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Genetics Review Powerpoint. MENDEL’S PEA EXPERIMENTS. P 1 = Parental. F 1 = Filial (pffspring). F 2 = Filial (pffspring). http://hus.yksd.com/distanceedcourses/YKSDbiology/lessons/FourthQuarter/Chapter11/11-1/images/MendelExperiment.gif. Refresh your “Bio Brain” about: GENETICS VOCAB
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MENDEL’S PEA EXPERIMENTS P1 = Parental F1 = Filial (pffspring) F2 = Filial (pffspring) http://hus.yksd.com/distanceedcourses/YKSDbiology/lessons/FourthQuarter/Chapter11/11-1/images/MendelExperiment.gif
Refresh your “Bio Brain”about: GENETICS VOCAB DOMINANT: RECESSIVE: HOMOZYGOUS (pure-breeding): HETEROZYGOUS (hybrid): GENOTYPE: PHENOTYPE:
Refresh your “Bio Brain” about: GENETICS VOCAB DOMINANT: RECESSIVE: gene that hides anotherrepresented by capital letter gene that is hidden by anotherrepresented by lower case letter
Refresh your “Bio Brain” about: GENETICS VOCAB HOMOZYGOUS (pure-breeding): HETEROZYGOUS (hybrid): Organism with two identical alleles for a gene TT OR tt Organism with two different alleles for a gene Tt
Refresh your “Bio Brain” about: GENETICS VOCAB GENOTYPE: PHENOTYPE: Genetic make up of an organism “What genes it has” Appearance of an organism “Way it looks”
Probability is the likelihood that an event will occur It can be written as a: Fraction ____ Percent ____ Ratio ____ 1/4 25% 1:3
http://www.arborsci.com/CoolStuff/CoinFlip.jpg COIN FLIP There are 2 possible outcomes: HEADS TAILS The chance the coin will land on either one is: ____ ____ ____ Alleles segregate randomly just like a coin flip. . . So can use probability to predict outcomes of genetic crosses. 1/2 1:1 50% NOT 1:2!
IN PEAS: R = round T = tall Y = yellow peas P = purple flowers r = wrinkled t = short y = green peas p = white flowers
Make a cross between a HOMOZYGOUS ROUND pea plant X PURE-BREEDING WRINKLED pea plant Show probabilities for: genotypes and phenotypes of possible offspring R R GENOTYPE PHENOTYPE ____________ ___________ _______ show dominant phenotype _______ show recessive phenotype Rr r r ROUND Rr Rr Rr Rr 100% 4/4 0% 0/4
Make a cross between a HOMOZYGOUS TALL pea plant X HOMOZGYOUS SHORT pea plant Show probabilities for: genotypes and phenotypes of possible offspring T T GENOTYPE PHENOTYPE ____________ ___________ _______ show dominant phenotype _______ show recessive phenotype Tt t t TALL Tt Tt Tt Tt 100% 4/4 0% 0/4
WHAT’s THE PATTERN? HOMOZYGOUS DOMINANT pea plant X HOMOZGYOUS RECESSIVE pea plant DO ONE IN YOUR HEAD HOMOZYGOUS PURPLE FLOWER X HOMOZGYOUS WHITE FLOWER pea plants ALL Pp 100% PURPLE FLOWERS 0% WHITE FLOWERS
IN PEAS: R = round T = tall Y = yellow peas P = purple flowers r = wrinkled t = short y = green peas p = white flowers
Make a cross between a HETEROZYGOUS YELLOW pea plant X HYBRID GREEN pea plant Show probabilities for: genotypes and phenotypes of possible offspring GENOTYPE PHENOTYPE ____________ _______________________ _______________________ ___________ _______ show dominant phenotype _______ show recessive phenotype _________ phenotypic ratio Y y YY YELLOW Yy YELLOW Y y YY Yy Yy yy yy GREEN 75% 3/4 25% 1/4 3:1 1:2:1 ____________ genotypic ratio
Make a cross between a HETEROZYGOUS TALL pea plant X HETEROZYGOUS SHORT pea plant Show probabilities for: genotypes and phenotypes of possible offspring GENOTYPE PHENOTYPE ____________ _______________________ _______________________ ___________ _______ show dominant phenotype _______ show recessive phenotype _________ phenotypic ratio T t TT TALL Tt TALL T t TT Tt Tt tt tt SHORT 75% 3/4 25% 1/4 3:1 1:2:1 ____________ genotypic ratio
WHAT’s THE PATTERN? HOMOZYGOUS DOMINANT pea plant X HOMOZGYOUS RECESSIVE pea plant DO ONE IN YOUR HEAD HOMOZYGOUS PURPLE FLOWER X HOMOZGYOUS WHITE FLOWER pea plants ______ PURPLE?______ WHITE? _____ PP? _____ Pp? _____ pp? _________ genotypic ratio _______ phenotypic ratio 75% 25% 25% 50% 25% 1:2:1 3:1
POSSIBLE PARENT GAMETES? __________________________ INDEPENDENT ASSORTMENT
POSSIBLE PARENT GAMETES? TTRR ________________________ TR TR TR TR INDEPENDENT ASSORTMENT
POSSIBLE PARENT GAMETES? ttrr ________________________ tr tr tr tr INDEPENDENT ASSORTMENT
TR TR TR TR tr tr tr tr GENOTYPE _____________ PHENOTYPE ____________ TrRr TrRr TrRr TrRr TtRrTtRr TtRr TtRr TtRr TtRr TtRr TtRr TtRrTtRr TtRr TtRr TtRr TALL & ROUND
POSSIBLE PARENT GAMETES? TtRr ________________________ TR tR tr Tr INDEPENDENT ASSORTMENT
POSSIBLE PARENT GAMETES? RrYy ________________________ RY rY ry Ry INDEPENDENT ASSORTMENT
RY Ry rY ry RY Ry rY ry ____ Round & Yellow ____ Round & green ____ Wrinkled & yellow ____ wrinkled & green
RY Ry rY ry RY Ry rY ry ____ Round & Yellow ____ Round & green ____ Wrinkled & yellow ____ wrinkled & green RRYY RRYy RrYY RrYy RRYy RRyy RrYy RryyRrYY RrYy rrYY rrYy RrYy Rryy rrYy rryy
RY Ry rY ry RY Ry rY ry ____ Round & Yellow ____ Round & green ____ Wrinkled & yellow ____ wrinkled & green 9 RRYYRRYyRrYY RrYy RRYy RRyy RrYy RryyRrYY RrYyrrYY rrYy RrYyRryy rrYyrryy 3 3 1 Sign of HETEROZYGOUS DIHYBRID cross What’s the pattern?
9 ____ ____________ TRAIT 1 ; ____________ TRAIT 2 ____ ____________ TRAIT 1; _____________ TRAIT 2 ____ ____________ TRAIT 1; _____________ TRAIT 2 ____ ____________ TRAIT 1; _____________ TRAIT 2 dominant dominant 3 dominant recessive 3 recessive dominant 1 recessive recessive __________ratio is a clue that it’s a ____________________________cross 9:3:3:1 HETEROZYGOUS TWO gene
NON-MENDELIAN INHERITANCE INCOMPLETEDOMINANCE COMPLETEDOMINANCE F2 generation- Not a 3:1 ratio Heterozygote= blended intermediate phenotype http://www.emc.maricopa.edu/faculty/farabee/BIOBK/BioBookTOC.html
NON-MENDELIAN INHERITANCE CO-DOMINANCE HETEROZYGOTE: Both traits are expressed together (NO BLENDING) Roan horse has BOTH red & whitehair (NOT A PINK HORSE! An A allele AND a B allele make BOTH A and B GLYCOPROTEINS= AB Blood type
Make a cross between TWO HETEROZYGOUS ROAN HORSES Show probabilities for: genotypes and phenotypes of possible offspring GENOTYPE PHENOTYPE ____________ _______________________ _______________________ ___________ _________ phenotypic ratio R W RR RED 25% 1/4 RW 50% 1/2 ROAN R W WW WHITE RR RW RW WW 25% 1/4 1:2:1 1:2:1 ____________ genotypic ratio
Make a cross between a HOMOZYGOUS RED HORSE and HOMOZYGOUS WHITE HORSE Show probabilities for: genotypes and phenotypes of possible offspring R R GENOTYPE PHENOTYPE ____________ ___________ _________ ROAN offspring W W RW RW RW RW RW ROAN 100%
NON-MENDELIAN INHERITANCE ALLELES: ____ ____ ____ BLOOD TYPE MULTIPLE ALLELE TRAIT & CODOMINANT TRAIT _____ allele is dominant to _____ allele._____ allele is dominant to _____ allele._____ and _____ are CODOMINANT. BOTH SHOW TOGETHER
NON-MENDELIAN INHERITANCE B A O ALLELES: ____ ____ ____ BLOOD TYPE MULTIPLE ALLELE TRAIT & CODOMINANT TRAIT A O _____ allele is dominant to _____ allele._____ allele is dominant to _____ allele._____ and _____ are CODOMINANT. BOTH SHOW TOGETHER O B A B
SEX-LINKED GENES Some genes are carried on SEX chromosomes X-linked recessive disorders:HemophiliaColor blindnessDuchenne Muscular Dystrophy XX= ________________XY = ________________ X-linked traits show up more frequently in malesNo backup X to cover for the “broken” gene FEMALES MALES
X-LINKED Cross a colorblind male with a normal vision (non-carrier) female Xc Y PHENOTYPE100% normal vision 50% normal males 50% carrier females XCXc XCY XCXc XCY XC XC
X-LINKED Cross a hemophilia male with a carrier female Xh Y PHENOTYPE 25%- hemophilia female25%- hemophilia male 25%- normal male 25% - normal (carrier) females XHXh XHY XhXh XhY XH Xh
TEST CROSSESDominant looking parent could have these genotypes: ________ OR __________ Can’t tell which by looking. Test cross used to determine which it is.ALWAYS TESTCROSS WITH A _________________________________Offspring provide clue about genotype of unknown parent. TT Tt HOMOZYGOUS RECESSIVE
TEST CROSSES T T T t tt t t Tt Tt Tt Tt Tt ttTt tt 50% will be TALL 50% will be SHORT All offspring will be TALL If any offspring show the recessive trait . . . unknown parent genotype was ________. If all offspring show the dominant trait . . . still don’t know. BOTH genotypes could produce offspring that look dominant! Tt
Deafness in dogs is caused by a recessive allele. Deaf dogs have the genotype dd. You have a hearing dog. Do a test cross to determine its genotype. D d D D dd Dd Dd Dd Dd d d Dd dd Dd dd An actual test cross results in a litter with: 5 hearing puppies 0 deaf puppies What can you conclude?
Firebreathing (F) in dragons is dominant over NON-firebreathing (f). You have a fire-breathing dragon. What possible alleles could the fire-breathing parent have? _______ OR ________ EXPLAIN how you could use a TEST CROSS to help determine the parental genotype. Show the results of test crossing BOTH OF THE POSSIBLE PARENT GENOTYPES: An actual test cross results in a litter with: 6 firebreathing dragons 1 NON-firebreather EXPLAIN how you could use these results to determine the correct parental genotype.
TEST CROSS Used to determine genotype of unknown DOMINANT LOOKING parent Always cross with HOMOZYGOUS RECESSIVE (EX: tt)Observe offspring-If any offspring show recessive trait… know parent was HETEROZYGOUSIf all offspring show DOMINANT trait . . .Still don’t know genotype. Do another test cross.Both TT and Tt can produce tall offspring with tt cross
DRAGONS An actual test cross results in a litter with: 6 firebreathing dragons 1 NON-firebreather F f F F f f Ff Ff Ff Ff f f Ff ff Ff ff What can you conclude? Unknown parent genotype is FfOnly way you can get a NON-FIREBREATHER
Write a NULL hypothesis that describes the mode of inheritance for the trait (purple eyes) I would expect this pattern in the F1 offspring _______________________________ I would expect this pattern in the F2 offspring ________________________________ THERE IS NO DIFFERENCE BETWEEN THE OBSERVED DATA AND THE EXPECTED DATA IF PURPLE EYES IS A(N) _________________ ____________ TRAIT
+ p p p +p +p +p +p ++ +p +p pp + p + + F1 100% wild type F2 75% wild type 25% purple eyed IF YOU IGNORE SEX:If 1000 flies, expect 750 to be wild type and 250 to be purple eyed If you DON’T IGNORE SEX: 375 WT MALES 125 purple eyed MALES 375 WY FEMALES 125 purple eyed FEMALES Calculate Chi-squareDO YOU ACCEPT OR REJECT THE NULL HYPOTHESIS?
H0- There is no difference between the frequencies observed and the frequencies expected if PURPLE eyes is an autosomal recessive trait.
IF GENE is AUTOSOMAL and RECESSIVE TO + MALES:FEMALES 1:1 m m + + +m +m +m +m F1 All = +m (wildtype) + m + m F2 ¼ = ++ 75% wildtype ½ = +m ¼ = mm 25% mutant 3:1 ++ +m +m mm http://www.exploratorium.edu/exhibits/mutant_flies/curly-wings.gif
IF GENE is AUTOSOMAL and DOMINANT TO + MALES:FEMALES 1:1 M M + + +M +M +M +M F1 All = +M (mutant) + M + M F2 ¼ = ++ 25% wildtype ½ = +M ¼ = MM 75% mutant 1:3 ++ +M +M MM
IF GENE is X-linked recessive Different pattern if gene is inherited from mom or dad Mutant mom X wild type dad F1 Xm y X+ Xm F1 X+ y Xm Xm X+Xm X+y XmXm Xmy X+Xm Xmy X+Xm Xmy 25% normal females25% mutant females 25% mutant males25% normal males 50% normal females 50% mutant males When using Virtual fly labChoose ignore sex and see if it changes the ratios
POSSIBLE PARENT GAMETES? RrYy ________________________ RY rY ry Ry INDEPENDENT ASSORTMENT