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Keys and Coupling

Keys and Coupling. Many Types of Keys and couplings, however understand how Torque is transferred in between each, and forms shearing stresses. Shaft Coupling. Sometimes, join 2 shafts together Flanged couplings Torque in Shaft  Torque in Couplings  Shear in bolts Similarly keys.

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Keys and Coupling

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  1. Keys and Coupling • Many Types of Keys and couplings, however understand how Torque is transferred in between each, and forms shearing stresses

  2. Shaft Coupling • Sometimes, join 2 shafts together • Flanged couplings • Torque in Shaft  Torque in Couplings  Shear in bolts • Similarly keys Bolt circle Flanged Couplings Bolt Shaft

  3. Design of Shaft Torque applied, TA = ∏ τ d3 / 16 • Where, τ = shear stress in shaft d = shaft dia. Design of bolts Torque resisted, TR = Shear Stress Area x Radius of bolt circle TR = n . (∏/4) . db2 . τ b .(D/2) Where, τ b = shear stress in bolt db = bolt dia. D = Diameter of bolt circle n = number of bolts TA < TR

  4. Design of Shaft Torque applied, TA = ∏ τ d3 / 16 • Where, τ = shear stress in shaft d = shaft dia. Design of keys Torque resisted, Tk = Shear Stress Area x Radius of shaft Tk = l b τ k (D/2) Where, τ k = shear stress in key db = bolt dia. D = Diameter of bolt circle n = number of bolts TA < Tk .

  5. Springs and Stiffness Stiffness of spring Load required to produce a unit deflection in spring. K = F/x x=unit deflection Under gravity, W = F

  6. Springs Types of spring • Bending / leaf / laminated spring • Torsion / helical spring • Close Coil helical spring • Open Coil helical spring

  7. Springs Uses of Springs • Storing energy, used in watch • Shock absorbers • Seismic isolation • Spring balance • Cycle seats

  8. Closed Coiled helical springs subjected to axial loads R = radius of the coil d = Spring wire diameter W= axial load on spring N = number of coils/turns δ = deflection τ, θ, G, Torque produced by axial load T = W R Also T = ∏ τ d3/16 Thus, ∏ τ d3/16 = W R

  9. Length of wire = no. of coils x length of one coil Or, l = n 2∏R T = G θ J l θ = 64 WR2 n Gd4 δ = R. θ = 64 WR3 n Gd4 Stiffness, s = W = Gd4 δ 64 R3 n Energy Stored in a spring, U = (1/2) W δ

  10. Combined Bending and Torsion Find how Tanθ = 2 τ / f = T /M Where • T = Torsion, • M = Bending Moment • τ = Shear Stress • M = Bending Stress

  11. Tutorial- 2 • Sketch 5 examples of use of springs • List differences between closed and open coil springs. Provide one sketch minimum • Answer Q.1. from Rethalia’s exercise on Helical Springs. pp. 72 • Answer Q.1. to Q.7 from Rethalia’s example exercise

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