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Warm up

Preliminary Activity. Notes. For Fun. Warm up. Activity. Scientific Notation and Order of Operations. Back. Back. Multiply these numbers together and call out the answer. http://jamit.com.au/htmlFolder/app1010.html. Back. Back. Scientific Notation

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Warm up

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  1. Preliminary Activity Notes For Fun Warm up Activity Scientific Notation and Order of Operations

  2. Back Back Multiply these numbers together and call out the answer http://jamit.com.au/htmlFolder/app1010.html

  3. Back Back Scientific Notation Scientific notation is always written in 3 parts. Part 1. a number between 1 and less than 10 Part 2. multiply by 10 Part 3. an index on the 10 to indicate the movement of the decimal point Examples 1. Write 345 000 000 in scientific notation 3.45 x 108 2. Write 0.000 000 000 000 000 9 in scientific notation 9 x 10-16

  4. Back Back Questions 1. Write the normal number for: a) 3 x 10-4 b) 9 x 10-5 c) 8 x 107 d) 4 x 102 2. Write these numbers in Scientific Notation a) 0.000 037 b)0.584 c) 79 000 d) 19 620 000 0.000 4 0.000 09 80 000 000 400 3.7 x 10-5 5.84 x 10-1 7.9 x 104 1.962 x 107

  5. Back Back Questions 1. The star nearest the Earth is approximately 41 600 000 000 000 kilometres from the sun. Write the distance in scientific notation. 2. A micron is one-millionth of a metre. Write 3 microns as a decimal of a metre, using scientific notation. 3. Round the following a) 2.706 x 10-3 to 3 significant figures b) 1.8326 x 10-9 to 2 significant figures 4. Evaluate the following, give your answers in scientific notation to 3 significant figures. a) (3.8 x 106) x (5.75 x 103) b) 3.166 x 103) ÷ (8.49 x 10-2) c) d) 4.16 x 1013 3 x 10-6 2.71 x 10-3 1.8 x 10-9 2.19 x 1010 3.73 x 104 3.67 x 109 8.11 x 10-3

  6. Back Back 5. Using the correct order of operations evaluate the following a) 8 + (4 x 6) b) 30 - [12 ÷ (4 ÷ 4)] c) 56 ÷ [(4 x 6) - (2 x 8)] d) 9 x 2 13 - 7 e) 33 (3 x 7) - 10 f) 15 + (9 x 3) 15 - 8 g) h) 6. The symbol for absolute value, I I , also acts as a grouping symbol. The absolute value of a number is its numerical value without regard to sign. Ι7I = 7 and I-7I = 7 Solve a) I15 - 7I b) I9 - 14I c) I7 - 13I + 6 d) I9 - 15I x I3 x (5 - 2)I 32 18 7 3 3 6 2.9 x 108 8.1 x 10-3 8 5 12 54

  7. Back Back End of topic 1 - well done! You should go onto Mathletics and Maths on line to complete this chapter in each.

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