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NUCLEAR REACTION. CHAPTER 27: Nuclear reaction (3 Hours). 27.1 Nuclear reaction 27.2 Nuclear fission and fusion. Learning Outcome:. 27.1 Nuclear reaction ( 1 hour). At the end of this chapter, students should be able to:
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NUCLEAR REACTION CHAPTER 27: Nuclear reaction(3 Hours) 27.1 Nuclear reaction 27.2 Nuclear fission and fusion
Learning Outcome: 27.1 Nuclear reaction (1 hour) At the end of this chapter, students should be able to: • Statethe conservation of charge (Z) and nucleon number (A) in a nuclear reaction. • Write and completethe equation of nuclear reaction. • Calculatethe energy liberated in the process of nuclear reaction
a) Radioactive decay. c) Nuclear fission. d) Nuclear fusion. 27.1 Nuclear reaction Examples: b) Induced nuclear reaction (particle bombardment).
27.1 Nuclear reaction • In any nuclear reaction, several conservation laws • must be obeyed, primaryly conservation of • charge and conservation of nucleons. Conservation of charge (atomic number Z) Conservation of mass number A (nucleon)
Reaction energy Q • Reaction energy is the energy released (absorbed) • in a nuclear reaction in the form of kinetic energy • of the particle emitted, the kinetic energy of the • daughter nucleus and the energy of the gamma- • ray photon that may accompany the reaction. Reaction energy ,
Note: Δm = mi - mf a) If Δm or Q> 0 (positive value) - exothermic (exoergic) reaction. - energy is released. b) If Δm or Q< 0 (negative value) - endothermic (endoergic) reaction. - energy is required/absorbed in the form of kinetic energy of the bombardment particle. Other reference : Δm = mf – mi Δm →negative (energy is released) Δm →positive (energy is absorbed)
Example 27.1 Complete and state the type of reaction in the following nuclear reactions. Natural/decaying Fusion Fission
Example 27.2 When lithium 7Li is bombarded by a proton, two alpha 4He particles are produced. Calculate the reaction energy. Given
c2 or
Example 27.3 A deuterium bombards a 136C nuclide and produces 147 N nuclide. a) Write an equation for the nuclear reaction. b) Calculate the kinetic energy (in MeV) that is released in the reaction.
Solution 27.3 a) b) Kinetic energy is released
Example 27.4 Q= 15.67 MeV A nuclear reaction can be written as . Calculate the energy involved in the reaction and state whether it is absorbed or released.
emitted particle new nucleus (daughter nucleus) Target nucleus (parent nucleus) bombarding particle
Learning Outcome: 27.2 Nuclear fission and fusion (2 hour) At the end of this chapter, students should be able to: • Distinguishthe processes of nuclear fission and fusion. • Explainthe occurrence of fission and fusion using the graph of binding energy per nucleon. • Explainchain reaction in nuclear fission of a nuclear reactor. • Describethe process of nuclear fusion in the sun.
27.2 Nuclear fission and fusion • Nuclear fission is the process by which heavy • nuclei are split into two lighter nuclei. • Energy is released by the process because the • average binding energy per nucleon of the • fission products is greater than that of the parent. • The energy released is in the form of increased • kinetic energy of the product particles • (neutrons) and any radiation emitted (gamma ray).
27.2 Nuclear fission and fusion • Nuclear fission can be divided into two ways • of processes : • spontaneous fission -very rarely occur • (take very long time) • ii) induced fission – heavy nucleus is bombarded by a particle : proton, alpha particle and neutron (slow neutrons or thermal neutrons of low energy (about 10-2 eV).
27.2 Nuclear fission and fusion • Example : is bombarded by a slow neutron. Nucleus in the excited state. (unstable) (10-12 s)
27.2 Nuclear fission and fusion • Other possible reactions are: • Figure X is a graph of the distribution of fission • fragments (daughter nuclei) from the fission of • uranium-235 versus mass number A. • Most of the fission fragments (daughter nuclei) • of the uranium-235 have mass numbers from 90 • to 100 and from 135 to 145.
Greatest stability Binding energy per nucleon (MeV/nucleon) Mass number A Binding energy per nucleon as a function of mass number,A daughter nuclei parent nuclei fission Moving toward more stable nuclei Figure Y
An estimate of the energy released in a fission • reaction can be obtained by considering the graph in • Figure Y. • From the Figure Y, the binding energy per nucleon • for uranium is about 7.6 MeV/nucleon, but for • fission fragment (Z~100), the average binding • energy per nucleon is about 8.5 MeV/nucleon. • Since the fission fragments are tightly bound, they • have less mass. • The difference in mass (or energy) between the • original uranium nucleus and the fission fragments • is about 8.5 -7.6 = 0.9 MeV per nucleon. Since there • are 236 nucleons involved in each fission, the total • energy released is
Example 27.5 Calculate the energy released (MeV) in the following fission reaction :
Example 27.6 Calculate the energy released when 10 kg of uranium-235 undergoes fission according to Given:
Solution 27.6 The energy released for one atom.
Solution 27.6 235x10-3 kg of 235U contains 6.02 x 1023 atoms. 10 kg of urainum-235 contains ; The energy released for 10 kg 235U ,
Chain Reaction in nuclear fission of a nuclear reactor. • Chain reaction is a series of nuclear fissions • whereby some of the neutrons produced by • each fission cause additional fissions. • Conditions to achieve chain reaction in a nuclear • reactor : • a) Slow neutrons are better at causing fission. • b) The fissile/fission material must more than a • critical size/mass (a few kg). • The critical size/mass is defined as the minimum • mass of fissile/fission material required to • produce a sustained chain reaction.
B A n n n n A : If the amount of uranium is less than critical mass, most neutrons escape before additional fissions occur, and the chain reaction is not sustained. B : If the amount of uranium exceeds the critical mass, a sustained chain reaction is possible.
Chain Reaction in nuclear fission of a nuclear reactor. • A nuclear reactor is a device in which energy is • generated by a controlled fission chain reaction. • Apart from being used to obtain energy from the • reaction of fission, a reactor is widely applied, for • example to generate : • - radioactive elements, • - new fissile materials, such as 233U or 239Pu, • - neutrons for scientific research.
movable Moderator (water)
A nuclear reactor consists of fuel rods (fission • material), movable control rods and a moderator • (water). • Fission reactors use a combination of 235U and • 238U (3-5% 235 U). • The 235U will fission, while the 238U(more stable) • merely absorbs neutrons (slow neutrons). • Firstly, neutron is bombarded to the 235U and other • neutrons are emitted during fission. • Then the emitting neutrons with high energy are • slowed down by collisions with nuclei in the • surrounding material, called moderator, so that they • can cause further fissions and produce more • energy.
In order to release energy at a steady rate, the rate • of the reaction is controlled by inserting or • withdrawing control rods made of elements (often • cadmium) whose nuclei absorb neutrons without • undergoing any additional reaction. • To have a self-sustaining chain reaction, the mass of • fission material must be sufficiently large (> critical • mass) so that on the average at least one neutron • produced in each fission must go on to produce • another fission.
Nuclear Fusion • Nuclear fusion is the process in which nuclei of • light elements combine to form nuclei of heavier • elements. • The energy released in this reaction is called • thermonuclear energy. • Examples ; • The amount of energy released by this process • can be estimated by using the binding energy per • nucleon curve (Figure Y).
Greatest stability Binding energy per nucleon (MeV/nucleon) Mass number A Binding energy per nucleon as a function of mass number,A Moving toward more stable nuclei fusion Figure Y
From Figure Y, the binding energy per nucleon for • the lighter nuclei (2H) is small compared to the • heavier nuclei. • The energy released per nucleon • in the fusion process is given by the difference • between two values of binding energy per nucleon. • And it is found that the energy released per nucleon • by this process is greater than the energy released • per nucleon by fission process.
Example 27.8 A fusion reaction occur as follows : • If 2 kg 2H is used, determine • Total mass loss after fusion • Energy released per helium nucleus obtained. • Total energy produced. • Given : mass of 21H = 2.014 u, • mass of 42 He = 4.002 u
Solution 27.8 Δm = mbefore –mafter Δm = 2(2.014)-4.002 Δm = 0.026 u a) The mass loss after fusion for 2 2H nuclei is 0.026 u. Number of nucleus for 2 kg 2H is, Total mass loss after fusion
Solution 27.8 b) Energy released per helium nucleus obtained, Q = 3.88 x10-12 J c) Total energy produced, Q= Δmc2 =(0.013)(3x108)2 =1.17x1015 J
For two nuclei to undergo fusion, they must come • together to within the range of the nuclear force, • typically of the order of 2 x 10-15 m. • To do this, they must overcome the electrical • repulsion of their positive charges. • For two protons at this distance, the corresponding • potential energy is about 1.2 x 10-13 J or 0.7 MeV; • this represents the total initial kinetic energy that • the fusion nuclei must have, for example, 0.6 x 10-13J • each in head-on collision. • Atoms have this much energy only at extremely • high temperature (108 K).
The lower border of the fusion temperature is 107 K. • Reactions that required such extremely high • temperature are called thermonuclear reactions. • The most important thermonuclear reactions • occurs in stars, such as our own sun.
Nuclear Fusion in the Sun • Nuclear fusion occurs in the interior of the sun • because the temperature of the sun is very high • (approximately 1.5 x 107K). • The energy radiated by the sun comes from deep • within its core, where the temperature is high • enough to initiate the fusion process. • One group of reactions thought to occur in the sun is • the proton-proton cycle, which is a series of • reactions whereby 6 protons form one helium • nucleus, 2 positrons, 2 gamma-rays, 2 protons • and 2 neutrinos.
The sequence of fusion reactions are shown below ; neutrino i) Positron (beta plus) ii) Gamma-ray iii) • The net result is the combination of 4 protons • to form a helium nucleus, two positrons and • two neutrinos. (consumes 6 protons but gives two • back) • The energy released by the proton-proton cycle is • about 26.7 MeV.
Comparison between nuclear Fission and nuclear Fusion Differences