1 / 17

Do Now – #1 and 2, Quick Review, p.328

Do Now – #1 and 2, Quick Review, p.328. Find dy /dx:. 1. 2. Integration by Parts. Section 6.3a. To “integrate by parts,” we first need to investigate the…. Product Rule in Integral Form. If u and v are differentiable functions of x , the Product Rule for differentiation gives:.

tavia
Download Presentation

Do Now – #1 and 2, Quick Review, p.328

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Do Now – #1 and 2, Quick Review, p.328 Find dy/dx: 1. 2.

  2. Integration by Parts Section 6.3a

  3. To “integrate by parts,” we first need to investigate the… Product Rule in Integral Form If u and v are differentiable functions of x, the Product Rule for differentiation gives: Next, let’s rearrange the terms a bit:

  4. To “integrate by parts,” we first need to investigate the… Product Rule in Integral Form Now, integrate both sides with respect to x:

  5. To “integrate by parts,” we first need to investigate the… Product Rule in Integral Form Writing this equation in simpler differential notation yields the Integration by Parts Formula:

  6. Integration by Parts Formula This formula expresses one integral in terms of a second integral. With proper choices for u and v, this second integral will be easier to evaluate…a very useful technique (but note: it doesn’t always work…)

  7. Integration by Parts Formula A bit of wisdom from your textbook’s authors: • We want u to be something that simplifies when differentiated. • We want v to be something “managable” when integrated. • When choosing u, use L I P E T for order preference: Natural Logarithm (L)  Inverse Trig Function (I)  Polynomial (P)  Exponential (E)  Trig Function (T)

  8. Guided Practice Evaluate Keep the formula in mind!!! Let Let Then Then The original integral is transformed:

  9. Guided Practice Evaluate What if we had made different choices for u and v? Let Let A poor choice, since we still don’t know how to integrate dv to obtain v…

  10. Guided Practice Evaluate What if we had made different choices for u and v? Let Let Then Then The new integral: …is worse than the original!!!

  11. Guided Practice Evaluate What if we had made different choices for u and v? Let Let Then Then The new integral: …is also a stinker!!!

  12. Guided Practice Evaluate Now, differentiate to confirm your answer!

  13. Guided Practice Evaluate Let Now we integrate by parts with this new integral!!! This is an example of repeated use of I.B.P…

  14. Guided Practice Evaluate Let

  15. Guided Practice Evaluate This technique works with integrals in the form in which f can be differentiated repeatedly to zero, and g can be integrated repeatedly without difficulty…

  16. An alternative to the long-cut is to use tabular integration in such situations: f(x) and its derivatives g(x) and its integrals ( + ) ( – ) ( + )

  17. Guided Practice Tabular integration: Evaluate: f(x) and its derivatives g(x) and its integrals (+) (–) (+) (–)

More Related