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By: Wen Cheng, Kelsey Boyce, Karina Kainth

The Memories. By: Wen Cheng, Kelsey Boyce, Karina Kainth. of Cherry.

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By: Wen Cheng, Kelsey Boyce, Karina Kainth

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  1. The Memories By: Wen Cheng, Kelsey Boyce, Karina Kainth of Cherry

  2. Cherry was in a car accident last night! She is now lying awake in the hospital with her loving parents by her side. Cherry has always been close to her parents, but still found them to be mysterious and elusive. Cherry now has no recollection of her past life or what happened on that fateful night. Can you help her get her memory back?

  3. Solve the following gas law problems to help Cherry unlock her most important memories and link her past to the present. Click on the “HINT” button for hints. Click on the “ANSWER” button for answers. (Make sure you remember the question number whenever you use hint. ) There was a significant reason behind the car accident and only you can solve the mystery!

  4. 1. A gas at 22ºC occupies a volume of 380mL. If the new volume is 600mL, what will the new temperature in Celsius be? HINT ANSWER

  5. ANSWER • V1 = 380mL; V2 = 600mL • T1 = 22˚C + 273 = 295K; T2 = X • V↑T↑ • 295 (600mL) = 465.79K (380mL) • 465.79K – 273 = 193˚C

  6. Congratulations! You just helped Cherry remember her bedroom as a child. She always used to sleep with the stuffed animals. Her favorite furry friend is her little tiger, Puff.

  7. 2. A gas occupies a volume of 30.0cm3 at 322.5K. If the temperature drops 47.5K, what will the new volume be? HINT ANSWER

  8. ANSWER • T1 = 322.5K; T2 = 322.5K - 47.5K = 275K • V1 = 30.0cm3; V2 = X • T↓V↓ • 30.0cm3(275K) = 25.6cm3 (322.5K)

  9. Cherry’s first day of kindergarten was nerve-racking but also exciting. She made many new friends that day.

  10. 3. A gas with a pressure of 92.0 kPa at 30ºC is raised to a new temperature of 89ºC. What is the new pressure? HINT ANSWER

  11. ANSWER • T1 = 30˚C + 273 = 303K; T2 = 89˚C + 273 = 362K • P1 = 92 kPa; P2 = X • T↑P↑ • 92.0 kPa (362K) = 110. kPa (303K)

  12. Cherry had a great time during her sixth birthday party. She celebrated it with her best friend Sarah along with several other friends and a big blue shark.

  13. 4. A gas with a pressure of 580 torr and at 96ºC is raised to a pressure of 830 torr. What is the new temperature in Celsius? HINT ANSWER

  14. ANSWER • P1 = 580 torr; P2 = 830 torr • T1 = 96˚C + 273 = 369K; T2 = X • P↑T↑ • 369K (830 torr) = 528.05K (580 torr) • 528K – 273 = 255˚C

  15. Christmas has always been Cherry’s favorite time of year. She relished the smell of pine when she and her family brought home a freshly-cut Christmas tree.

  16. 5. A gas with volume of 2.8L and pressure of 720. mmHg is raised to a volume of 4.3L. What is the new pressure? HINT ANSWER

  17. ANSWER • V1 = 2.8L; V2 = 4.3L • P1 = 720 mmHg; P2 = X • V↑P↓ • 720. mmHg (2.8L) = 469 mmHg (4.3L)

  18. You just helped Cherry recollect a pretty “painful” memory. One day during the summer of third grade, while climbing a tree to get a ball that got stuck on the branches, Cherry fell and broke her arm. It did not heal until a month later.

  19. 6. A gas with volume of 25.7dm3 and pressure of 1.4 atm is raised to a pressure of 3.3 atm. What is the new volume? HINT ANSWER

  20. ANSWER • P1 = 1.4 atm; P2 = 3.3 atm • V1 = 25.7 dm3; V2 = X • P↑V↓ • 25.7 dm3 (1.4 atm) = 10.9 dm3 (3.3 atm)

  21. When Cherry was eleven, her parents gifted her with an adorable puppy! Cherry named her Popcorn. She was her most loyal friend and even helped her to get through some tough times.

  22. 7. 2.5dm3 of a gas at 38ºC has a pressure of 5.60 kPa. What is the new pressure at 4.8dm3 and 103ºC? HINT ANSWER

  23. ANSWER • P1 = 5.60 kPa; P2 = X • V1 = 2.5 dm3; V2 = 4.8 dm3 • T1 = 38˚C + 273 = 311K; T2 = 103˚C + 273 = 376K • V↑P↓; T↑P↑ • 5.60 kPa (2.5 dm3) (376K) = 3.53 kPa (4.8 dm3) (311K)

  24. Cherry enjoyed playing soccer very much. She joined a soccer summer camp after she graduated from her elementary school and had a great time there.

  25. 8. At 15ºC and 590 torr, a gas has a volume of 21.7 L. What is the new volume of the gas at 89ºC and 630 torr? HINT ANSWER

  26. ANSWER • V1 = 21.7 L; V2 = X • T1 = 15˚C + 273 = 288K; T2 = 89˚C + 273 = 362K • P1 = 590 torr; P2 = 630 torr • T↑V↑; P↑V↓ • 21.7L (590 torr) (362K) = 25.5 L (630 torr) (288K)

  27. Middle school graduation was a defining moment in Cherry’s life. She has grown older and more mature. It was time to prepare for high school.

  28. 9. A gas with volume of 510 cm3 is collected over water at 789 mmHg and 25ºC. What will the new temperature be when the dry gas is in 683 cm3 and 650 mmHg? (Water vapor pressure at 25ºC is 3.2 kPa) HINT ANSWER

  29. ANSWER • T1 = 25˚C + 273 = 298K; T2 = X • V1 = 510 cm3; V2 = 683 cm3 • Water: 3.2 kPa (760 mmHg) = 24.0 mmHg (101.3 kPa) P1 = 789 - 24.0 = 765 mmHg; P2 = 650 mmHg • V↑T↑; P↓T↓ • 298K (683 cm3) (650 mmHg) = 339K (510 cm3) (765 mmHg)

  30. The first few weeks of high school were a mind-numbing blur of new rules, challenging classes, and formations of new cliques and friends.

  31. 10. What pressure in torr is exerted by a gas of 0.623 moles in a 16.3 L vessel at -15ºC? HINT ANSWER

  32. ANSWER • P•V = n•R•T • P = X; V = 16.3 L; n = 0.623 mol; R = 62.4 torr•L ; T = -15˚C + 273 = 258K mol•K • (X)(16.3 L) = (0.623 moles)(62.4 torr•L)(258K) mol•K • X = 615 torr

  33. Ever since high school started, Cherry had to wrestle with more challenging school work, but she has always worked very hard and received good grades. Her parents are very proud of her.

  34. 11. How many grams of oxygen would occupy a 280 mL vessel at 40ºC and 5.6 atm? HINT ANSWER

  35. ANSWER • P•V = n•R•T • P = 5.6 atm; V = 280 mL ( 1 L ) = 0.280 L (1000 mL) n = X; R = 0.0821 atm•L; T = 40˚C + 273 = 313K mol•K • (5.6 atm)(0.280 L) = (X)(0.0821 atm•L)(313K) mol•K • X = 0.0610 mol O2 (32g O2) = 0.438g O2 (1 mol O2)

  36. Cherry and her parents took many outdoor trips. Cherry had the most fun on a fishing trip she and her parents went on one summer. However, they had to cut their family trip short because of her parents’ work-related emergency.

  37. 12. A gas is collected over water at 21.0ºC at a pressure of 740 mmHg. The gas a mass of 4.192 grams and the volume is 125 mL. What is the molar mass of the gas? (water vapor pressure at 21.0ºC is 2.5 kPa) HINT ANSWER

  38. ANSWER • m = 4.192g; R = 62.4 mmHg•L; moles•K T = 21.0˚C + 273 = 294K Water: 2.5 kPa (760 mmHg) = 19 mmHg; (101.3 kPa) P = 740 – 19 = 721 mmHg; V = 125 mL ( 1 L ) = 0.125 L (1000 mL) • M = mRT = (4.192g)(62.4 mmHg•L/ moles•K)(294K) PV (721 mmHg)(0.125 L) • = 853 g/mol

  39. Cherry won the State Soccer Finals in her sophomore year of high school. Sarah and all of Cherry’s other friends witnessed her in glory. Too bad her parents had not been able to make it because of their work.

  40. 13. A gas that occupies a volume of 0.91 L at 1.2 atm and 22.5ºC has a mass of 2.10g. The gas is collected over water and the water vapor pressure is 20.0 mmHg. Calculate the molar mass of the gas. HINT ANSWER

  41. ANSWER • m = 2.10g; R = 0.0821 atm•L; mol•K T = 22.5˚C + 273 = 295.5K; P = 1.2 atm; V = 0.91 L • M = mRT PV = (2.10g)(0.0821 atm•L/ moles•K)(295.5K) (1.2 atm)(0.91 L) = 46.7 g/mol

  42. Cherry met her current boyfriend, Henry, in a coed soccer summer camp during the summer of her sophomore year. During these two years, they have always been there to help each other through hard times. They are still together.

  43. 14. Find the relative rates of diffusion for the gases nitrogen and chlorine. Which diffuses faster? ANSWER HINT

  44. ANSWER • VN2 = (mCl2 )^1/2 VCl2 (mN2 )^1/2 • X = (70.90g)^1/2 1 (28.02g )^1/2 • X = 1.59 (nitrogen diffuses faster)

  45. Finally, you have helped Cherry recall her most recent memories. The day before the car accident, Cherry remembered that her parents were working late, and never came home that night nor the next day.

  46. 15. Neon diffuses 1.26 times faster than gas A. What is the molar mass for gas A? What is gas A? HINT ANSWER

  47. ANSWER • VNe = (mA )^1/2 VA (mNe )^1/2 • 1.26 = (mA)^1/2 1 (20.18g)^1/2 • X = 32.09g (Sulfur)

  48. On the day of the crash, Cherry had a party with her fellow classmates to celebrate the end of their lives in high school. They all had a great time.

  49. 16. Use the ideal gas law and stoichiometry to calculate the mass of a piece of magnesium using the data below. HINT ANSWER

  50. ANSWER • P•V = n•R•T • P = 30.01 inHg (2.54 cm) (10 mm) (101.3 kPa) = 101.6 - 2.6 = 99 kPa; ( 1 in ) ( 1 cm ) (760 mmHg) • V = 62.4 mL ( 1 L ) = 0.0624 L (1000 ml) • n = X; • R = 8.31 kPa•L ; mol•K • T = 22.5˚C + 273 = 295.5K • (99 kPa)(0.0624 mL) = (X)(8.31 kPa•L)(295.5K) mol•K • X = 0.0025 mol Mg (24.31g Mg) = 0.061 Mg (1 mole Mg)

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