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Entry Task: Dec 3 rd Monday. Question: Provide the rate expression of this reaction. 2PbCl 3 + 3Na 2 CO 3 Pb 2 (CO 3 ) 3 + 6NaCl You have 5 minutes!. Agenda:. Discuss Rates of Rxn 1 ws HW: Rate of Rxn #2 ws AND Pre-Lab Rates of Rxn Lab. 1 5. 1 1. 1 3. 1 3. 1 6.
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Entry Task: Dec 3rd Monday Question: Provide the rate expression of this reaction. 2PbCl3 + 3Na2CO3 Pb2(CO3)3 + 6NaCl You have 5 minutes!
Agenda: • Discuss Rates of Rxn 1 ws • HW: Rate of Rxn #2 ws AND Pre-Lab Rates of Rxn Lab
1 5 1 1 1 3 1 3 1 6 [BrO3-] t [H2O] t [Br2] t [Br-] t [H+] t 1. Write the reaction rate in terms of the disappearance of the reactants and the appearance of products. 5Br- (aq) + BrO3- (aq) + 6H+ (aq) 3Br2 (aq) + 3H2O (l) =− Rate = − =− = =
1 1 1 3 1 2 1 3 1 2 2 3 [NH3] t [NH3] t [N2] t [H2] t 2. For the reaction N2 (g) + 3 H2 (g) 2 NH3 (g), the rate of consumption of H2 was observed to be 3.50 x 10-4 M/s under certain conditions. Determine the rate of production of ammonia. Determine the rate of this reaction. = Rate = − =− This is our “X” what we are looking for, so get 2 out of there =− 3.50 x 10-4 M/s = =− 3.50 x 10-4 M/s = 2.33 x 10-4 M/s
1 3 2 3 1 2 1 2 1 3 [O3] t [O3] t [O2] t 3. For the reaction 2 O3 (g) 3 O2 (g), the rate of production of O2 was observed to be 1.35 x 10-4 M/s under certain conditions. Determine the rate of consumption of ozone and the rate of this reaction. = Rate = − 1.35 x 10-4 M/s = = − This is our “X” what we are looking for, so get 2 out of there = 1.35 x 10-4 M/s = 9 x 10-5 M/s
1 3 2 3 1 2 1 2 1 3 [O3] t [O3] t [O2] t 4. For the reaction 2O3 (g) ----- > 3O2 (g) the rate of production of O2 was observed to be 8.9 x 10-4 M/s under certain conditions. Determine the rate of consumption of ozone. = Rate = − 8.9 x 10-4 M/s = = − This is our “X” what we are looking for, so get 2 out of there = 8.9 x 10-4 M/s = 5.9 x 10-4 M/s
1 3 1 3 1 2 1 4 1 4 4 3 [A] t [B] t [C] t [C] t 5. For the reaction 2A + 3B 4C the rate of consumption of B was observed to be 0.2130M/s under certain conditions. Determine the rate of production of C . − − = Rate = This is our “X” what we are looking for, so get 2 out of there = − 0.2130 M/s = = 0.2130 M/s = 0.284 M/s
MORE PRACTICEHW: Finish backside of worksheet AND pre-Lab Rates Lab