1 / 24

Warm Up

Warm Up. Problem of the Day. Lesson Presentation. Lesson Quizzes. 4. __. c. Warm Up Write an algebraic expression for each word phrase. 1. A number x decreased by 9 2. 5 times the sum of p and 6 3. 2 plus the product of 8 and n 4. the quotient of 4 and a number c. x – 9.

sereno
Download Presentation

Warm Up

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Warm Up Problem of the Day Lesson Presentation Lesson Quizzes

  2. 4 __ c Warm Up Write an algebraic expression for each word phrase. 1. A number x decreased by 9 2. 5 times the sum of p and 6 3. 2 plus the product of 8 and n 4. the quotient of 4 and a number c x – 9 5(p + 6)‏ 2 +8n

  3. Problem of the Day How many pieces do you have if you cut a log into six pieces and then cut each piece into 4 pieces? 24

  4. Learn to solve equations using multiplication and division.

  5. You can solve a multiplication equation using the Division Property of Equality.

  6. ? 6(8) = 48 ? 48 = 48 Additional Example 1A: Solving Equations Using Division Solve 6x = 48. 6x = 48 Use the Division Property of Equality: Divide both sides by 6. 6x = 48 6 6 1 • x = x 1x = 8 x = 8 Check 6x = 48 Substitute 8 for x. 

  7. ? –9(–5) = 45 ? 45 = 45 Additional Example 1B: Solving Equations Using Division Solve –9y = 45. –9y = 45 –9y = 45 Use the Division Property of Equality: Divide both sides by –9. –9 –9 1 • y = y 1y = –5 y = –5 Check –9y = 45 Substitute –5 for y. 

  8. ? 9(4) = 36 ? 36 = 36 Check It Out: Example 1A Solve 9x = 36. 9x = 36 Use the Division Property of Equality: Divide both sides by 9. 9x = 36 9 9 1 • x = x 1x = 4 x = 4 Check 9x = 36 Substitute 4 for x. 

  9. ? –3(–12) = 36 ? 36 = 36 Check It Out: Example 1B Solve –3y = 36. –3y = 36 Use the Division Property of Equality: Divide both sides by –3. –3y = 36 –3 –3 1 • y = y 1y = –12 y = –12 Check –3y = 36 Substitute –12 for y. 

  10. You can solve a division equation using the Multiplication Property of Equality.

  11. b –4 b = 5 –4 b = 5 –4 –20 ? = 5 –4 ? 5 = 5 Additional Example 2: Solving Equations Using Multiplication Solve = 5. Use the Multiplication Property of Equality: Multiply both sides by –4. –4 • –4 • b = –20 Check Substitute –20 for b. 

  12. c –3 c = 5 –3 c = 5 –3 –15 ? = 5 –3 ? 5 = 5 Check It Out: Example 2 Solve = 5. Use the Multiplication Property of Equality: Multiply both sides by –3. –3 • –3 • c = –15 Check Substitute –15 for c. 

  13. 1 4 1 x = 670 4 1 x = 670 4 Additional Example 3: Money Application To go on a school trip, Helene has raised $670, which is one-fourth of the amount she needs. What is the total amount needed? fraction of amount raised so far amount raised so far total amount needed  = • = x 670 Write the equation. Multiply both sides by 4. 4• 4• Helene needs $2680 total. x = 2680 Check: The amount raised so far is about $700. She needs about 4 times this amount, or $2800. The answer is reasonable.

  14. fraction of total amount raised so far 1 8 1 x = 750 8 1 x = 750 8 Check It Out: Example 3 The school library needs money to complete a new collection. So far, the library has raised $750, which is only one-eighth of what they need. What is the total amount needed? amount raised so far total amount needed =  • = x 750 Write the equation. 8• Multiply both sides by 8. 8• The library needs $6000 total. x = 6000 Check: The amount raised so far is about $800. She needs about 8 times this amount, or $6400. The answer is reasonable.

  15. Sometimes it is necessary to solve equations by using two inverse operations. For instance, the equation 6x 2 = 10 has multiplication and subtraction. Variable term 6x 2 = 10 Multiplication Subtraction To solve this equation, add to isolate the term with the variable in it. Then divide to solve.

  16. Additional Example 4: Solving a Two-Step Equation Solve 3x + 2 = 14. Subtract 2 to both sides to isolate the term with x in it. Step 1: 3x + 2 = 14 – 2 – 2 3x = 12 Step 2: 3x = 12 Divide both sides by 3. 3 3 x = 4

  17. Check It Out: Example 4 Solve 4y + 5 = 29. Subtract 5 from both sides to isolate the term with y in it. Step 1: 4y + 5 = 29 – 5 – 5 4y = 24 Step 2: 4y = 24 Divide both sides by 4. 4 4 y = 6

  18. Lesson Quizzes Standard Lesson Quiz Lesson Quiz for Student Response Systems

  19. x –4 Lesson Quiz Solve. 1.3t = 9 2. –15 = 3b 3. = –7 4.z ÷ 4 = 22 5. A roller coaster descends a hill at a rate of 80 feet per second. The bottom of the hill is 400 feet from the top. How long will it take the coaster rides to reach the bottom? t = 3 b = –5 x = 28 z = 88 5 seconds

  20. Lesson Quiz for Student Response Systems 1. Solve the equation. 7e = 28 A.e = 1 B.e = 2 C.e = 3 D.e = 4

  21. Lesson Quiz for Student Response Systems 2. Solve the equation. –72 = 4g A.g = –18 B.g = –17 C.g = –16 D.g = –15

  22. Lesson Quiz for Student Response Systems 3. Solve the equation. = –12 A.i = –72 B.i = –18 C.i = 72 D.i = 80 i–6

  23. Lesson Quiz for Student Response Systems 4. Solve the equation. k ÷ 9 = 13 A.k = 104 B.k = 117 C.k = 118 D.k = 123

  24. Lesson Quiz for Student Response Systems 5. A surf boat descends a stream running downhill at a rate of 15 ft/minute. The bottom of the hill is at 90 ft from the top. How long will it take the surf boat to reach the bottom? A. 3 min B. 4 min C. 5 min D. 6 min

More Related