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Kyla, Maurice, Amari , Deja , Demarcus , Twylah see me. Do p. 86-88 25 , 45, 65 , 79 . Review Class assignment. Objectives: By the end of class, students will be able to: Solve equations with one or more steps. with 90% or above mastery. Lesson 2-3 Equations. 13. – 34 = 6m – 4
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Do p. 86-88 25, 45, 65, 79 Review Class assignment
Objectives: By the end of class, students will be able to: • Solve equations with one or more steps. with 90% or above mastery. Lesson 2-3 Equations
13. – 34 = 6m – 4 +4 +4 Add 4 on both sides -30 = 6m 6 6 Divide 6 on both sides -5 = m p. 94
15. y - 6 = 8 5 + 6 +6 Add 6 on both sides y = 14 5 (5)y = 14 (5) Multiply 5 on both sides 5 y = 70
19. n – 2 = 2 7 (7) n – 2 = 2 (7) Multiply 7 on both sides 7 n – 2 = 14 +2 + 2 n = 16
23. Financial Literacy: Important Facts Raul chose the business plan and has budgeted $100 per month. Write an equation for this situation, and determine how many minutes per month he can use the phone and stay within budget. Let m = number of minutes per month .15m + 49.99 = 100.00 - 49.99 - 49.99 .15m = 50.01 .15 .15 m = 333.40 650 + 333 = 983 minutes Raul can use 983 minutes.
Do p. 93 1 - 5, 7 and 8 On the white boards Class Assignment
27. Find three consecutive odd integers whose sum is 57. Let n = the smallest consecutive odd integer Let n + 2 = the next largest odd integer Let n + 4 = the largest consecutive odd integer n + (n + 2) + (n + 4) = 57 3n + 6 = 57 - 6 -6 3n = 51 3 3 n = 17 the smallest odd integer So, 17, 19, 21 are three consecutive odd integers whose sum is 57. Number Theory
40. Family: The ages of 3 brothers are consecutive integers with the sum of 96. Let n = the smallest consecutive integer Let n + 1 = the next largest consecutive integer Let n + 2 = the largest consecutive integer n + (n + 1) + (n + 2) = 96 3n + 3 = 96 - 3 -3 3n = 93 3 3 n = 31 the youngest age So, 31, 33, and 35 are the brother’s ages.
Do p. 93 #9, 10 P. 102 Do 48 Class Assignment
1. p. 102 #52 2. p. 102 #53 Exit Slip