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Step 1 : Write the products for both double replacement reactions

(a) NiCl 2 ( aq ) + (NH 4 ) 2 S( aq )  NiS + NH 4 Cl (b) Mn (NO 3 ) 2 ( aq ) + Na 3 PO 4 ( aq )  Mn 3 (PO 4 ) 2 + NaNO 3.

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Step 1 : Write the products for both double replacement reactions

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  1. (a) NiCl2(aq) + (NH4)2S(aq) NiS + NH4Cl (b) Mn(NO3)2(aq) + Na3PO4(aq) Mn3(PO4)2 + NaNO3 PROBLEM: Predict the products of each precipitation reaction. Balance the completed equation and then write the net ionic equation.(a) NiCl2(aq) + (NH4)2S(aq)  (b)Mn(NO3)2(aq) + Na3PO4(aq)  Step 2: Balance the reactions (a) NiCl2(aq) + (NH4)2S(aq) NiS + 2 NH4Cl (b) 3 Mn(NO3)2(aq) + 2 Na3PO4(aq)  Mn3(PO4)2 + 6 NaNO3 Step 3: Determine the precipitates – (a) sulfides are generally insoluble while halides are generally soluble. (b) phosphates are generally insoluble while nitrates are always soluble. Step 1: Write the products for both double replacement reactions (a) NiCl2(aq) + (NH4)2S(aq) NiS(s) + 2 NH4Cl(aq) (b) 3 Mn(NO3)2(aq) + 2 Na3PO4(aq)  Mn3(PO4)2(s)+ 6 NaNO3(aq) Step 4: Eliminate the spectator ions to get the net ionic equation (a) Ni2+(aq) + S2–(aq) NiS(s) (b) 3 Mn2+(aq) + 2 PO43–(aq)  Mn3(PO4)2(s)

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