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Drill: Determine the pH of 0.25 M HZ. K aHZ = 2.5 x 10 -7. Buffer Solutions. Buffer Solution. A solution that resists changes in pH. Buffer Solution. Made from the combination of a weak acid & its salt. Buffer Solution. Made from the combination of a weak base & its salt. Buffer Examples.
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Buffer Solution • A solution that resists changes in pH
Buffer Solution • Made from the combination of a weak acid & its salt
Buffer Solution • Made from the combination of a weak base & its salt
Buffer Examples • Mix acetic acid & sodium acetate • Mix ammonia & ammonium chloride
Buffer Solution • A buffer solution works best when the acid to salt ratio is • 1 : 1
Buffer Solution • A buffer solution works best when the base to salt ratio is • 1 : 1
Buffer Solution • The buffering capacity of a solution works best when the pH is near the pKa
pKa or pKb • pKa = - log Ka • pKb = - log Kb
Buffer Problems • Calculate the pH of a solution containing 0.10 M HAc in 0.10 M NaAc: Ka = 1.8 x 10-5
Buffer Problems • Calculate the pH of 0.10 M NH3 in 0.20 M NH4NO3: • Kb = 1.8 x 10-5
Buffer Problems Calculate the pH of a solution containing 0.10 M HBz in 0.20 M NaBz: Ka = 6.4 x 10-5
Buffer Problems Calculate the pH of a solution containing 0.50 M HQ in 0.10 M NaQ: Ka = 4.0 x 10-5
Drill Calculate the pH of a solution containing 0.30 M HZ in 0.10 M NaZ: Ka = 3.0 x 10-5
Lab Requirements • To make accurate measurements, we must have solutions with accurately measured concentrations
Standard Solution • A solution with known concentration • 2.004 M HCl
STD Problems Calculate the mass of KHP (MW = 204.23) required to make 1.0 L of 0.100 M KHP
Henderson-Hasselbach Eq [A-] [HA] pH = pKa + log
Henderson-Hasselbach Eq [B+] [B] pOH = pKb+ log
Buffer Problems • Calculate the salt to acid ratio to make a buffer solution with pH = 5.0 • Ka for HBZ = 2.0 x 10-5
Buffer Problems Calculate the salt to base ratio to make a buffer solution with pH = 9.48 • Kb for MOH = 2.0 x 10-5
Calculate the HCO3- to H2CO3 ratio in blood with pH = 7.40 • Ka1 for H2CO3 = 4.4 x 10-7
150 ml of 0.10 M NaOH is added to 100.0 ml of 0.10 M H2CO3. Calculate all. • Ka1 for H2CO3 = 4.4 x 10-7 • Ka2 for H2CO3 = 4.7 x 10-11