1 / 1

Mohr’s circle can be used to graphically determine : a) the principle axes and principle moments of inertia of the area

Mohr's Circle for Moment of Inertia. Mohr’s circle can be used to graphically determine : a) the principle axes and principle moments of inertia of the area about O b) the moment and product of inertia of the area with respect to any other pair of rectangular axes x’ and y’ through O.

sherri
Download Presentation

Mohr’s circle can be used to graphically determine : a) the principle axes and principle moments of inertia of the area

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Mohr's Circle for Moment of Inertia Mohr’s circle can be used to graphically determine: a) the principle axes and principle moments of inertia of the area about O b) the moment and product of inertia of the area with respect to any other pair of rectangular axes x’ and y’ through O • Graphical Solution Path • On x-axis C=(Ix+Iy)/2 • R={[(Ix-Iy)/2)^2]+Ixy^2}^(1/2) • Imax=A=C+R & Imin=B=C-R • Plot points (Ix, Ixy) & (Iy, -Ixy), and draw a line to illustrate original moment of inertia. • Proceed with analysis as in Mohr’s circle for stress to find Ix’, Iy’ and Ix’y’ at different angles. Algebraic Solution Equations Ix=Moment of inertia about x axis Iy=Moment of inertia about y axis Ixy=Product of inertia I’x = Ix cos2 θ + Iy sin2 θ – 2 Ixy sin θ cos θ I’x = Ix sin2 θ + Iy cos2 θ + 2 Ixy sin θ cos θ I’xy = Ixy cos2 θ + 0.5 ( Ix – Iy ) sin 2θ Poster by: Rosanna Anderson, Jared McCombs, and Mike Thompson

More Related