronic with Neon (a completed n=2)
Valance Electrons and Chemistry • Valance electrons are the ones participating in chemical reactions. • Compounds are stabilized by reaching a filled principal energy level. • We will return to this next chapter.
Ionization Energy • Ionization Energy, the amount of energy required to remove en electron from an gaseous atom (kJ/mol) • The lower the ionization energy the more reactive a compound is.