1 / 17

Log Equations Review

Log Equations Review. OBJ: Review for Quest 2. 1. 16 2 – s 2 = ½ 2 4(2 – s 2) = 2 -1 4(2 – s 2 ) = -1 8 – 4s 2 = -1 9 – 4s 2 = 0 (3 – 2s)(3 + 2s) = 0 s =  . 2. 64 x – 4 = (½) 2x 2 6(x – 4 ) = (2 -1 ) 2x 6(x – 4) = (-1)2x 6x – 24 = -2x 8x = 24 x = 3. Solve.

sorley
Download Presentation

Log Equations Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Log Equations Review OBJ: Review for Quest 2

  2. 1.162 – s 2= ½ 24(2 – s 2) = 2-1 4(2 – s2) = -1 8 – 4s2 = -1 9 – 4s2 = 0 (3 – 2s)(3 + 2s) = 0 s =  2.64x – 4 = (½)2x 26(x – 4 ) = (2-1)2x 6(x – 4) = (-1)2x 6x – 24 = -2x 8x = 24 x = 3 Solve

  3. 3.()2x = 64 27 ()2x = ()-3 2x = -3 x = -  4.63x + 5 = 1 60 = 1 3x + 5 = 0 x = -5 3 Solve

  4. log5125 = x 5x = 125 5x = 53 x = 3 5.log2 t = 6 26 = t (2½)6 = t 23 = t 8 = t Solve

  5. 6.log2x3 = 6 26 = x3 (26) = (x3) 22 = x 4 = x log24 + log26= log2x log224 = log2x 24 = x Solve

  6. log310-log35=log3x log310 = log3x 5 log32 = log3x 2 = x 7.log4(5x – 1) = 3 43 = 5x – 1 64 = 5x – 1 65 = 5x 13 = x Solve

  7. 8.log(x2 + 21x) = 2 (base 10) 102 = x2 + 21x 100 = x2 + 21x 0 = x2 + 21x – 100 0 = (x + 25)(x – 4) x = 4, -25 2=log3(t2 – 3t + 5) 32 = t2 – 3t + 5 9 = t2 – 3t + 5 0 = t2 – 3t – 4 0 = (t – 4)(t + 1) t = 4, -1 Solve

  8. 2log23–log2(x + 1)=3 log2( 32 ) = 3 x+1 23 = ( 32 ) x+1 8 = 9_ x+1 8x + 8 = 9 8x = 1: x = ⅛ 9.log(x+5) – log(3x) = log(x+1) log(x+5) = log(x+1) 3x x + 5 = x + 1 3x 3x2 +3x = x + 5 3x2 + 2x – 5 = 0 (3x + 5)(x – 1) = 0; x=1 Solve

  9. 10.log(n+4) =1–log(2n) log(n+4) +log(2n)=1 log10(n+4)(2n) = 1 101 = (n + 4)(2n) 2n2 + 8n – 10 = 0 2(n2 + 4n – 5) = 0 2(n + 5)(n – 1) = 0 n = 1 Solve

  10. 1.2x = 5 log2x = log5 x log2 = log5 x = log5 log2 x = log(5)/log(2) x = 2.322 2.35 – x = 100 log35 – x = log100 (5 – x)log3= log100 5log3-xlog3=log100 5log3-log100= xlog3 (5log(3)-log(100)) /log(3) x = .808 Solve. Round answers to 3 dec. places

  11. 3.log2x +1 = log31 – x (x + 1)log2 = (1 – x)log3 xlog2+1log2=1log3-xlog3 xlog2+xlog3 = log3–log2 x(log2+log3) = log3–log2 log3 – log2 = x log2 + log3 (log(3) – log(2))/(log(2) + log(3)) = x .226 = x Solve. Round answers to 3 dec. places

  12. 4.ex = 5 log ex = log 5 x log e = log 5 x = log 5 log e x = 1.609 Solve. Round answers to 3 dec. places

  13. 3e2x – 1 = 12 e2x – 1 = 4 log e2x – 1 = log 4 (2x – 1) log e = log4 2xlog e-log e = log4 x = log e + log 4 2 log e = 1.193 Solve. Round answers to 3 dec. places

  14. 72x + 1 = 11 log72x + 1 = log 11 (2x + 1)log7= log11 2xlog7+log7=log11 2xlog7=log11–log7 x = log11 – log7 2log7 x = .116 Solve. Round answers to 3 dec. places

  15. 5.log 5 x +3 = log 3 2 – x (x + 3)log5=(2 – x)log3 xlog5+3log5=2log3–xlog3 xlog5+xlog3=2log3–3log5 x(log5+log3)=2log3–3log5 2log3 – 3log5 = x log5 + log 3 -.972 = x 6.log2s = 1.3 21.3 = s 2.462 = s To do it on the calculator, type 2 Λ1.3 The “Λ” key is above the “” key Solve. Round answers to 3 dec. places

  16. 7.log812 = x 8x = 12 xlog8= log12 x = log12 log8 x = log(12)/log(8) x = 1.195 8.log53.6 = x 5x = 3.6 xlog5 = log3.6 x = log3.6 log5 x = log(3.6)/log(5) x = .796 Solve. Round answers to 3 dec. places

  17. 9.log1.26 = x 1.2x = 6 xlog1.2 = log6 x = log6 log1.2 x = 4.914 10.log27 = x x = 27 3-x = 3 x = - Solve. Round answers to 3 dec. places

More Related