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The Temperature-Pressure Relationship Gay-Lussac’s Law

The Temperature-Pressure Relationship Gay-Lussac’s Law. The pressure of a gas is directly proportional to the temperature of a gas Temperature goes up; pressure goes up P 1 = P 2 T 1 T 2. Gay-Lussac’s Law example problems.

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The Temperature-Pressure Relationship Gay-Lussac’s Law

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  1. The Temperature-Pressure RelationshipGay-Lussac’s Law • The pressure of a gas is directly proportional to the temperature of a gas • Temperature goes up; pressure goes up P1= P2 T1 T2

  2. Gay-Lussac’s Lawexample problems • The gas left in a used aerosol can is at a pressure of 103 kPa at 25oC. If the can is thrown into a fire, what is the pressure of the gas when it reaches 928oC? 103 kPa = P2 298 K 1201 K P2 = 415 kPa

  3. Gay-Lussac’s Lawexample problems • Your turn • A container of propane has a pressure of 108.6 kPa at a morning temperature 15oC. By mid afternoon the temperature has reached 32oC. What is the pressure inside the propane tank?

  4. Gay-Lussac’s Lawexample problems • Answer 108.6 kPa = P2 288K 305 K P2 = 115 kPa

  5. The combined gas law P1 x V1= P2 x V2 T1 T2

  6. The combined gas lawexample problem • The volume of a gas-filled balloon is 30.0 L at 40oC and 153 kPa. What volume will the balloon have at STP? 153 kPa x 30.0 L = 101.3 kPa x V2 313 273 V2 = 3.95 L

  7. The combined gas lawexample problem • Your turn • A gas-filled balloon is 25.0 L at 35oC and 145 kPa. What is the temperature if the volume increases to 28 L and a pressure of 152 kPa?

  8. The combined gas lawexample problem • Answer 145 kPa x 25.0 L = 152 kPa x 28 L 308 K T2 T2 = 362 K = 88.6 oC

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