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Unit 6. Covalent Bonding. Lesson 1:Covalent Bonding. Covalent bonds: atoms held together by sharing electrons. Molecules : neutral group of atoms joined together by covalent bonds.
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Unit 6 Covalent Bonding
Lesson 1:Covalent Bonding • Covalent bonds: atoms held together by sharing electrons. • Molecules: neutral group of atoms joined together by covalent bonds. • Diatomic molecule: molecule consisting of 2 atoms. Remember them: F2, Cl2, I2, Br2, H2, N2, O2 • Molecules tend to have lower melting and boiling points than ionic compounds. • YouTube - Making Molecules with Atoms
Molecular Formula • Shows how many atoms of each element a molecule contains. • Naming binary molecular compounds • Composed of two nonmetals; often combine in more than one way. Ex. CO and CO2 • Prefixes are used to name binary molecular compounds.
Binary Compounds Containing Two Nonmetals To name these compounds: give the name of the less electronegative element first with the Greek prefix indicating the number of atoms of that element present After give the name of the more electronegative non-metal with the Greek prefix indicating the number of atoms of that element present and with its ending replaced by the suffix –ide. Do not use the prefix mono- if required for the first element.
Binary Molecular Compounds N2O dinitrogen monoxide N2O3dinitrogentrioxide N2O5dinitrogenpentoxide ICl iodine monochloride ICl3 iodine trichloride SO2 sulfur dioxide SO3 sulfur trioxide YouTube - Naming molecular compounds
Binary Molecular CompoundsContaining Two Nonmetals As2S3 • ________________ diarsenic trisulfide • ________________ sulfur dioxide • P2O5 ____________________ • ________________ carbon dioxide • N2O5 ____________________ • H2O ____________________ SO2 diphosphorus pentoxide CO2 dinitrogen pentoxide dihydrogen monoxide
Naming Binary Compounds Binary Compound? Yes Metal Present? No Yes Molecule Use Greek Prefixes Does the metal form more than one cation? No Yes Ionic compound (cation has more than one charge) Determine the Charge of the cation; use a Roman numeral after the cation name. Ionic compound (cation has one charge only) Use the element name for the cation. Zumdahl, Zumdahl, DeCoste, World of Chemistry2002, page 98
Lesson 2: The Nature of Covalent Bonding • Introduction with balloon activity • octet rule: electron sharing occurs usually so that atoms attain the electron configurations of noble gases. • Single covalent bond: two atoms held together by sharing a pair of electrons. Shown as two dots or as a long dash. • A pair of valence electrons that is not shared between atoms is called an unshared pair.
H H O O H H or H H O
Double bonds: covalent bond formed by sharing two pairs of electrons • Triple bonds: covalent bond formed by sharing three pairs of electrons.
chlorine iodine nitrogen hydrogen Covalent bonding with equal sharing of electrons occurs in diatomic molecules formed from one element. A dash may replace a pair of dots.
Lesson 3:Molecular Structure • Structural formula: uses symbols and bonds to show relative position of atoms. • Steps to determine Lewis structures for molecules • Predict the location of certain atoms. • Hydrogen is always an end atom • The least electronegative atom is the central atom (usually the one closer to the left on periodic table) • Find the total number of electrons available for bonding. (# of valence electrons of atoms in molecule) • Determine the number of bonding pairs by dividing the total number of electron by 2
Place one bonding pair (single bond) between central atom and terminal atoms. • Subtract pairs used in step 4 from bonding pairs in step 3. Place lone pairs around each terminal atom bonded to the central atom to satisfy the octet rule. Any remaining pairs are assigned to the central atom. • If the central atom does not have an octet, convert one or two of the lone pairs on the terminal atoms to a double or a triple bond between central and terminal atom. Some elements like Be, B, Al do not form a complete octet, S and P can have more than 8 valence electrons.
Ex. 1 Draw the lewis structure for ammonia, NH3 • Hydrogen is an end atom and nitrogen is the central atom. • Total number of valence electrons: (1 nitrogen x 5 valence electrons)+ (3 hydrogens x 1 valence electron)= 8 valence electrons. • Total number of bonding pairs= 8/2 = 4 • Draw single bond from each H to N N H H H
Ex. 1 Draw the lewis structure for ammonia, NH3 • Subtract the number of pairs of electrons used from the total pairs of electrons: 4-3 =1 pair available One lone pair remains, hydrogen can have only one bond, assign the lone pair to the central atom, N. N H H H
Ex. 2 Draw the lewis structure for carbon dioxide, CO2 • Oxygen atoms are end atoms and carbon is the central atom. • Total number of valence electrons: (1 carbon x 4 valence electrons)+ (2 oxygen x 6 valence electron)= 16 valence electrons. • Total number of bonding pairs= 16/2 = 8 • Draw single bond from each C to O C O O
Ex. 1 Draw the lewis structure for carbon dioxide, CO2 • Subtract the number of pairs of electrons used from the total pairs of electrons: 8-2 =6 pair available Add three pairs of electrons to each oxygen. C O O
Ex. 1 Draw the lewis structure for carbon dioxide, CO2 • No lone pairs remain for carbon. Carbon does not have an octet, use a lone pair from each oxygen to form a double bond with the carbon atom. C C O O O O
Lesson :4 Exception to octet rule • Some molecules have an odd number of valence electrons and cannot form an octet around each atom. • Some molecules form with fewer than eight electrons present around an atom. Ex. Boron • Some compounds have central atoms with more than 8 electrons. This is called an expanded octet. Ex. S, Xe and P
Ex. 3 Draw the lewis structure for XeF4 (exception octet rule) • F is an end atom and nitrogen is the central atom. • Total number of valence electrons: (1 xenon x 8 valence electrons)+ (4 fluorines x 7 valence electron)= 36 valence electrons. • Total number of bonding pairs= 36/2 = 18 • Draw single bond from each F to Xe F Xe F F F
Ex. 1 Draw the lewis structure for XeF4 (exception octet rule) • Subtract the number of pairs of electrons used from the total pairs of electrons: 18-4 =14 pairs available 14 lone pairs remain, place them around each fluorine so that each fluorine has 8 valence electrons F Xe F F F
Ex. 1 Draw the lewis structure for XeF4 (exception octet rule) • There are 2 pairs of electrons still available, place around Xe which is capable of having more than 8 valence electron. F Xe F F F
Molecular Shape • VSEPR (Valence shell electron pair repulsion) Model • The repulsion between electron pairs in a molecule result in atoms existing at fixed angles from each other. (Remember balloon activity) • Shared electron pairs repel each other • A greater repulsion occurs between unshared electron pairs and shared electron pairs.
B : N : : O Bonding and Shape of Molecules:Count number of bonds and unshared pairs of electrons AROUND CENTRAL ATOM and then use table below to determine shape of molecule. Number of Bonds Number of Unshared Pairs Covalent Structure Shape Examples -Be- 0 0 0 1 2 2 3 4 3 2 Linear Trigonal planar Tetrahedral Pyramidal Bent BeCl2 BF3 CH4, SiCl4 NH3, PCl3 H2O, H2S, SCl2 C
O H H Use table on last slide to determine shape of molecule. SO2 Shape: bent 2 bonds and 2 unshared pairs
Cl Cl Cl C Cl C Cl Cl Cl 109.5o Cl Carbon tetrachloride Shape: Tetrahedral 4 bonds and 0 unshared pairs. CCl4 Carbon tetrachloride – “carbon tet” had been used as dry cleaning solvent because of its extreme non-polarity.
Classwork: do in your notebook • Determine the shape for the following molecules (first draw the lewis structure for the molecule and then use the table on slide #7 to determine the shape taking in consideration the number of bonds and unshared pairs of electrons around the CENTRAL ATOM.) • BF3 2. OCl2 3. CF4 4. NH3 5. BeI2