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Finding the Area of Shaded Regions

Finding the Area of Shaded Regions. By Sandie Villanueva, Michelle Polanco, Helen Nguyen Christopher Herrera. Key. * = Multiplication ^ = exponents sqrt = square root pi=. Problem #1. Area of Area Area Shaded = of a - of a Region square circle A= A s – A c

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Finding the Area of Shaded Regions

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  1. Finding the Area of Shaded Regions By Sandie Villanueva, Michelle Polanco, Helen Nguyen Christopher Herrera

  2. Key * = Multiplication ^ = exponents sqrt = square root pi=

  3. Problem #1 Area of Area Area Shaded = of a - of a Region square circle A= As– Ac A = l^2 – ( pi*r^2) A=(2r)^2 – (pi*r^2) A=4r^2 – pi* r^2 A=r^2(4-pi)

  4. Problem #2 Area of Area Area Shaded = of a - of a Region rectangle circle A=Ar – Ac A = l*w – ( pi*r^2) A=2r(4r) – (pi*r^2) A=8r^2 – pi* r^2 A=r^2(8-pi)

  5. Problem #3 Area of Area Area Shaded = of a + of a Region square circle A=As + Ac A = l^2 + ( pi*r^2) A=(2r)^2 + (pi*r^2) A=4r^2 + pi* r^2 A=r^2(4+pi)

  6. Problem #4 Area of Area Area Shaded = of a - of a Region square circle A= As– Ac A = l^2 – ( pi*r^2) A=(2r)^2 – (pi*r^2) A=4r^2 – pi* r^2 A=r^2(4-pi)

  7. Problem #5 Area of Area Area Shaded = of a - of 4 Region square circle A= As– 4Ac A = l^2 – 4( pi*r^2) A=(4r)^2 – 4pi*r^2 A=16r^2 – 4pi* r^2 A=4r^2(4-pi)

  8. Problem #6 Area of Area Area Shaded = of a - of 2 Region square circle A= As– Ac A = l^2 – ( pi*r^2) A=(4r)^2 – 2(pi*r^2) A=16r^2 – 2pi* r^2 A=2r^2(8-pi)

  9. Problem #7 Area of Area Area Shaded = of a - of 2 Region circle square A= As– Ac A = l^2 – ( pi*r^2) A=(2r)^2 – (pi*r^2) A=4r^2 – pi* r^2 A=r^2(4-pi)

  10. Problem #8 Area of Area Area Shaded = of a - of 2 Region circle square A= As– Ac A = pi*r^2 – (r * sqrt2)^2 A = pi*r^2– r^2*2 A= pi*r^2 – 2r^2 A=r^2(pi-2)

  11. Problem #9 Area of Area Area Area Shaded = of a - of a + of 2 Region semicircle semicircle rectangles

  12. Problem #10 Area of Area Area Shaded = of a + of a Region semicircle rectangles A= 2pi*x^2 + 2xy A= 2x(pi*x+y)

  13. Problem #11 Area of Area Area Area Area Shaded = of big - of + of 2 + of Region circle little circle rectangles middle rectangle A=pi*r^2b – pi*r^2l + lewe – lmwm A=pi( 2r)^2 – pi*r^2 + (4r)(2r) – (2r)(2r) A=4p*ir^2 – pi*r^2 +8r^2 – 4r^2 A=3pi*r^2 +4r^2 A=r^2(3pi+4)

  14. WE BETTER GET EXTRA CREDIT Credits To Michelle Polanco Sandie Villanueva Helen Nyguen Christopher Herrera

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