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Score Key for MT5 EOT. 9 9. 6.25 6.25. x 2 + 6x + ____ = 72 + ____ (x + ____) 2 = ____ y = (x + ____) 2 - ____. x 2 – 5x + ____ = -6 + ____ (x + ____) 2 = ____ y = (x + ____) 2 - ____. 81. .25. 3. 2.5. 6/2 = 3. 5/2 = 2.5.
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9 9 6.25 6.25 x2 + 6x + ____ = 72 + ____ (x + ____)2 = ____ y = (x + ____)2 - ____ x2 – 5x + ____ = -6 + ____ (x + ____)2 = ____ y = (x + ____)2 - ____ 81 .25 3 2.5 6/2 = 3 5/2 = 2.5 3 81 2.5 .25 Notes: Move “C” to the other side and create “space” for your new numbers. Create ( )2 for you perfect square Find the number to be added to both sides and fill in your spaces. Make your equation look like y = ( )2 + c. This will create “Vertex Form” which will be used in MT6 for graphing.
12 -7 -24 2 -4 6 -3 -4 (x )(x ) - 3 - 4 - 4 + 2 6 -4 (3x )(x ) Notes: Diamond method works on both…
A B C A B C 22 – 4*4*-8 122 – 4*9*4 4 + 128 = 132 144 - 144 = 0 Positive is 2 roots Zero is 1 root Notes: Use b2 – 4ac to find possible roots + is two roots 0 is one root - Is no roots
-6 ± 62 – 4*2*3 2*2 -13 ± 132 – 4*8*4 2*8 -6 ± 36 – 24 4 -13 ± 169 – 128 16 -6 ± 2 3 4 -3 ± 3 2 -6 ± 12 4 -13 ± 41 16 Notes: Use Quadratic Formula: - b ± b2 – 4ac 2a The negative boy could decide if he wanted to go to the radical party with his two best friends and meet four awesome chicks and be home by two a.m.
0 (the ground) 10 seconds ? I have no idea 0 (the ground) Notes: Assign your values to your variables H is ending height T is time V is velocity C is starting height (when you are on the ground, height is 0)
h = -16(t)2 + v(t) + c 160 0 = -16(10)2 + v(10) + 0 H=0 T=10 V=? C=0 0 = -1600 + 10v 1600 = 10v V=160 Notes: Use gravity formula - h = -16t2 + vt + c, plug in variables, and solve for “V”
h = -16(t)2 + v(t) + c 5 h = -16(5)2 + 160(5) + 0 400 T=? (Maximum height) h = -400 + 800 H=400 T=0 T=10 Notes: Draw a picture of what is happening. You know velocity (160), you must figure out how many second it took to get to the maximum height. Plug in and solve.