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Princess Sumaya Univ. Electronic Engineering Dept. 3442 Industrial Instruments 2 Chapter 7 Final Control. Dr. Bassam Kahhaleh. 7: Final Control. Objective
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Princess Sumaya Univ.Electronic Engineering Dept. 3442Industrial Instruments 2Chapter 7Final Control Dr. Bassam Kahhaleh
3442 - Industrial Instruments 2 7: Final Control Objective The function of the final control element is to translate low-energy control signals into a level of action commensurate with the process under control.
3442 - Industrial Instruments 2 7: Final Control Operation • Block Diagram Signal Conversions Actuator Control Signal Final Control Element Process
3442 - Industrial Instruments 2 7: Final Control Operation • Block Diagram Signal Conversions Actuator Control Signal The devices that perform such signal conversions are often called transducers because they convert control signals from one form to another, such as current to pressure, current to voltage … etc. Final Control Element Process
3442 - Industrial Instruments 2 7: Final Control Operation • Block Diagram Signal Conversions Actuator Control Signal Final Control Element Theactuator is a translation of the (converted) control signal into action on the control element. Process
3442 - Industrial Instruments 2 7: Final Control Operation • Block Diagram Signal Conversions Actuator Control Signal Final Control Element Thecontrol element is operated (run) by the actuator. Process
3442 - Industrial Instruments 2 7: Final Control Operation • Block Diagram Signal Conversions Actuator Control Signal Final Control Element Theprocess is operation (objective) under control. Process
3442 - Industrial Instruments 2 7: Final Control Operation Example: Baking of Crackers
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Relays • Mechanical • Solid-State • Amplifiers • Transistor • Op-amp
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Relays • Mechanical
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Relays • Mechanical
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Relays • Mechanical
V (Volts) 10 5 I (mA) 4 20 3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Op-amp Example: Convert a “4 – 20” mA control signal to a “5 – 10” V signal. Solution: Vin = Rin * Iin Vout = K Vin + VB
Vout (V) 10 5 Vin (V) 0.4 2 3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Op-amp Solution: Vin = Rin * Iin Let Rin = 100 Ω
Vout (V) 10 5 Vin (V) 0.4 2 3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Op-amp Solution: Vout = K Vin + VB 5 = K * 0.4 + VB 10 = K * 2 + VB K = 3.125 VB = 3.75 Vout = 3.125 Vin + 3.75 Vout = 3.125 (Vin + 1.2)
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Analog Electrical Signals • Op-amp Solution: Vout = 3.125 (Vin + 1.2)
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Digital Electrical Signals • Op-amp • DAC • Direct Action Example: A 4-bit digital word is intended to control the setting of a 2-Ω DC resistive heater. Heat output varies as a 0 – 24 V input to the heater. Using a 10–V DAC followed by an amplifier and a unity gain high-current amplifier, calculate: a) the settings from minimum to maximum heat dissipation, and b) how the power varies with LSB changes.
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Digital Electrical Signals • DAC Solution: DAC 10–V reference 24 = 16 Therefore: 1111 (15/16) * 10 = 9.375 V . . 0000 0 V Amplifier gain = 24 / 9.375 = 2.56 Incremental step = [(1/16) * 10 ] * 2.56 = 1.6 V ΔV = (1/16) * 10 V
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Digital Electrical Signals • DAC Power (W) Solution: ΔP (from 0000 to 0001) = (1.6 V)2 / 2 Ω = 1.28 W ΔP (from 1110 to 1111) = (24)2 – (22.4)2 / 2 = 37.12 W Control Ward
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Pneumatic Signals • Pressure signal travels down the pipe at a speed in the range of the speed of sound.
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Pneumatic Signals • Pressure signal travels down the pipe at a speed in the range of the speed of sound. • Amplifier (booster or relay)
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Pneumatic Signals • Pressure signal travels down the pipe at a speed in the range of the speed of sound. • Amplifier (booster or relay) • Nozzle/Flapper system
3442 - Industrial Instruments 2 7: Final Control Signal Conversions • Pneumatic Signals • Pressure signal travels down the pipe at a speed in the range of the speed of sound. • Amplifier (booster or relay) • Nozzle/Flapper system • Current-to-Pressure converters
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • Silicon-Controlled Rectifier (SCR) • Maximum forward current • Peak reverse voltage • Trigger voltage • Trigger current • Holding current
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • SCR Operation: Half-wave
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • SCR Operation: Full-wave
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • SCR Operation: Full-wave (with digital control)
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics SCR Example An SCR with a 4.0–V trigger is used as a light–dimmer control. What resistance, R, should be used to provide approximately 10% to 90% ON time?
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics SCR Example
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics SCR Example VC(t) = VO(1 – e-t/RC) 4.0 = 10 (1 – e-t/RC) t = 0.511 RC T half a cycle = 10 ms 10% 1 ms 90% 9 ms With C = 0.12 μF Rmin = 16.3 KΩ Rmax = 147 KΩ
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • TRIAC • DIAC
3442 - Industrial Instruments 2 7: Final Control Industrial Electronics • TRIAC
3442 - Industrial Instruments 2 7: Final Control TRIAC Example An DIAC with a 28–V breakdown voltage is used in the light–dimmer control. What resistance, R, should be used to provide approximately 10% to 90% ON time? Industrial Electronics
3442 - Industrial Instruments 2 7: Final Control TRIAC Example When does VAC reach 28 Volts so that it becomes possible to trigger the TRIAC? Industrial Electronics 28 = 310 sin(314 t) t = 0.288 ms ≈ 2.9% of the period And for 40 Volts: 40 = 310 sin(314 t) t = 0.412 ms ≈ 4.1% of the period
3442 - Industrial Instruments 2 7: Final Control TRIAC Example Industrial Electronics • 28 = 40 [ 1 – e – t / RC ] • t = 1.2 RC • If t = 1 ms: Rmin = 6.9 KΩ • If t = 9 ms: Rmax = 62.5 KΩ
3442 - Industrial Instruments 2 7: Final Control Actuators • Electrical Actuators • Solenoid
3442 - Industrial Instruments 2 7: Final Control Actuators • Electrical Actuators • Solenoid • DC Motor • AC Motor
3442 - Industrial Instruments 2 7: Final Control Actuators • Electrical Actuators • Solenoid • DC Motor • AC Motor • Stepping Motor
3442 - Industrial Instruments 2 7: Final Control Actuators • Electrical Actuators • Solenoid • DC Motor • AC Motor • Stepping Motor • Pneumatic Actuators
3442 - Industrial Instruments 2 7: Final Control Actuators • Electrical Actuators • Solenoid • DC Motor • AC Motor • Stepping Motor • Pneumatic Actuators • Hydraulic Actuators
3442 - Industrial Instruments 2 7: Final Control Control Elements • Mechanical • Solid-Material Hopper Valves
3442 - Industrial Instruments 2 7: Final Control Control Elements • Mechanical • Paper Thickness
3442 - Industrial Instruments 2 7: Final Control Control Elements • Electrical • Motor Speed Control
3442 - Industrial Instruments 2 7: Final Control Control Elements • Electrical • Temperature Control
3442 - Industrial Instruments 2 7: Final Control Control Elements • Fluid Valves
3442 - Industrial Instruments 2 7: Final Control End of Chapter 7