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2 3. 18. or. 56 3. Warm Up Find each product. 1. 8 12 2. 3 3. 9.4 6.3 4. 3.5 7. 96. 1 3. 1 2. 5. 59.22. 24.5. California Standards. AF3.1 Use variables in expressions describing geometric quantities (e.g.,
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2 3 18 or 56 3 Warm Up Find each product. 1.8 12 2. 3 3. 9.4 6.3 4. 3.5 7 96 1 3 1 2 5 59.22 24.5
California Standards AF3.1 Use variables in expressions describing geometric quantities (e.g., P = 2w + 2l, A = bh, C = pd–the formulas for the perimeter of a rectangle,the area of a triangle, and the circumference of a circle, respectively). Also covered:NS2.1, AF1.1, AF2.1, AF3.2 1 2
Vocabulary area base height
h b The area of a figure is the number of non-overlapping unit squares needed to cover the figure. Area is measured in square units. Area = 15 square units The base of a parallelogram is the length of one side. Its height is the perpendicular distance from the base to the opposite side.
Finding the Area of a Parallelogram Find the area of the parallelogram. A = bh Use the formula. Substitute for b and h. A = 16 · 8 8 m Multiply. A = 128 16 m The area of the parallelogram is 128 m2.
Find the area of the parallelogram. A = bh Use the formula. Substitute for b and h. A = 12 · 6 6 cm Multiply. A = 72 12 cm The area of the parallelogram is 72 cm2.
Find the area of the rectangle. 4.5 in. 7.4 in. A = lw Use the formula. Substitute for l and w. A = 7.4 · 4.5 Multiply. A = 33.3 The area of the rectangle is 33.3 in2.
Find the area of the rectangle. 6.3 in. 8.2 in. A = lw Use the formula. Substitute for l and w. A = 8.2 · 6.3 Multiply. A = 51.66 The area of the rectangle is 51.66 in2.
The area of a playing field is 1,470 ft2 and the length is 42 ft. What is the width of the field? Use the formula for the area of a rectangle. A = lw 1,470 = 42 · w Substitute 1,470 for A and 42 for l. 1,470 42 42 · w 42 = Divide both sides by 42 to isolate w. 35 = w The width of the playing field is 35 ft.
The area of a rectangular parking lot is 3,570 ft2 and the width is 70 ft. What is the length of the parking lot? Use the formula for the area of a rectangle. A = lw 3,570 = l· 70 Substitute 3,570 for A and 70 for w. 3,570 70 l· 70 70 = Divide both sides by 70 to isolate l. 51 = l The length of the parking lot is 51 ft.
4 yd 5 yd A carpenter is laying a wood floor measuring 4 yd by 5 yd. How many square feet of flooring material does she need? Step 1: Convert yards to feet. Step 2: Solve. A = l w A= 4 (3) x 5 (3) A= 12 x 15 The carpenter needs 180 ft2 of flooring material.
A carpenter is laying a tile floor measuring 5 yd by 7 yd. How many square feet of tile material does she need? 5 yd L x W= A 7 yd 7 (3) x 5 (3) = A 21 x 15 = A The carpenter needs 315 ft2 of tile material.
105 8 1 8 in2 or 13 57 2 = 1 2 ft2 28 Lesson Quiz: Part I Find the area of each figure. 1. 2. 24.5 ft2 4.